The Grothendieck Group. [on hold]
Given a set A, how would you go about constructing the Grothendieck group K of M, the free commutative monoid on A?
Many thanks for any help.
abstract-algebra monoid
put on hold as off-topic by jgon, Dietrich Burde, KReiser, Cesareo, amWhy Jan 5 at 1:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – jgon, Dietrich Burde, KReiser, Cesareo, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
Given a set A, how would you go about constructing the Grothendieck group K of M, the free commutative monoid on A?
Many thanks for any help.
abstract-algebra monoid
put on hold as off-topic by jgon, Dietrich Burde, KReiser, Cesareo, amWhy Jan 5 at 1:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – jgon, Dietrich Burde, KReiser, Cesareo, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
2
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
1
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15
add a comment |
Given a set A, how would you go about constructing the Grothendieck group K of M, the free commutative monoid on A?
Many thanks for any help.
abstract-algebra monoid
Given a set A, how would you go about constructing the Grothendieck group K of M, the free commutative monoid on A?
Many thanks for any help.
abstract-algebra monoid
abstract-algebra monoid
asked Jan 4 at 16:27
AktAkt
367
367
put on hold as off-topic by jgon, Dietrich Burde, KReiser, Cesareo, amWhy Jan 5 at 1:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – jgon, Dietrich Burde, KReiser, Cesareo, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by jgon, Dietrich Burde, KReiser, Cesareo, amWhy Jan 5 at 1:57
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – jgon, Dietrich Burde, KReiser, Cesareo, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
2
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
1
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15
add a comment |
2
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
1
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15
2
2
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
1
1
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15
add a comment |
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2
Isn't it just the same as free abelian group on $A$?
– Wojowu
Jan 4 at 16:30
1
A simple google search will show to construct both the Grothendieck group K of M, and the free commutative monoid on A.
– user458276
Jan 4 at 17:53
I would "go about" reading the wikipedia article, which has further references.
– Dietrich Burde
Jan 4 at 19:15