How to keep the state of relay












3














In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:



schematic



How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?






relay schematics







share|improve this question




















  • 1




    It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
    – Harry Svensson
    2 days ago






  • 1




    Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
    – mike65535
    2 days ago










  • thanks @HarrySvensson found the solution.
    – newbie
    2 days ago










  • thanks @mike65535 found the solution.
    – newbie
    2 days ago
















3














In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:



schematic



How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?






relay schematics







share|improve this question




















  • 1




    It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
    – Harry Svensson
    2 days ago






  • 1




    Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
    – mike65535
    2 days ago










  • thanks @HarrySvensson found the solution.
    – newbie
    2 days ago










  • thanks @mike65535 found the solution.
    – newbie
    2 days ago














3












3








3


3





In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:



schematic



How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?






relay schematics







share|improve this question















In schematic below when current exceeds the set point of PR1 it toggles the relay and as soon as current drops the relay goes back to normal state:



schematic



How can i keep the relay state as triggered even when the current drops and only switch the relay back to normal state when i pressed a push-button?






relay schematics




relay schematics






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago







newbie

















asked 2 days ago









newbienewbie

469




469








  • 1




    It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
    – Harry Svensson
    2 days ago






  • 1




    Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
    – mike65535
    2 days ago










  • thanks @HarrySvensson found the solution.
    – newbie
    2 days ago










  • thanks @mike65535 found the solution.
    – newbie
    2 days ago














  • 1




    It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
    – Harry Svensson
    2 days ago






  • 1




    Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
    – mike65535
    2 days ago










  • thanks @HarrySvensson found the solution.
    – newbie
    2 days ago










  • thanks @mike65535 found the solution.
    – newbie
    2 days ago








1




1




It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
– Harry Svensson
2 days ago




It would be interesting to hear what this circuit will accomplish once it's done. Some background information is what I'm talking about, who knows, maybe, just maybe, there's a better solution to that than what you've proposed.
– Harry Svensson
2 days ago




1




1




Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
– mike65535
2 days ago




Can you use a second relay, or a DPDT relay? Or perhaps some digital logic?
– mike65535
2 days ago












thanks @HarrySvensson found the solution.
– newbie
2 days ago




thanks @HarrySvensson found the solution.
– newbie
2 days ago












thanks @mike65535 found the solution.
– newbie
2 days ago




thanks @mike65535 found the solution.
– newbie
2 days ago










3 Answers
3






active

oldest

votes


















8














You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).



Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.



To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:





schematic





simulate this circuit – Schematic created using CircuitLab






share|improve this answer





















  • A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
    – Dorian
    2 days ago










  • Oh, already sugested by Sphero
    – Dorian
    2 days ago












  • @Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
    – Bimpelrekkie
    2 days ago










  • When you push the switch the relay will be off no matter the input.
    – Dorian
    2 days ago






  • 1




    @newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
    – Bimpelrekkie
    2 days ago



















8














You can add some positive feedback, with a N.C. pushbutton in series.



For example, a diode from the op-amp output to non-inverting input. With said switch in series.



Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.



Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.



enter image description here






share|improve this answer























  • i'm new to electronics, can you please explain with schematic?
    – newbie
    2 days ago






  • 2




    Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
    – Bimpelrekkie
    2 days ago










  • @Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
    – newbie
    13 mins ago



















3














If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.



https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460



there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.






share|improve this answer





















  • Sometimes called a "bistable (or bi-stable) relay".
    – Stobor
    yesterday











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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









8














You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).



Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.



To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:





schematic





simulate this circuit – Schematic created using CircuitLab






share|improve this answer





















  • A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
    – Dorian
    2 days ago










  • Oh, already sugested by Sphero
    – Dorian
    2 days ago












  • @Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
    – Bimpelrekkie
    2 days ago










  • When you push the switch the relay will be off no matter the input.
    – Dorian
    2 days ago






  • 1




    @newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
    – Bimpelrekkie
    2 days ago
















8














You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).



Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.



To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:





schematic





simulate this circuit – Schematic created using CircuitLab






share|improve this answer





















  • A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
    – Dorian
    2 days ago










  • Oh, already sugested by Sphero
    – Dorian
    2 days ago












  • @Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
    – Bimpelrekkie
    2 days ago










  • When you push the switch the relay will be off no matter the input.
    – Dorian
    2 days ago






  • 1




    @newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
    – Bimpelrekkie
    2 days ago














8












8








8






You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).



Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.



To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:





schematic





simulate this circuit – Schematic created using CircuitLab






share|improve this answer












You can realize the required function using a diode. What needs to be done is to pull one of the inputs of the opamp to such a voltage that the opamp's output stays high (and the relay powered).



Add a diode (1N4148) with the anode to the opamp's output and the kathode to the + input of the opamp. Then when the opamp's output is high (and the relay is powered) the + input of the opamp will be pulled to a higher voltage than R3 and R7 supply (which is about 6 V). The - input of the opamp will not be able to reach that voltage (it will always be at a lower voltage) So the output of the opamp remains high.



