Analyzing $sum^infty _{n=1}{frac{1}{p^n - q^n}}, 0lt qlt p$ [on hold]
I am told to analyze the convergence of $sum^infty _{n=1}{frac{1}{p^n - q^n}}, 0lt qlt p$ depending on the values of $p$ and $q$. The only thing I have concluded is that ovbiously, the series is a positive term series. I do not know which criteria to use in this case. Thanks in advance.
real-analysis calculus sequences-and-series
put on hold as off-topic by Did, Strants, rtybase, amWhy, José Carlos Santos 2 days ago
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I am told to analyze the convergence of $sum^infty _{n=1}{frac{1}{p^n - q^n}}, 0lt qlt p$ depending on the values of $p$ and $q$. The only thing I have concluded is that ovbiously, the series is a positive term series. I do not know which criteria to use in this case. Thanks in advance.
real-analysis calculus sequences-and-series
put on hold as off-topic by Did, Strants, rtybase, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Strants, rtybase, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago
add a comment |
I am told to analyze the convergence of $sum^infty _{n=1}{frac{1}{p^n - q^n}}, 0lt qlt p$ depending on the values of $p$ and $q$. The only thing I have concluded is that ovbiously, the series is a positive term series. I do not know which criteria to use in this case. Thanks in advance.
real-analysis calculus sequences-and-series
I am told to analyze the convergence of $sum^infty _{n=1}{frac{1}{p^n - q^n}}, 0lt qlt p$ depending on the values of $p$ and $q$. The only thing I have concluded is that ovbiously, the series is a positive term series. I do not know which criteria to use in this case. Thanks in advance.
real-analysis calculus sequences-and-series
real-analysis calculus sequences-and-series
edited 2 days ago
Foobaz John
21.4k41351
21.4k41351
asked 2 days ago
Andarrkor
446
446
put on hold as off-topic by Did, Strants, rtybase, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Strants, rtybase, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Did, Strants, rtybase, amWhy, José Carlos Santos 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Did, Strants, rtybase, amWhy, José Carlos Santos
If this question can be reworded to fit the rules in the help center, please edit the question.
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago
add a comment |
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago
add a comment |
2 Answers
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Observe that
$$sum_{n=1}^inftyfrac{1}{p^n-q^n}=frac{1}{p-q}sum_{n=1}^inftyfrac{1}{p^{n-1}+p^{n-2}q+cdots+pq^{n-2}+q^{n-1}}$$
We can apply the comparison test to $dfrac{1}{p^{n-1}}$ and $dfrac{1}{q^{n-1}}$ to see that the series converges whenever $p>1$ or $q>1$.
If both $pleq 1$ and $qleq 1$, then it is not the case that $dfrac 1{(p^n-q^n)}to 0$, hence the series diverges.
add a comment |
Write the general term $a_n$ of the series as
$$
0lefrac{m}{p^n}leq a_n=frac{1}{p^n(1-(q/p)^n)}leq frac{M}{p^n}
$$
since $frac{1}{1-(q/p)^n}to 1$ for some $m, M>0$. The above inequality should allow you to deduce convergence depending on whether $p>1$ or $p<1$.
For the case with $p=1$, the general term of the series is
$$
a_n=frac{1}{1-q^n}
$$
What can we say about $lim_{nto infty} a_n$ if $q<1$.
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Observe that
$$sum_{n=1}^inftyfrac{1}{p^n-q^n}=frac{1}{p-q}sum_{n=1}^inftyfrac{1}{p^{n-1}+p^{n-2}q+cdots+pq^{n-2}+q^{n-1}}$$
We can apply the comparison test to $dfrac{1}{p^{n-1}}$ and $dfrac{1}{q^{n-1}}$ to see that the series converges whenever $p>1$ or $q>1$.
If both $pleq 1$ and $qleq 1$, then it is not the case that $dfrac 1{(p^n-q^n)}to 0$, hence the series diverges.
add a comment |
Observe that
$$sum_{n=1}^inftyfrac{1}{p^n-q^n}=frac{1}{p-q}sum_{n=1}^inftyfrac{1}{p^{n-1}+p^{n-2}q+cdots+pq^{n-2}+q^{n-1}}$$
We can apply the comparison test to $dfrac{1}{p^{n-1}}$ and $dfrac{1}{q^{n-1}}$ to see that the series converges whenever $p>1$ or $q>1$.
