Ring Theory: Is the ring $S$ a prime ring? Ref. Page no. 8 (Section 2) Neal H. McCoy “The Theory of...
Let $R$ be a non commutative prime ring without unity and let $S$ be the set of all ordered pair $(a,i)$, where $ain R$ and $iin I$, where $I$ is the ring of integers. On $S$ we define addition and multiplication as follows:
$(a,i)+(b,j)=(a+b,i+j)$,
$(a,i)(b,j)=(ab+ib+ja, ij)$.
Then $S$ is a ring with unity $(0,1)$.
My question-
Is the ring $S$ a prime ring?
In case $R$ is a commutative prime ring with unity, I have shown $S$ is not a prime ring.
But I am stuck in the case $R$ is non commutative prime ring without unity.
ring-theory
add a comment |
Let $R$ be a non commutative prime ring without unity and let $S$ be the set of all ordered pair $(a,i)$, where $ain R$ and $iin I$, where $I$ is the ring of integers. On $S$ we define addition and multiplication as follows:
$(a,i)+(b,j)=(a+b,i+j)$,
$(a,i)(b,j)=(ab+ib+ja, ij)$.
Then $S$ is a ring with unity $(0,1)$.
My question-
Is the ring $S$ a prime ring?
In case $R$ is a commutative prime ring with unity, I have shown $S$ is not a prime ring.
But I am stuck in the case $R$ is non commutative prime ring without unity.
ring-theory
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago
add a comment |
Let $R$ be a non commutative prime ring without unity and let $S$ be the set of all ordered pair $(a,i)$, where $ain R$ and $iin I$, where $I$ is the ring of integers. On $S$ we define addition and multiplication as follows:
$(a,i)+(b,j)=(a+b,i+j)$,
$(a,i)(b,j)=(ab+ib+ja, ij)$.
Then $S$ is a ring with unity $(0,1)$.
My question-
Is the ring $S$ a prime ring?
In case $R$ is a commutative prime ring with unity, I have shown $S$ is not a prime ring.
But I am stuck in the case $R$ is non commutative prime ring without unity.
ring-theory
Let $R$ be a non commutative prime ring without unity and let $S$ be the set of all ordered pair $(a,i)$, where $ain R$ and $iin I$, where $I$ is the ring of integers. On $S$ we define addition and multiplication as follows:
$(a,i)+(b,j)=(a+b,i+j)$,
$(a,i)(b,j)=(ab+ib+ja, ij)$.
Then $S$ is a ring with unity $(0,1)$.
My question-
Is the ring $S$ a prime ring?
In case $R$ is a commutative prime ring with unity, I have shown $S$ is not a prime ring.
But I am stuck in the case $R$ is non commutative prime ring without unity.
ring-theory
ring-theory
asked 7 hours ago
nazim khan
555
555
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago
add a comment |
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3060351%2fring-theory-is-the-ring-s-a-prime-ring-ref-page-no-8-section-2-neal-h-m%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3060351%2fring-theory-is-the-ring-s-a-prime-ring-ref-page-no-8-section-2-neal-h-m%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
If you have already shown the statement to be false for commutative ring with identity, what is there left to do? You have not been asked to prove it is false for all categories of rings.
– rschwieb
49 mins ago