How do I convert this into a linear programming problem?












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A farmer is planning to raise wheat and barley. Each acre of wheat yields a profit of $50 and each acre of barley yields a profit of $70. To sow the crop, two machines, a tractor and tiller, are rented. The tractor is available for 200 hours, and the tiller is available for 100 hours, Sowing an acre of barley requires 3 hours of tractor time and 2 hours of tilling. Sowing an acre of wheat requires 4 hours of tractor time and 1 hour of tilling. How many acres of each crop should be planted to maximize the farmer's profit?



I'll try to use simplex method, afterwards.










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    A farmer is planning to raise wheat and barley. Each acre of wheat yields a profit of $50 and each acre of barley yields a profit of $70. To sow the crop, two machines, a tractor and tiller, are rented. The tractor is available for 200 hours, and the tiller is available for 100 hours, Sowing an acre of barley requires 3 hours of tractor time and 2 hours of tilling. Sowing an acre of wheat requires 4 hours of tractor time and 1 hour of tilling. How many acres of each crop should be planted to maximize the farmer's profit?



    I'll try to use simplex method, afterwards.










    share|cite|improve this question



























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      A farmer is planning to raise wheat and barley. Each acre of wheat yields a profit of $50 and each acre of barley yields a profit of $70. To sow the crop, two machines, a tractor and tiller, are rented. The tractor is available for 200 hours, and the tiller is available for 100 hours, Sowing an acre of barley requires 3 hours of tractor time and 2 hours of tilling. Sowing an acre of wheat requires 4 hours of tractor time and 1 hour of tilling. How many acres of each crop should be planted to maximize the farmer's profit?



      I'll try to use simplex method, afterwards.










      share|cite|improve this question















      A farmer is planning to raise wheat and barley. Each acre of wheat yields a profit of $50 and each acre of barley yields a profit of $70. To sow the crop, two machines, a tractor and tiller, are rented. The tractor is available for 200 hours, and the tiller is available for 100 hours, Sowing an acre of barley requires 3 hours of tractor time and 2 hours of tilling. Sowing an acre of wheat requires 4 hours of tractor time and 1 hour of tilling. How many acres of each crop should be planted to maximize the farmer's profit?



      I'll try to use simplex method, afterwards.







      linear-algebra linear-programming






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      edited Mar 29 '15 at 22:51









      George V. Williams

      4,50321746




      4,50321746










      asked Mar 29 '15 at 22:48









      randevrandev

      63




      63






















          1 Answer
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          The first step is to describe what your variables are: $x$ which could be the number of acres of Barley sown, and $y$ which could be the number of acres of wheat.



          Now, what is the profit function: $P = 70x + 50y$ (70 dollars per acre of barley + 50 dollars per acre of wheat).



          Now, what are the constraints: certainly $xgeq 0$ and $ygeq 0$. What about not overusing the tiller?



          $$2x + 1y leq 100$$ 2 hours on tiller for each acre of barley, 1 hour for each acre of wheat... not more than 100 hours available.



          Similarly, what about not overusing the tractor?



          $$3x + 4y leq 200$$ 3 hours on tractor for each acre of barley, 4 hours on the tractor for each acre of wheat... not more than 200 hours total on the tractor.



          Condensing all those constraints you have:



          Maximize $P=70x + 50y$



          Subject to
          begin{align*}
          2x + 1y &leq 100 \
          3x + 4y &leq 200 \
          x, y &geq 0
          end{align*}






          share|cite|improve this answer





















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            The first step is to describe what your variables are: $x$ which could be the number of acres of Barley sown, and $y$ which could be the number of acres of wheat.



            Now, what is the profit function: $P = 70x + 50y$ (70 dollars per acre of barley + 50 dollars per acre of wheat).



            Now, what are the constraints: certainly $xgeq 0$ and $ygeq 0$. What about not overusing the tiller?



            $$2x + 1y leq 100$$ 2 hours on tiller for each acre of barley, 1 hour for each acre of wheat... not more than 100 hours available.



            Similarly, what about not overusing the tractor?



            $$3x + 4y leq 200$$ 3 hours on tractor for each acre of barley, 4 hours on the tractor for each acre of wheat... not more than 200 hours total on the tractor.



            Condensing all those constraints you have:



            Maximize $P=70x + 50y$



            Subject to
            begin{align*}
            2x + 1y &leq 100 \
            3x + 4y &leq 200 \
            x, y &geq 0
            end{align*}






            share|cite|improve this answer


























              1














              The first step is to describe what your variables are: $x$ which could be the number of acres of Barley sown, and $y$ which could be the number of acres of wheat.



              Now, what is the profit function: $P = 70x + 50y$ (70 dollars per acre of barley + 50 dollars per acre of wheat).



              Now, what are the constraints: certainly $xgeq 0$ and $ygeq 0$. What about not overusing the tiller?



              $$2x + 1y leq 100$$ 2 hours on tiller for each acre of barley, 1 hour for each acre of wheat... not more than 100 hours available.



              Similarly, what about not overusing the tractor?



              $$3x + 4y leq 200$$ 3 hours on tractor for each acre of barley, 4 hours on the tractor for each acre of wheat... not more than 200 hours total on the tractor.



              Condensing all those constraints you have:



              Maximize $P=70x + 50y$



              Subject to
              begin{align*}
              2x + 1y &leq 100 \
              3x + 4y &leq 200 \
              x, y &geq 0
              end{align*}






              share|cite|improve this answer
























                1












                1








                1






                The first step is to describe what your variables are: $x$ which could be the number of acres of Barley sown, and $y$ which could be the number of acres of wheat.



                Now, what is the profit function: $P = 70x + 50y$ (70 dollars per acre of barley + 50 dollars per acre of wheat).



                Now, what are the constraints: certainly $xgeq 0$ and $ygeq 0$. What about not overusing the tiller?



                $$2x + 1y leq 100$$ 2 hours on tiller for each acre of barley, 1 hour for each acre of wheat... not more than 100 hours available.



                Similarly, what about not overusing the tractor?



                $$3x + 4y leq 200$$ 3 hours on tractor for each acre of barley, 4 hours on the tractor for each acre of wheat... not more than 200 hours total on the tractor.



                Condensing all those constraints you have:



                Maximize $P=70x + 50y$



                Subject to
                begin{align*}
                2x + 1y &leq 100 \
                3x + 4y &leq 200 \
                x, y &geq 0
                end{align*}






                share|cite|improve this answer












                The first step is to describe what your variables are: $x$ which could be the number of acres of Barley sown, and $y$ which could be the number of acres of wheat.



                Now, what is the profit function: $P = 70x + 50y$ (70 dollars per acre of barley + 50 dollars per acre of wheat).



                Now, what are the constraints: certainly $xgeq 0$ and $ygeq 0$. What about not overusing the tiller?



                $$2x + 1y leq 100$$ 2 hours on tiller for each acre of barley, 1 hour for each acre of wheat... not more than 100 hours available.



                Similarly, what about not overusing the tractor?



                $$3x + 4y leq 200$$ 3 hours on tractor for each acre of barley, 4 hours on the tractor for each acre of wheat... not more than 200 hours total on the tractor.



                Condensing all those constraints you have:



                Maximize $P=70x + 50y$



                Subject to
                begin{align*}
                2x + 1y &leq 100 \
                3x + 4y &leq 200 \
                x, y &geq 0
                end{align*}







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 29 '15 at 22:58









                TravisJTravisJ

                6,35831730




                6,35831730






























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