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2 Let $wneq 1$ and $w^{13} = 1$ . If $a = w+ w^3 + w^4 + w^{-4} + w^{-3} + w^{-1}$ and $b = w^2+ w^5 + w^6 + w^{-6} + w^{-5} + w^{-2}$ , then the quadratic equation whose roots are $a$ and $b$ is ... ? I got $w=cos(frac{2pi}{13})+isin(frac{2pi}{13})$ And then I found $a$ and $b$ in trigonometric form. But when I multiplied them to get the product of roots it gets very difficult. How to solve it? complex-numbers share | cite | improve this question edited 2 days ago Andrei 11.3k 2 10 26 asked 2 days ago