How to calculate Wind direction from uwind and vwind?
How to calculate wind direction from uwind and vwind?
if uwind and vwind are -1.82 , -3.18 respectively
meteorology oceanography
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
How to calculate wind direction from uwind and vwind?
if uwind and vwind are -1.82 , -3.18 respectively
meteorology oceanography
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago
add a comment |
How to calculate wind direction from uwind and vwind?
if uwind and vwind are -1.82 , -3.18 respectively
meteorology oceanography
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
How to calculate wind direction from uwind and vwind?
if uwind and vwind are -1.82 , -3.18 respectively
meteorology oceanography
meteorology oceanography
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
asked yesterday
ThehalfarisedPheonixThehalfarisedPheonix
111
111
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ThehalfarisedPheonix is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago
add a comment |
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago
add a comment |
1 Answer
1
active
oldest
votes
The base formula for the direction $theta$ is
$theta=atan2left(frac{text{uwind}}{text{vwind}}right)$
Where $atan2$ is the four quadrant inverse tangent. Note that if you used the normal inverse tangent your results will be all collapsed to the first quadrant (0° to 90°). Also note that depending on the platform the result can be in radians or degrees (most often in radians, some platforms have a function atan2d that return values in degrees).
If you get a negative value (which is the same direction but measured counterclockwise), you have to add 360° (or $2pi$ radians).
This will give you the direction the wind is coming from. For the direction is going to, you have to add/substract 180° (or $pi$ radians).
For the values you provide, the answer would be 210°.
answered yesterday
Camilo RadaCamilo Rada
8,00812563
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "553"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
ThehalfarisedPheonix is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fearthscience.stackexchange.com%2fquestions%2f15883%2fhow-to-calculate-wind-direction-from-uwind-and-vwind%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The base formula for the direction $theta$ is
$theta=atan2left(frac{text{uwind}}{text{vwind}}right)$
Where $atan2$ is the four quadrant inverse tangent. Note that if you used the normal inverse tangent your results will be all collapsed to the first quadrant (0° to 90°). Also note that depending on the platform the result can be in radians or degrees (most often in radians, some platforms have a function atan2d that return values in degrees).
If you get a negative value (which is the same direction but measured counterclockwise), you have to add 360° (or $2pi$ radians).
This will give you the direction the wind is coming from. For the direction is going to, you have to add/substract 180° (or $pi$ radians).
For the values you provide, the answer would be 210°.
answered yesterday
Camilo RadaCamilo Rada
8,00812563
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
add a comment |
The base formula for the direction $theta$ is
$theta=atan2left(frac{text{uwind}}{text{vwind}}right)$
Where $atan2$ is the four quadrant inverse tangent. Note that if you used the normal inverse tangent your results will be all collapsed to the first quadrant (0° to 90°). Also note that depending on the platform the result can be in radians or degrees (most often in radians, some platforms have a function atan2d that return values in degrees).
If you get a negative value (which is the same direction but measured counterclockwise), you have to add 360° (or $2pi$ radians).
This will give you the direction the wind is coming from. For the direction is going to, you have to add/substract 180° (or $pi$ radians).
For the values you provide, the answer would be 210°.
answered yesterday
Camilo RadaCamilo Rada
8,00812563
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
add a comment |
The base formula for the direction $theta$ is
$theta=atan2left(frac{text{uwind}}{text{vwind}}right)$
Where $atan2$ is the four quadrant inverse tangent. Note that if you used the normal inverse tangent your results will be all collapsed to the first quadrant (0° to 90°). Also note that depending on the platform the result can be in radians or degrees (most often in radians, some platforms have a function atan2d that return values in degrees).
If you get a negative value (which is the same direction but measured counterclockwise), you have to add 360° (or $2pi$ radians).
This will give you the direction the wind is coming from. For the direction is going to, you have to add/substract 180° (or $pi$ radians).
For the values you provide, the answer would be 210°.
answered yesterday
Camilo RadaCamilo Rada
8,00812563
The base formula for the direction $theta$ is
$theta=atan2left(frac{text{uwind}}{text{vwind}}right)$
Where $atan2$ is the four quadrant inverse tangent. Note that if you used the normal inverse tangent your results will be all collapsed to the first quadrant (0° to 90°). Also note that depending on the platform the result can be in radians or degrees (most often in radians, some platforms have a function atan2d that return values in degrees).
If you get a negative value (which is the same direction but measured counterclockwise), you have to add 360° (or $2pi$ radians).
This will give you the direction the wind is coming from. For the direction is going to, you have to add/substract 180° (or $pi$ radians).
For the values you provide, the answer would be 210°.
answered yesterday
Camilo RadaCamilo Rada
8,00812563
edited yesterday
answered yesterday
Camilo RadaCamilo Rada
8,00812563
answered yesterday
Camilo RadaCamilo Rada
8,00812563
answered yesterday
Camilo RadaCamilo Rada
8,00812563
8,00812563
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
add a comment |
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
Query: maths & hence trigonometry uses a horizontal, x-direction, east-west line as it's reference & angles are measured anti-clockwise. Surveying and navigation uses the y-direction, north-south line as its reference & angles are measured clockwise. By simply using the atan2 function, would this give the answer using the mathematical reference line & if so would it then need to be adjusted for surveying/navigation reference?
– Fred
15 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
@Fred You are right about the differences in the reference frame, but this formula does not know where does point the reference line the angle is measured from. In the math world uwind would be X, and vwind would be Y and you would consider the resulting angle as measured clockwise from the direction the positive X axis points to. But in the geographical world you can just use the same output angle and simply consider it as measured clockwise from the north arrow.
– Camilo Rada
7 hours ago
add a comment |
ThehalfarisedPheonix is a new contributor. Be nice, and check out our Code of Conduct.
ThehalfarisedPheonix is a new contributor. Be nice, and check out our Code of Conduct.
ThehalfarisedPheonix is a new contributor. Be nice, and check out our Code of Conduct.
ThehalfarisedPheonix is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Earth Science Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fearthscience.stackexchange.com%2fquestions%2f15883%2fhow-to-calculate-wind-direction-from-uwind-and-vwind%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
colaweb.gmu.edu/dev/clim301/lectures/wind/wind-uv if you want more detail for the formula provided in the answer
– gansub
19 hours ago