To add the reset function, add a 1 kohm resistor in series with the diode and add a switch to ground from the + input to force it low so that the output of the opamp becomes low as well:





schematic





simulate this circuit – Schematic created using CircuitLab







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









BimpelrekkieBimpelrekkie

47.2k240104




47.2k240104












  • A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
    – Dorian
    2 days ago










  • Oh, already sugested by Sphero
    – Dorian
    2 days ago












  • @Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
    – Bimpelrekkie
    2 days ago










  • When you push the switch the relay will be off no matter the input.
    – Dorian
    2 days ago






  • 1




    @newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
    – Bimpelrekkie
    2 days ago


















  • A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
    – Dorian
    2 days ago










  • Oh, already sugested by Sphero
    – Dorian
    2 days ago












  • @Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
    – Bimpelrekkie
    2 days ago










  • When you push the switch the relay will be off no matter the input.
    – Dorian
    2 days ago






  • 1




    @newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
    – Bimpelrekkie
    2 days ago
















A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
– Dorian
2 days ago




A downside of this solution is that it will disarm the relay even in the active area. If it's an overvoltage protection this might be not desirable. Maybe a slight modification could help, using a normal closed push-button in series with D1 instead?
– Dorian
2 days ago












Oh, already sugested by Sphero
– Dorian
2 days ago






Oh, already sugested by Sphero
– Dorian
2 days ago














@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
– Bimpelrekkie
2 days ago




@Dorian A downside of this solution is that it will disarm the relay even in the active area I fail to see how that would happen. Can you explain.
– Bimpelrekkie
2 days ago












When you push the switch the relay will be off no matter the input.
– Dorian
2 days ago




When you push the switch the relay will be off no matter the input.
– Dorian
2 days ago




1




1




@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
– Bimpelrekkie
2 days ago




@newbie Why do you think you need a 2 A diode? If you do not have the 1N4148 you can use almost any other diode including the 1N4007 that's already in your schematic. Also "tolerance" relates to how accurate something is. Your sentence should have been: ... to tolerate more current up to 2A?. Note that there is a resistor in series with the diode, in this circuit the highest current through the diode is 12V/1kohm = 12 mA which is much less than 2 A.
– Bimpelrekkie
2 days ago













8














You can add some positive feedback, with a N.C. pushbutton in series.



For example, a diode from the op-amp output to non-inverting input. With said switch in series.



Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.



Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.



enter image description here






share|improve this answer























  • i'm new to electronics, can you please explain with schematic?
    – newbie
    2 days ago






  • 2




    Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
    – Bimpelrekkie
    2 days ago










  • @Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
    – newbie
    13 mins ago
















8














You can add some positive feedback, with a N.C. pushbutton in series.



For example, a diode from the op-amp output to non-inverting input. With said switch in series.



Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.



Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.



enter image description here






share|improve this answer























  • i'm new to electronics, can you please explain with schematic?
    – newbie
    2 days ago






  • 2




    Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
    – Bimpelrekkie
    2 days ago










  • @Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
    – newbie
    13 mins ago














8












8








8






You can add some positive feedback, with a N.C. pushbutton in series.



For example, a diode from the op-amp output to non-inverting input. With said switch in series.



Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.



Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.



enter image description here






share|improve this answer














You can add some positive feedback, with a N.C. pushbutton in series.



For example, a diode from the op-amp output to non-inverting input. With said switch in series.



Edit: This is similar to Bimpelrekkie's solution except it requires a N.C. pushbutton, which is less common, and does not force the relay state when the button is pushed. The diode can be any common silicon signal diode such as 1N4148.



Note: If you require a particular guaranteed state at power-up you might have to add some circuitry.



enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago

























answered 2 days ago









Spehro PefhanySpehro Pefhany

204k4150408




204k4150408












  • i'm new to electronics, can you please explain with schematic?
    – newbie
    2 days ago






  • 2




    Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
    – Bimpelrekkie
    2 days ago










  • @Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
    – newbie
    13 mins ago


















  • i'm new to electronics, can you please explain with schematic?
    – newbie
    2 days ago






  • 2




    Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
    – Bimpelrekkie
    2 days ago










  • @Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
    – newbie
    13 mins ago
















i'm new to electronics, can you please explain with schematic?
– newbie
2 days ago




i'm new to electronics, can you please explain with schematic?
– newbie
2 days ago




2




2




Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
– Bimpelrekkie
2 days ago




Indeed I did not suggest this solution as push-to-open push buttons are hard(er) to find than push-to-close push buttons.
– Bimpelrekkie
2 days ago












@Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
– newbie
13 mins ago




@Sephro Pefhany using Bimpelrekkie method i swapped pin 2 with pin 3, so now when i connect the power relay state will be off, when i push the button it will trigger the relay and when current exceeds set point relay goes back to normal state. the only problem is when i connect the power it toggle the relay for like 200ms then relay goes off. how can i avoid that?
– newbie
13 mins ago











3














If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.



https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460



there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.






share|improve this answer





















  • Sometimes called a "bistable (or bi-stable) relay".
    – Stobor
    yesterday
















3














If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.



https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460



there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.






share|improve this answer





















  • Sometimes called a "bistable (or bi-stable) relay".
    – Stobor
    yesterday














3












3








3






If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.



https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460



there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.






share|improve this answer












If you have a chance to change your relay, you may try to use latching relays.
I'm adding a latching relay below.BTW I couldn't check current and voltage ratings of your circuit. This component is just an example.



https://www.digikey.com/product-detail/en/kemet/EE2-3SNUH-L/399-11008-1-ND/4506460



there is 2 control input in this relay. once you triggered first input and the other one is logic0, relay switches inputs. Until you apply trigger to the second input this will stay same.







share|improve this answer












share|improve this answer



share|improve this answer










answered 2 days ago









KorayKoray

704




704












  • Sometimes called a "bistable (or bi-stable) relay".
    – Stobor
    yesterday


















  • Sometimes called a "bistable (or bi-stable) relay".
    – Stobor
    yesterday
















Sometimes called a "bistable (or bi-stable) relay".
– Stobor
yesterday




Sometimes called a "bistable (or bi-stable) relay".
– Stobor
yesterday


















draft saved

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