If $(Ω,A,text P)$ is a non-atomic prob. space and $μ$ is a prob. measure on a Borel space there is a...












1














Let





  • $(Omega,mathcal A,operatorname P)$ be a non-atomic probability space


  • $(E,mathcal E)$ be a Borel space


  • $mu$ be a probability measure on $(E,mathcal E)$



How can we show that there is a $(mathcal A,mathcal E)$-measurable $X:Omegato E$ with $X_astoperatorname P=mu$ (pushforward measure)?




I know that if $(mathbb R,mathcal B(mathbb R),nu)$ is a non-atomic probability space, the distribution function $F$ of $nu$ is continous and $F_astnu=mathcal U_{[0,:1]}$ (uniform distribution).




Now, I'll assume that for all $Binmathcal B(mathbb R)$, $(B,mathcal B(B))$ is isomorphic to $(mathbb R,mathcal B(mathbb R))$ (i.e. there is a measurable bijection between $(B,mathcal B(B))$ and $(mathbb R,mathcal B(mathbb R))$ with measurable inverse). Does anyone have a reference for that claim?




By that assumption, there is a $mathcal U_{[0,:1]}$-distributed random variable on any non-atomic probability space $(B,mathcal B(B),nu)$ with $Binmathcal B(mathbb R)$.



$(E,mathcal E)$ being Borel implies that $(E,mathcal E)$ is isomorphic to $(B,mathcal B(B))$.




How can we conclude? This answer seems to claim that the desired conclusion is possible, but I don't get how we need to argue exactly.











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  • 1




    See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
    – Kavi Rama Murthy
    Jan 3 at 23:55












  • @KaviRamaMurthy Do you have a specific section in mind?
    – 0xbadf00d
    Jan 4 at 0:17










  • There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
    – Kavi Rama Murthy
    Jan 4 at 0:21










  • @KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
    – 0xbadf00d
    Jan 4 at 0:23


















1














Let





  • $(Omega,mathcal A,operatorname P)$ be a non-atomic probability space


  • $(E,mathcal E)$ be a Borel space


  • $mu$ be a probability measure on $(E,mathcal E)$



How can we show that there is a $(mathcal A,mathcal E)$-measurable $X:Omegato E$ with $X_astoperatorname P=mu$ (pushforward measure)?




I know that if $(mathbb R,mathcal B(mathbb R),nu)$ is a non-atomic probability space, the distribution function $F$ of $nu$ is continous and $F_astnu=mathcal U_{[0,:1]}$ (uniform distribution).




Now, I'll assume that for all $Binmathcal B(mathbb R)$, $(B,mathcal B(B))$ is isomorphic to $(mathbb R,mathcal B(mathbb R))$ (i.e. there is a measurable bijection between $(B,mathcal B(B))$ and $(mathbb R,mathcal B(mathbb R))$ with measurable inverse). Does anyone have a reference for that claim?




By that assumption, there is a $mathcal U_{[0,:1]}$-distributed random variable on any non-atomic probability space $(B,mathcal B(B),nu)$ with $Binmathcal B(mathbb R)$.



$(E,mathcal E)$ being Borel implies that $(E,mathcal E)$ is isomorphic to $(B,mathcal B(B))$.




How can we conclude? This answer seems to claim that the desired conclusion is possible, but I don't get how we need to argue exactly.











share|cite|improve this question




















  • 1




    See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
    – Kavi Rama Murthy
    Jan 3 at 23:55












  • @KaviRamaMurthy Do you have a specific section in mind?
    – 0xbadf00d
    Jan 4 at 0:17










  • There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
    – Kavi Rama Murthy
    Jan 4 at 0:21










  • @KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
    – 0xbadf00d
    Jan 4 at 0:23
















1












1








1







Let





  • $(Omega,mathcal A,operatorname P)$ be a non-atomic probability space


  • $(E,mathcal E)$ be a Borel space


  • $mu$ be a probability measure on $(E,mathcal E)$



How can we show that there is a $(mathcal A,mathcal E)$-measurable $X:Omegato E$ with $X_astoperatorname P=mu$ (pushforward measure)?




I know that if $(mathbb R,mathcal B(mathbb R),nu)$ is a non-atomic probability space, the distribution function $F$ of $nu$ is continous and $F_astnu=mathcal U_{[0,:1]}$ (uniform distribution).




