Probability density function of random variable $X$ [on hold]












-1














If the probability density function of the random variable $X$ is given by:



$f_X(x)=(1-x)^2$ for $0<x<1$



Then find the mean variance and standard deviation.










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New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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put on hold as off-topic by Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom 16 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
    – Matti P.
    16 hours ago










  • There is no such density function since $f$ does not integrate to $1$.
    – Kavi Rama Murthy
    16 hours ago










  • Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
    – drhab
    16 hours ago










  • I need formulas
    – Meganath Chidara
    9 hours ago










  • @MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
    – drhab
    9 hours ago
















-1














If the probability density function of the random variable $X$ is given by:



$f_X(x)=(1-x)^2$ for $0<x<1$



Then find the mean variance and standard deviation.










share|cite|improve this question









New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











put on hold as off-topic by Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom 16 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
    – Matti P.
    16 hours ago










  • There is no such density function since $f$ does not integrate to $1$.
    – Kavi Rama Murthy
    16 hours ago










  • Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
    – drhab
    16 hours ago










  • I need formulas
    – Meganath Chidara
    9 hours ago










  • @MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
    – drhab
    9 hours ago














-1












-1








-1







If the probability density function of the random variable $X$ is given by:



$f_X(x)=(1-x)^2$ for $0<x<1$



Then find the mean variance and standard deviation.










share|cite|improve this question









New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











If the probability density function of the random variable $X$ is given by:



$f_X(x)=(1-x)^2$ for $0<x<1$



Then find the mean variance and standard deviation.







probability






share|cite|improve this question









New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 16 hours ago









drhab

98k544129




98k544129






New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 16 hours ago









Meganath Chidara

1




1




New contributor




Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Meganath Chidara is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




put on hold as off-topic by Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom 16 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom 16 hours ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, drhab, José Carlos Santos, Kavi Rama Murthy, StubbornAtom

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
    – Matti P.
    16 hours ago










  • There is no such density function since $f$ does not integrate to $1$.
    – Kavi Rama Murthy
    16 hours ago










  • Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
    – drhab
    16 hours ago










  • I need formulas
    – Meganath Chidara
    9 hours ago










  • @MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
    – drhab
    9 hours ago














  • 1




    Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
    – Matti P.
    16 hours ago










  • There is no such density function since $f$ does not integrate to $1$.
    – Kavi Rama Murthy
    16 hours ago










  • Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
    – drhab
    16 hours ago










  • I need formulas
    – Meganath Chidara
    9 hours ago










  • @MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
    – drhab
    9 hours ago








1




1




Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
– Matti P.
16 hours ago




Please use MathJax to type out the equation. Next, write the whole question, and your own thoughts. What have you tried? Where did you face difficulty? This way, people are more likely to help you.
– Matti P.
16 hours ago












There is no such density function since $f$ does not integrate to $1$.
– Kavi Rama Murthy
16 hours ago




There is no such density function since $f$ does not integrate to $1$.
– Kavi Rama Murthy
16 hours ago












Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
– drhab
16 hours ago




Check my edit. Defined like this and under the assumption that $f_X(x)=0$ if $xnotin(0,1)$ this function is not a PDF because integration does not result in $1$.
– drhab
16 hours ago












I need formulas
– Meganath Chidara
9 hours ago




I need formulas
– Meganath Chidara
9 hours ago












@MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
– drhab
9 hours ago




@MeganathChidara If $f_X$ is indeed a PDF (and the function in your question is not) then $mathbb Eg(X)=int g(x)f_X(x)dx$. You can apply that on functions $g$ prescribed by $xmapsto x$ and $xmapsto x^2$ in order to find $mathbb EX$ and $mathbb EX^2$. Then you can find $mathsf{Var}(X)$ as $mathbb EX^2-(mathbb EX)^2$ and standard deviation as $sqrt{text{Var}(X)}$
– drhab
9 hours ago










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