How does a guitar work?












6














Here are four different possible ways:




  1. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the air inside the sound box to vibrate also, which vibrates the outside air also.


  2. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the front wall of the sound box to vibrate also, which vibrates the outside air.


  3. The plucked string has varying tension; when it is longer it has more tension and when it is at the middle of its cycle it has less. This changing tension causes the guitar to vibrate because of the effect at the bridge and/or the nut. The vibrating walls of the guitar, particularly the front wall of the sound box, vibrate the outside air.


  4. The plucked string has transverse vibration, and that sideways motion at the bridge or the nut is somehow what makes the body of the guitar vibrate.



1 does not make sense to me but for all I know it could be true. If it's true, a string under tension which has no connection to a soundbox would make a soundbox make loud noise if the vibrating string was close to the soundbox.



2 would help explain why guitar makers often use an expensive wood for the front and cheap woods for sides and back, because the front is particularly important for vibrating just right.



Both #1 and #2 have the disadvantage that the string isn't very good at vibrating the air which is why you want a sounding board, and yet we depend on the air vibration of the string to make the sounding board move.



3 and 4 would also explain the expensive wood on front. Ovation brand guitars use a tough plastic for the sides and back, with very little difference in tone.



The Godin acoustocaster apparently can function as an acoustic guitar with no soundhole at all. If so, I doubt that the air vibrating inside the body of the guitar is critical.



I stuffed a sweater inside my guitar and I couldn't tell any difference in the sound except when it actually touched a string.



I tried sliding a piece of stiff thin cardboard over the soundhole while playing a note, and I couldn't tell any difference in the sound.



I started out thinking there was a difference between an effect caused by a transverse motion of the string, versus the effect caused by a tensional longitudinal difference at the bridge. But now I'm not sure I understand the difference in a guitar. I can say that it sounded about the same when I plucked it up versus sideways, but I couldn't do that very loud without buzzing against the frets.



I really tend to think the effect on the sound box is longitudinal on an irish harp. But I could be wrong. I don't see how to test it.



enter image description here



Safesphere's answer is excellent, and explains many things I wanted to know.



My remaining question is kind of academic and maybe not worth answering, but I'm still curious. I'll approach it as a thought experiment.



Imagine you have a guitar wire with the ends embedded in two concrete walls, stretched. No give in those walls at all. You clamp a small fishing weight onto the wire at the midpoint. If you pluck the wire, you are clearly causing lateral motion. The string will vibrate laterally because of the mass of the fishing weight versus the stretch of the wire. The string is a spring, and its vibration depends on mass versus stretch.



Now imagine you take that same guitar wire and instead connect one end to a dynamometer. If the vibration is slow enough, I expect you will see the load changing in a sine wave when you pluck the string. And I expect it will be mostly because of the change in the longitudinal force from the stretched string, and not because of the angular change from the string's transverse vibration.



Similarly, if you connect a sounding board to one end of the string instead of a solid concrete wall, I expect the effect on the sounding board is probably more from the change in tension than from the transverse motion of the string.



But this is a picky point, probably not worth a lot of argument.










share|cite|improve this question





























    6














    Here are four different possible ways:




    1. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the air inside the sound box to vibrate also, which vibrates the outside air also.


    2. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the front wall of the sound box to vibrate also, which vibrates the outside air.


    3. The plucked string has varying tension; when it is longer it has more tension and when it is at the middle of its cycle it has less. This changing tension causes the guitar to vibrate because of the effect at the bridge and/or the nut. The vibrating walls of the guitar, particularly the front wall of the sound box, vibrate the outside air.


    4. The plucked string has transverse vibration, and that sideways motion at the bridge or the nut is somehow what makes the body of the guitar vibrate.



    1 does not make sense to me but for all I know it could be true. If it's true, a string under tension which has no connection to a soundbox would make a soundbox make loud noise if the vibrating string was close to the soundbox.



    2 would help explain why guitar makers often use an expensive wood for the front and cheap woods for sides and back, because the front is particularly important for vibrating just right.



    Both #1 and #2 have the disadvantage that the string isn't very good at vibrating the air which is why you want a sounding board, and yet we depend on the air vibration of the string to make the sounding board move.



    3 and 4 would also explain the expensive wood on front. Ovation brand guitars use a tough plastic for the sides and back, with very little difference in tone.



    The Godin acoustocaster apparently can function as an acoustic guitar with no soundhole at all. If so, I doubt that the air vibrating inside the body of the guitar is critical.



    I stuffed a sweater inside my guitar and I couldn't tell any difference in the sound except when it actually touched a string.



    I tried sliding a piece of stiff thin cardboard over the soundhole while playing a note, and I couldn't tell any difference in the sound.



