Why Does GraphPlot mislabel Vertices from a Graph?
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
asked yesterday
tjm167ustjm167us
506211
add a comment |
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
asked yesterday
tjm167ustjm167us
506211
add a comment |
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
asked yesterday
tjm167ustjm167us
506211
A very peculiar thing is happening when I wrap a Graph with GraphPlot. The picture below shows the correct vertex labeling. However, GraphPlot changes the vertex labeling! Am I misusing this function or is this something I should report to Wolfram? I'm running version 11.0.1.0.
Below is some code to reproduce the issue (but with a simpler graph).
{gph = Graph[{2 -> 1, 5 -> 0, 7 -> 6, 8 -> 7, 10 -> 8, 0 -> 2, 2 -> 3,
3 -> 4, 5 -> 10, 8 -> 9}, VertexLabels -> "Name"],
GraphPlot[gph, VertexLabeling -> True]}
Interestingly enough, using a built-in function (like KaryTree) yields expected results:
{KaryTree[15, VertexLabels -> "Name"],
GraphPlot[KaryTree[15], VertexLabeling -> True]}
My work-around is using Graph and formatting it exactly how I want, but I would like to understand why the vertex labeling is incorrect!
graphs-and-networks
graphs-and-networks
asked yesterday
tjm167ustjm167us
506211
asked yesterday
tjm167ustjm167us
506211
asked yesterday
tjm167ustjm167us
506211
asked yesterday
tjm167ustjm167us
506211
asked yesterday
tjm167ustjm167us
506211
506211
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
GraphPlot supports inputs in several different formats. Originally, it took either a list of Rules or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot also takes Graph expressions as input. But it handles Graphs by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
answered yesterday
SzabolcsSzabolcs
158k13432926
1
One of SW's Twitch videos showed thatGraphPlotis being updated for version 12.0, so you can expect this to be fixed.
– Szabolcs
yesterday
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
GraphPlot supports inputs in several different formats. Originally, it took either a list of Rules or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot also takes Graph expressions as input. But it handles Graphs by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
answered yesterday
SzabolcsSzabolcs
158k13432926
1
One of SW's Twitch videos showed thatGraphPlotis being updated for version 12.0, so you can expect this to be fixed.
– Szabolcs
yesterday
add a comment |
GraphPlot supports inputs in several different formats. Originally, it took either a list of Rules or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot also takes Graph expressions as input. But it handles Graphs by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
answered yesterday
SzabolcsSzabolcs
158k13432926
1
One of SW's Twitch videos showed thatGraphPlotis being updated for version 12.0, so you can expect this to be fixed.
– Szabolcs
yesterday
add a comment |
GraphPlot supports inputs in several different formats. Originally, it took either a list of Rules or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot also takes Graph expressions as input. But it handles Graphs by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
answered yesterday
SzabolcsSzabolcs
158k13432926
GraphPlot supports inputs in several different formats. Originally, it took either a list of Rules or an adjacency matrix. With a rule-list input, it displays the vertex labels you would expect. But the adjacency matrix does not contain information about vertex names. Thus with a matrix input, it uses vertex indices (not names) for labelling.
In 11.3 (and probably all the way back to at least 10.0), GraphPlot also takes Graph expressions as input. But it handles Graphs by converting them to a matrix (not a rule list!) first. Thus the vertex names are lost, and it will use vertex indices instead.
Workaround: convert the graph to a rule list yourself.
GraphPlot[Rule @@@ EdgeList@gph, VertexLabeling -> True,
DirectedEdges -> True, Method -> "LayeredDrawing"]
answered yesterday
SzabolcsSzabolcs
158k13432926
edited yesterday
answered yesterday
SzabolcsSzabolcs
158k13432926
answered yesterday
SzabolcsSzabolcs
158k13432926
answered yesterday
SzabolcsSzabolcs
158k13432926
158k13432926
1
One of SW's Twitch videos showed thatGraphPlotis being updated for version 12.0, so you can expect this to be fixed.
– Szabolcs
yesterday
add a comment |
1
One of SW's Twitch videos showed thatGraphPlotis being updated for version 12.0, so you can expect this to be fixed.
– Szabolcs
yesterday
1
1
One of SW's Twitch videos showed that
GraphPlot is being updated for version 12.0, so you can expect this to be fixed.– Szabolcs
yesterday
One of SW's Twitch videos showed that
GraphPlot is being updated for version 12.0, so you can expect this to be fixed.– Szabolcs
yesterday
add a comment |
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