Maths probleme vector help fast [on hold]
I need your help
be ABC a triangle non flat,we define the isobarycentre of the triangle ABC the point G such that :
vector(AG)+vector(BG)+vector(CG)=0
the point G is the centre of gravity of the triangle ABC
QUESTIONS :
1.the respective points I,J and k are placed in the segments (AB),(BC) and (AC).express the vector AJ according to the vector(AB) and the vector(AC).
2 .using the expression: vector(AG)+vector(BG)+vector(CG)=0, express the vector(AG) accrording to the vector(AB) and the vector(AC).
3.show that we can write vector(AG)=Kvector(AJ) "AG=KAJ) " , for a certain k to be determined .
4.deduce the the points A,G and J are aligned .
5.in the same way it can be shown it can be shown that the ponints B,G and k are aligned , as are the points C,G and I , show that G is the the point of intersection of the lines (AJ),(BK) and (CI)
6.what is the position of the point G (the centre of gravity of the triangle ABC)
indication : if AB is a segment , the middle I of (AB) is the poin of intersection between the segment (AB) and its median.
vectors
New contributor
put on hold as off-topic by stressed out, Ethan Bolker, amWhy, José Carlos Santos, Don Thousand 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – stressed out, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
I need your help
be ABC a triangle non flat,we define the isobarycentre of the triangle ABC the point G such that :
vector(AG)+vector(BG)+vector(CG)=0
the point G is the centre of gravity of the triangle ABC
QUESTIONS :
1.the respective points I,J and k are placed in the segments (AB),(BC) and (AC).express the vector AJ according to the vector(AB) and the vector(AC).
2 .using the expression: vector(AG)+vector(BG)+vector(CG)=0, express the vector(AG) accrording to the vector(AB) and the vector(AC).
3.show that we can write vector(AG)=Kvector(AJ) "AG=KAJ) " , for a certain k to be determined .
4.deduce the the points A,G and J are aligned .
5.in the same way it can be shown it can be shown that the ponints B,G and k are aligned , as are the points C,G and I , show that G is the the point of intersection of the lines (AJ),(BK) and (CI)
6.what is the position of the point G (the centre of gravity of the triangle ABC)
indication : if AB is a segment , the middle I of (AB) is the poin of intersection between the segment (AB) and its median.
vectors
New contributor
put on hold as off-topic by stressed out, Ethan Bolker, amWhy, José Carlos Santos, Don Thousand 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – stressed out, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
4
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
1
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago
add a comment |
I need your help
be ABC a triangle non flat,we define the isobarycentre of the triangle ABC the point G such that :
vector(AG)+vector(BG)+vector(CG)=0
the point G is the centre of gravity of the triangle ABC
QUESTIONS :
1.the respective points I,J and k are placed in the segments (AB),(BC) and (AC).express the vector AJ according to the vector(AB) and the vector(AC).
2 .using the expression: vector(AG)+vector(BG)+vector(CG)=0, express the vector(AG) accrording to the vector(AB) and the vector(AC).
3.show that we can write vector(AG)=Kvector(AJ) "AG=KAJ) " , for a certain k to be determined .
4.deduce the the points A,G and J are aligned .
5.in the same way it can be shown it can be shown that the ponints B,G and k are aligned , as are the points C,G and I , show that G is the the point of intersection of the lines (AJ),(BK) and (CI)
6.what is the position of the point G (the centre of gravity of the triangle ABC)
indication : if AB is a segment , the middle I of (AB) is the poin of intersection between the segment (AB) and its median.
vectors
New contributor
I need your help
be ABC a triangle non flat,we define the isobarycentre of the triangle ABC the point G such that :
vector(AG)+vector(BG)+vector(CG)=0
the point G is the centre of gravity of the triangle ABC
QUESTIONS :
1.the respective points I,J and k are placed in the segments (AB),(BC) and (AC).express the vector AJ according to the vector(AB) and the vector(AC).
2 .using the expression: vector(AG)+vector(BG)+vector(CG)=0, express the vector(AG) accrording to the vector(AB) and the vector(AC).
3.show that we can write vector(AG)=Kvector(AJ) "AG=KAJ) " , for a certain k to be determined .
4.deduce the the points A,G and J are aligned .
5.in the same way it can be shown it can be shown that the ponints B,G and k are aligned , as are the points C,G and I , show that G is the the point of intersection of the lines (AJ),(BK) and (CI)
6.what is the position of the point G (the centre of gravity of the triangle ABC)
indication : if AB is a segment , the middle I of (AB) is the poin of intersection between the segment (AB) and its median.
vectors
vectors
New contributor
New contributor
New contributor
asked 2 days ago
Assalfreef
6
6
New contributor
New contributor
put on hold as off-topic by stressed out, Ethan Bolker, amWhy, José Carlos Santos, Don Thousand 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – stressed out, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by stressed out, Ethan Bolker, amWhy, José Carlos Santos, Don Thousand 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – stressed out, amWhy
If this question can be reworded to fit the rules in the help center, please edit the question.
4
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
1
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago
add a comment |
4
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
1
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago
4
4
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
1
1
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago
add a comment |
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4
Welcome to stackexchange. That said I'm voting to close this question because you show no work of your own. If you edit the question to tell us what you tried and where you are stuck we may be able to help. For the future, asking for "help fast" is likely to produce exactly the opposite response.
– Ethan Bolker
2 days ago
1
Saying you need help fast probably won't help you get help fast - users here like to help people understand the maths they are learning rather than just help them get a homework assignment done on time. If you include where you are stuck on this question, people will be more willing to help as it shows you have put some effort in.
– John Doe
2 days ago
I'm very sorry .I'm new here I didn't read the rules.
– Assalfreef
2 days ago