Game combinations of tic-tac-toe [on hold]












3














How many combinations are possible in the game tic-tac-toe (Noughts and crosses)?



So for example a game which looked like: (with positions 1-9)



A1   --   B1

A2 -- B2

A3 -- --


[1][3][4][6][7] would be one combination










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put on hold as off-topic by user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer Jan 7 at 2:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 4




    se16.info/hgb/tictactoe.htm
    – Daryl
    Jan 2 '13 at 10:00










  • @Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
    – Mark S.
    Nov 22 '13 at 3:42










  • @MarkS. Sure thing.
    – Daryl
    Nov 22 '13 at 5:14
















3














How many combinations are possible in the game tic-tac-toe (Noughts and crosses)?



So for example a game which looked like: (with positions 1-9)



A1   --   B1

A2 -- B2

A3 -- --


[1][3][4][6][7] would be one combination










share|cite|improve this question















put on hold as off-topic by user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer Jan 7 at 2:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 4




    se16.info/hgb/tictactoe.htm
    – Daryl
    Jan 2 '13 at 10:00










  • @Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
    – Mark S.
    Nov 22 '13 at 3:42










  • @MarkS. Sure thing.
    – Daryl
    Nov 22 '13 at 5:14














3












3








3


4





How many combinations are possible in the game tic-tac-toe (Noughts and crosses)?



So for example a game which looked like: (with positions 1-9)



A1   --   B1

A2 -- B2

A3 -- --


[1][3][4][6][7] would be one combination










share|cite|improve this question















How many combinations are possible in the game tic-tac-toe (Noughts and crosses)?



So for example a game which looked like: (with positions 1-9)



A1   --   B1

A2 -- B2

A3 -- --


[1][3][4][6][7] would be one combination







combinatorics combinatorial-game-theory tic-tac-toe






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jul 26 '16 at 22:03









Rodrigo de Azevedo

12.8k41855




12.8k41855










asked Jan 2 '13 at 9:50









DanieldDanield

118115




118115




put on hold as off-topic by user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer Jan 7 at 2:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer Jan 7 at 2:19


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user21820, A. Pongrácz, Gibbs, mrtaurho, Eevee Trainer

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 4




    se16.info/hgb/tictactoe.htm
    – Daryl
    Jan 2 '13 at 10:00










  • @Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
    – Mark S.
    Nov 22 '13 at 3:42










  • @MarkS. Sure thing.
    – Daryl
    Nov 22 '13 at 5:14














  • 4




    se16.info/hgb/tictactoe.htm
    – Daryl
    Jan 2 '13 at 10:00










  • @Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
    – Mark S.
    Nov 22 '13 at 3:42










  • @MarkS. Sure thing.
    – Daryl
    Nov 22 '13 at 5:14








4




4




se16.info/hgb/tictactoe.htm
– Daryl
Jan 2 '13 at 10:00




se16.info/hgb/tictactoe.htm
– Daryl
Jan 2 '13 at 10:00












@Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
– Mark S.
Nov 22 '13 at 3:42




@Daryl, if you feel up to it, you should repackage that as an answer citing that website so this question can have an answer.
– Mark S.
Nov 22 '13 at 3:42












@MarkS. Sure thing.
– Daryl
Nov 22 '13 at 5:14




@MarkS. Sure thing.
– Daryl
Nov 22 '13 at 5:14










2 Answers
2






active

oldest

votes


















6














This information is taken from this website.



A naive estimate would be $9!=362,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.




  • Ending on the $5^text{th}$ move: $1,440$ possibilities

  • Ending on the $6^text{th}$ move: $5,328$ possibilities

  • Ending on the $7^text{th}$ move: $47,952$ possibilities

  • Ending on the $8^text{th}$ move: $72,576$ possibilities

  • Ending on the $9^text{th}$ move: $127,872$ possibilities


This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.






share|cite|improve this answer





















  • Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
    – Pieter Geerkens
    Nov 22 '13 at 5:32










  • As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
    – Henry
    Jan 2 '15 at 11:18










  • I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
    – kyriakosSt
    Dec 3 '17 at 23:47



















0














I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.



I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217



Cheers!






share|cite|improve this answer








New contributor




user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6














    This information is taken from this website.



    A naive estimate would be $9!=362,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.




    • Ending on the $5^text{th}$ move: $1,440$ possibilities

    • Ending on the $6^text{th}$ move: $5,328$ possibilities

    • Ending on the $7^text{th}$ move: $47,952$ possibilities

    • Ending on the $8^text{th}$ move: $72,576$ possibilities

    • Ending on the $9^text{th}$ move: $127,872$ possibilities


    This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.






    share|cite|improve this answer





















    • Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
      – Pieter Geerkens
      Nov 22 '13 at 5:32










    • As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
      – Henry
      Jan 2 '15 at 11:18










    • I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
      – kyriakosSt
      Dec 3 '17 at 23:47
















    6














    This information is taken from this website.