    I started out thinking there was a difference between an effect caused by a transverse motion of the string, versus the effect caused by a tensional longitudinal difference at the bridge. But now I'm not sure I understand the difference in a guitar. I can say that it sounded about the same when I plucked it up versus sideways, but I couldn't do that very loud without buzzing against the frets.



    I really tend to think the effect on the sound box is longitudinal on an irish harp. But I could be wrong. I don't see how to test it.



    enter image description here



    Safesphere's answer is excellent, and explains many things I wanted to know.



    My remaining question is kind of academic and maybe not worth answering, but I'm still curious. I'll approach it as a thought experiment.



    Imagine you have a guitar wire with the ends embedded in two concrete walls, stretched. No give in those walls at all. You clamp a small fishing weight onto the wire at the midpoint. If you pluck the wire, you are clearly causing lateral motion. The string will vibrate laterally because of the mass of the fishing weight versus the stretch of the wire. The string is a spring, and its vibration depends on mass versus stretch.



    Now imagine you take that same guitar wire and instead connect one end to a dynamometer. If the vibration is slow enough, I expect you will see the load changing in a sine wave when you pluck the string. And I expect it will be mostly because of the change in the longitudinal force from the stretched string, and not because of the angular change from the string's transverse vibration.



    Similarly, if you connect a sounding board to one end of the string instead of a solid concrete wall, I expect the effect on the sounding board is probably more from the change in tension than from the transverse motion of the string.



    But this is a picky point, probably not worth a lot of argument.










    share|cite|improve this question



























      6












      6








      6


      3





      Here are four different possible ways:




      1. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the air inside the sound box to vibrate also, which vibrates the outside air also.


      2. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the front wall of the sound box to vibrate also, which vibrates the outside air.


      3. The plucked string has varying tension; when it is longer it has more tension and when it is at the middle of its cycle it has less. This changing tension causes the guitar to vibrate because of the effect at the bridge and/or the nut. The vibrating walls of the guitar, particularly the front wall of the sound box, vibrate the outside air.


      4. The plucked string has transverse vibration, and that sideways motion at the bridge or the nut is somehow what makes the body of the guitar vibrate.



      1 does not make sense to me but for all I know it could be true. If it's true, a string under tension which has no connection to a soundbox would make a soundbox make loud noise if the vibrating string was close to the soundbox.



      2 would help explain why guitar makers often use an expensive wood for the front and cheap woods for sides and back, because the front is particularly important for vibrating just right.



      Both #1 and #2 have the disadvantage that the string isn't very good at vibrating the air which is why you want a sounding board, and yet we depend on the air vibration of the string to make the sounding board move.



      3 and 4 would also explain the expensive wood on front. Ovation brand guitars use a tough plastic for the sides and back, with very little difference in tone.



      The Godin acoustocaster apparently can function as an acoustic guitar with no soundhole at all. If so, I doubt that the air vibrating inside the body of the guitar is critical.



      I stuffed a sweater inside my guitar and I couldn't tell any difference in the sound except when it actually touched a string.



      I tried sliding a piece of stiff thin cardboard over the soundhole while playing a note, and I couldn't tell any difference in the sound.



      I started out thinking there was a difference between an effect caused by a transverse motion of the string, versus the effect caused by a tensional longitudinal difference at the bridge. But now I'm not sure I understand the difference in a guitar. I can say that it sounded about the same when I plucked it up versus sideways, but I couldn't do that very loud without buzzing against the frets.



      I really tend to think the effect on the sound box is longitudinal on an irish harp. But I could be wrong. I don't see how to test it.



      enter image description here



      Safesphere's answer is excellent, and explains many things I wanted to know.



      My remaining question is kind of academic and maybe not worth answering, but I'm still curious. I'll approach it as a thought experiment.



      Imagine you have a guitar wire with the ends embedded in two concrete walls, stretched. No give in those walls at all. You clamp a small fishing weight onto the wire at the midpoint. If you pluck the wire, you are clearly causing lateral motion. The string will vibrate laterally because of the mass of the fishing weight versus the stretch of the wire. The string is a spring, and its vibration depends on mass versus stretch.



      Now imagine you take that same guitar wire and instead connect one end to a dynamometer. If the vibration is slow enough, I expect you will see the load changing in a sine wave when you pluck the string. And I expect it will be mostly because of the change in the longitudinal force from the stretched string, and not because of the angular change from the string's transverse vibration.



      Similarly, if you connect a sounding board to one end of the string instead of a solid concrete wall, I expect the effect on the sounding board is probably more from the change in tension than from the transverse motion of the string.



      But this is a picky point, probably not worth a lot of argument.










      share|cite|improve this question















      Here are four different possible ways:




      1. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the air inside the sound box to vibrate also, which vibrates the outside air also.


      2. The plucked string vibrates longitudinally, vibrating the air around it. This vibrating air then causes the front wall of the sound box to vibrate also, which vibrates the outside air.