Now, I'll assume that for all $Binmathcal B(mathbb R)$, $(B,mathcal B(B))$ is isomorphic to $(mathbb R,mathcal B(mathbb R))$ (i.e. there is a measurable bijection between $(B,mathcal B(B))$ and $(mathbb R,mathcal B(mathbb R))$ with measurable inverse). Does anyone have a reference for that claim?




By that assumption, there is a $mathcal U_{[0,:1]}$-distributed random variable on any non-atomic probability space $(B,mathcal B(B),nu)$ with $Binmathcal B(mathbb R)$.



$(E,mathcal E)$ being Borel implies that $(E,mathcal E)$ is isomorphic to $(B,mathcal B(B))$.




How can we conclude? This answer seems to claim that the desired conclusion is possible, but I don't get how we need to argue exactly.











share|cite|improve this question















Let





  • $(Omega,mathcal A,operatorname P)$ be a non-atomic probability space


  • $(E,mathcal E)$ be a Borel space


  • $mu$ be a probability measure on $(E,mathcal E)$



How can we show that there is a $(mathcal A,mathcal E)$-measurable $X:Omegato E$ with $X_astoperatorname P=mu$ (pushforward measure)?




I know that if $(mathbb R,mathcal B(mathbb R),nu)$ is a non-atomic probability space, the distribution function $F$ of $nu$ is continous and $F_astnu=mathcal U_{[0,:1]}$ (uniform distribution).




Now, I'll assume that for all $Binmathcal B(mathbb R)$, $(B,mathcal B(B))$ is isomorphic to $(mathbb R,mathcal B(mathbb R))$ (i.e. there is a measurable bijection between $(B,mathcal B(B))$ and $(mathbb R,mathcal B(mathbb R))$ with measurable inverse). Does anyone have a reference for that claim?




By that assumption, there is a $mathcal U_{[0,:1]}$-distributed random variable on any non-atomic probability space $(B,mathcal B(B),nu)$ with $Binmathcal B(mathbb R)$.



$(E,mathcal E)$ being Borel implies that $(E,mathcal E)$ is isomorphic to $(B,mathcal B(B))$.




How can we conclude? This answer seems to claim that the desired conclusion is possible, but I don't get how we need to argue exactly.








probability-theory measure-theory probability-distributions random-variables






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edited Jan 4 at 0:19

























asked Jan 3 at 21:39









0xbadf00d

1,75741430




1,75741430








  • 1




    See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
    – Kavi Rama Murthy
    Jan 3 at 23:55












  • @KaviRamaMurthy Do you have a specific section in mind?
    – 0xbadf00d
    Jan 4 at 0:17










  • There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
    – Kavi Rama Murthy
    Jan 4 at 0:21










  • @KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
    – 0xbadf00d
    Jan 4 at 0:23
















  • 1




    See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
    – Kavi Rama Murthy
    Jan 3 at 23:55












  • @KaviRamaMurthy Do you have a specific section in mind?
    – 0xbadf00d
    Jan 4 at 0:17










  • There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
    – Kavi Rama Murthy
    Jan 4 at 0:21










  • @KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
    – 0xbadf00d
    Jan 4 at 0:23










1




1




See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
– Kavi Rama Murthy
Jan 3 at 23:55






See 'A course on Borel sets' by Srivastava and 'Measure Theory' by Cohen.
– Kavi Rama Murthy
Jan 3 at 23:55














@KaviRamaMurthy Do you have a specific section in mind?
– 0xbadf00d
Jan 4 at 0:17




@KaviRamaMurthy Do you have a specific section in mind?
– 0xbadf00d
Jan 4 at 0:17












There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
– Kavi Rama Murthy
Jan 4 at 0:21




There are several isomorphism theorems in measure theory and the they are quite deep. You will, have to spend quiet a bit of time to digest these. I suggest you first look at statements of some of these theorems from Cohen's book first.
– Kavi Rama Murthy
Jan 4 at 0:21












@KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
– 0xbadf00d
Jan 4 at 0:23






@KaviRamaMurthy Your comment is only related to the isomorphism between $(mathbb R,mathcal B(mathbb R))$ and $(B,mathcal B(B))$ I've asked for, right? If so, do you have any idea how we need to proceed once this existence is known?
– 0xbadf00d
Jan 4 at 0:23












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