    A naive estimate would be $9!=362,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.




    • Ending on the $5^text{th}$ move: $1,440$ possibilities

    • Ending on the $6^text{th}$ move: $5,328$ possibilities

    • Ending on the $7^text{th}$ move: $47,952$ possibilities

    • Ending on the $8^text{th}$ move: $72,576$ possibilities

    • Ending on the $9^text{th}$ move: $127,872$ possibilities


    This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.






    share|cite|improve this answer





















    • Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
      – Pieter Geerkens
      Nov 22 '13 at 5:32










    • As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
      – Henry
      Jan 2 '15 at 11:18










    • I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
      – kyriakosSt
      Dec 3 '17 at 23:47














    6












    6








    6






    This information is taken from this website.



    A naive estimate would be $9!=362,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.




    • Ending on the $5^text{th}$ move: $1,440$ possibilities

    • Ending on the $6^text{th}$ move: $5,328$ possibilities

    • Ending on the $7^text{th}$ move: $47,952$ possibilities

    • Ending on the $8^text{th}$ move: $72,576$ possibilities

    • Ending on the $9^text{th}$ move: $127,872$ possibilities


    This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.






    share|cite|improve this answer












    This information is taken from this website.



    A naive estimate would be $9!=362,880$, since there are $9$ possible first moves, $8$ for the second move, etc. This does not take into account games which finish in less than $9$ moves.




    • Ending on the $5^text{th}$ move: $1,440$ possibilities

    • Ending on the $6^text{th}$ move: $5,328$ possibilities

    • Ending on the $7^text{th}$ move: $47,952$ possibilities

    • Ending on the $8^text{th}$ move: $72,576$ possibilities

    • Ending on the $9^text{th}$ move: $127,872$ possibilities


    This gives a total of $255168$ possible games. This calculation doesn't take into account symmetry in the game.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered Nov 22 '13 at 5:21









    DarylDaryl

    4,74231835




    4,74231835












    • Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
      – Pieter Geerkens
      Nov 22 '13 at 5:32










    • As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
      – Henry
      Jan 2 '15 at 11:18










    • I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
      – kyriakosSt
      Dec 3 '17 at 23:47


















    • Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
      – Pieter Geerkens
      Nov 22 '13 at 5:32










    • As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
      – Henry
      Jan 2 '15 at 11:18










    • I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
      – kyriakosSt
      Dec 3 '17 at 23:47
















    Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
    – Pieter Geerkens
    Nov 22 '13 at 5:32




    Accounting for symmetry, this can quickly be reduced by a factor of 6, as there are only 12 possible two move openings, not 8*9=72.
    – Pieter Geerkens
    Nov 22 '13 at 5:32












    As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
    – Henry
    Jan 2 '15 at 11:18




    As that linked page makes clear at the bottom, symmetry allows a reduction by a factor of $8$ (i.e. rotations and reflections of a square) to $31896$, but arguably by a greater amount to $26830$.
    – Henry
    Jan 2 '15 at 11:18












    I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
    – kyriakosSt
    Dec 3 '17 at 23:47




    I am assuming I am asking a naive question here, but why isn't the answer $9! - sumlimits_{i=5}^{8} m_i = 235584$, where, $m_i$ are the number of games ending on $i$ moves (the numbers above). (From the overestimation of the games that take all 9 moves we subtract the ones that require less)
    – kyriakosSt
    Dec 3 '17 at 23:47











    0














    I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.



    I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217



    Cheers!






    share|cite|improve this answer








    New contributor




    user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0














      I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.



      I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217



      Cheers!






      share|cite|improve this answer








      New contributor




      user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





















        0












        0








        0






        I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.



        I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217



        Cheers!






        share|cite|improve this answer








        New contributor




        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        I will say that the board combinations are 3^9, which is 19683 possibilities, and 2032 winning positions. The answer of 9! is related to how many ways we have to fell all the positions, rather than the possible combinations.



        I have answered this question already in another post, please see the next link: https://stackoverflow.com/a/54035004/5117217



        Cheers!







        share|cite|improve this answer








        New contributor




        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|cite|improve this answer



        share|cite|improve this answer






        New contributor




        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered Jan 4 at 20:07









        user5117217user5117217

        1




        1




        New contributor




        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        user5117217 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.















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