If both $pleq 1$ and $qleq 1$, then it is not the case that $dfrac 1{(p^n-q^n)}to 0$, hence the series diverges.
add a comment |
Observe that
$$sum_{n=1}^inftyfrac{1}{p^n-q^n}=frac{1}{p-q}sum_{n=1}^inftyfrac{1}{p^{n-1}+p^{n-2}q+cdots+pq^{n-2}+q^{n-1}}$$
We can apply the comparison test to $dfrac{1}{p^{n-1}}$ and $dfrac{1}{q^{n-1}}$ to see that the series converges whenever $p>1$ or $q>1$.
If both $pleq 1$ and $qleq 1$, then it is not the case that $dfrac 1{(p^n-q^n)}to 0$, hence the series diverges.
Observe that
$$sum_{n=1}^inftyfrac{1}{p^n-q^n}=frac{1}{p-q}sum_{n=1}^inftyfrac{1}{p^{n-1}+p^{n-2}q+cdots+pq^{n-2}+q^{n-1}}$$
We can apply the comparison test to $dfrac{1}{p^{n-1}}$ and $dfrac{1}{q^{n-1}}$ to see that the series converges whenever $p>1$ or $q>1$.
If both $pleq 1$ and $qleq 1$, then it is not the case that $dfrac 1{(p^n-q^n)}to 0$, hence the series diverges.
edited 2 days ago
amWhy
192k28224439
192k28224439
answered 2 days ago
Ben W
1,825514
1,825514
add a comment |
add a comment |
Write the general term $a_n$ of the series as
$$
0lefrac{m}{p^n}leq a_n=frac{1}{p^n(1-(q/p)^n)}leq frac{M}{p^n}
$$
since $frac{1}{1-(q/p)^n}to 1$ for some $m, M>0$. The above inequality should allow you to deduce convergence depending on whether $p>1$ or $p<1$.
For the case with $p=1$, the general term of the series is
$$
a_n=frac{1}{1-q^n}
$$
What can we say about $lim_{nto infty} a_n$ if $q<1$.
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
add a comment |
Write the general term $a_n$ of the series as
$$
0lefrac{m}{p^n}leq a_n=frac{1}{p^n(1-(q/p)^n)}leq frac{M}{p^n}
$$
since $frac{1}{1-(q/p)^n}to 1$ for some $m, M>0$. The above inequality should allow you to deduce convergence depending on whether $p>1$ or $p<1$.
For the case with $p=1$, the general term of the series is
$$
a_n=frac{1}{1-q^n}
$$
What can we say about $lim_{nto infty} a_n$ if $q<1$.
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
add a comment |
Write the general term $a_n$ of the series as
$$
0lefrac{m}{p^n}leq a_n=frac{1}{p^n(1-(q/p)^n)}leq frac{M}{p^n}
$$
since $frac{1}{1-(q/p)^n}to 1$ for some $m, M>0$. The above inequality should allow you to deduce convergence depending on whether $p>1$ or $p<1$.
For the case with $p=1$, the general term of the series is
$$
a_n=frac{1}{1-q^n}
$$
What can we say about $lim_{nto infty} a_n$ if $q<1$.
Write the general term $a_n$ of the series as
$$
0lefrac{m}{p^n}leq a_n=frac{1}{p^n(1-(q/p)^n)}leq frac{M}{p^n}
$$
since $frac{1}{1-(q/p)^n}to 1$ for some $m, M>0$. The above inequality should allow you to deduce convergence depending on whether $p>1$ or $p<1$.
For the case with $p=1$, the general term of the series is
$$
a_n=frac{1}{1-q^n}
$$
What can we say about $lim_{nto infty} a_n$ if $q<1$.
answered 2 days ago
Foobaz John
21.4k41351
21.4k41351
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
add a comment |
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
How did you delimit the series? Thanks for answering.
– Andarrkor
2 days ago
add a comment |
Faced with such a problem, I would experiment. Try different values of p, q, and n (e.g. p=3 or 5, q = 2, n =5. Look for patterns in the behavior of the sums of the fractions. Form hypotheses around the observed behavior. Prove the hypotheses. Form hypotheses around convergence. Try to prove these hypostheses. Then, if you still can't complete the problem, edit your post to show all of your work.
– user2661923
2 days ago