Derivatives and continuous expansion of $sin x^{|cos x|}$ [on hold]
At all points of the domain determine the existence or calculate the (one-sided) derivatives of the function $(sin x)^{|cos x|}$. Can this function be continuously extended?
Honestly I am quite stumped by this problem. Any help would be appreciated.
real-analysis calculus derivatives
put on hold as off-topic by metamorphy, stressed out, RRL, onurcanbektas, Abcd 2 days ago
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add a comment |
At all points of the domain determine the existence or calculate the (one-sided) derivatives of the function $(sin x)^{|cos x|}$. Can this function be continuously extended?
Honestly I am quite stumped by this problem. Any help would be appreciated.
real-analysis calculus derivatives
put on hold as off-topic by metamorphy, stressed out, RRL, onurcanbektas, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – metamorphy, stressed out, onurcanbektas, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
1
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41
add a comment |
At all points of the domain determine the existence or calculate the (one-sided) derivatives of the function $(sin x)^{|cos x|}$. Can this function be continuously extended?
Honestly I am quite stumped by this problem. Any help would be appreciated.
real-analysis calculus derivatives
At all points of the domain determine the existence or calculate the (one-sided) derivatives of the function $(sin x)^{|cos x|}$. Can this function be continuously extended?
Honestly I am quite stumped by this problem. Any help would be appreciated.
real-analysis calculus derivatives
real-analysis calculus derivatives
edited Jan 3 at 22:45
asked Jan 3 at 22:24
J. Lastin
1005
1005
put on hold as off-topic by metamorphy, stressed out, RRL, onurcanbektas, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – metamorphy, stressed out, onurcanbektas, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by metamorphy, stressed out, RRL, onurcanbektas, Abcd 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – metamorphy, stressed out, onurcanbektas, Abcd
If this question can be reworded to fit the rules in the help center, please edit the question.
1
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41
add a comment |
1
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41
1
1
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41
add a comment |
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1
There is problem with definition of the power when $sin, x <0$. Perhaps you have to consider the domain as ${x: sin, x>0}$.
– Kavi Rama Murthy
Jan 3 at 23:41