      3. The plucked string has varying tension; when it is longer it has more tension and when it is at the middle of its cycle it has less. This changing tension causes the guitar to vibrate because of the effect at the bridge and/or the nut. The vibrating walls of the guitar, particularly the front wall of the sound box, vibrate the outside air.


      4. The plucked string has transverse vibration, and that sideways motion at the bridge or the nut is somehow what makes the body of the guitar vibrate.



      1 does not make sense to me but for all I know it could be true. If it's true, a string under tension which has no connection to a soundbox would make a soundbox make loud noise if the vibrating string was close to the soundbox.



      2 would help explain why guitar makers often use an expensive wood for the front and cheap woods for sides and back, because the front is particularly important for vibrating just right.



      Both #1 and #2 have the disadvantage that the string isn't very good at vibrating the air which is why you want a sounding board, and yet we depend on the air vibration of the string to make the sounding board move.



      3 and 4 would also explain the expensive wood on front. Ovation brand guitars use a tough plastic for the sides and back, with very little difference in tone.



      The Godin acoustocaster apparently can function as an acoustic guitar with no soundhole at all. If so, I doubt that the air vibrating inside the body of the guitar is critical.



      I stuffed a sweater inside my guitar and I couldn't tell any difference in the sound except when it actually touched a string.



      I tried sliding a piece of stiff thin cardboard over the soundhole while playing a note, and I couldn't tell any difference in the sound.



      I started out thinking there was a difference between an effect caused by a transverse motion of the string, versus the effect caused by a tensional longitudinal difference at the bridge. But now I'm not sure I understand the difference in a guitar. I can say that it sounded about the same when I plucked it up versus sideways, but I couldn't do that very loud without buzzing against the frets.



      I really tend to think the effect on the sound box is longitudinal on an irish harp. But I could be wrong. I don't see how to test it.



      enter image description here



      Safesphere's answer is excellent, and explains many things I wanted to know.



      My remaining question is kind of academic and maybe not worth answering, but I'm still curious. I'll approach it as a thought experiment.



      Imagine you have a guitar wire with the ends embedded in two concrete walls, stretched. No give in those walls at all. You clamp a small fishing weight onto the wire at the midpoint. If you pluck the wire, you are clearly causing lateral motion. The string will vibrate laterally because of the mass of the fishing weight versus the stretch of the wire. The string is a spring, and its vibration depends on mass versus stretch.



      Now imagine you take that same guitar wire and instead connect one end to a dynamometer. If the vibration is slow enough, I expect you will see the load changing in a sine wave when you pluck the string. And I expect it will be mostly because of the change in the longitudinal force from the stretched string, and not because of the angular change from the string's transverse vibration.



      Similarly, if you connect a sounding board to one end of the string instead of a solid concrete wall, I expect the effect on the sounding board is probably more from the change in tension than from the transverse motion of the string.



      But this is a picky point, probably not worth a lot of argument.







      acoustics resonance vibrations






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      share|cite|improve this question













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      share|cite|improve this question








      edited yesterday







      J Thomas

















      asked 2 days ago









      J ThomasJ Thomas

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          10














          The string oscillations are mainly transverse (a standing wave). The string motion causes the tension to oscillate thus applying a varying force on the guitar top through the bridge and saddle. The string engage the air very little (as is evident on an electric guitar without amplification). This is because the acoustic wave impedance of the air does not match that of the string, so the energy transfer is not efficient. The guitar top acts as a transformer matching the impedances. The string tension moves the top and the top moves the air.



          However, the top is a dipole, meaning that it moves the air above and below itself out of phase. The wave generated below the top must have its phase and direction reversed to add to the wave generated above. The guitar body acts as a phase inverter with a sound hole acting much like a port on a ported speaker. The main function of the guitar back and sides is not to vibrate, but to simply reflect the sound. For this reason hard wood species like rosewood work best, but also laminated wood or plastic also works. This is in contrast to the guitar top whose function is to vibrate, so the quality of wood is critical there (typically, but not exclusively, spruce or cedar).



          The back wave inverted inside the guitar body and coming out of the sound hole is not 100% of course due to various losses. Even if it were the same amplitude as the front wave, it would increase the volume only by 6dB. In reality it is less and thus is not critically audible. This is why you don't hear much of a volume change when you cover the sound hole or put a sweater inside a guitar. Note that speakers also exist without a port and most speakers have fiberglass inside much like a sweater in the guitar.



          So out of your options, a combination of 4 and consequently 3 is correct, except the air is moved mostly by the top, but not directly by the strings.






          share|cite|improve this answer























          • excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
            – niels nielsen
            2 days ago










          • @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
            – safesphere
            yesterday












          • yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
            – niels nielsen
            yesterday










          • @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
            – safesphere
            yesterday










          • several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
            – niels nielsen
            yesterday











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          1 Answer
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          The string oscillations are mainly transverse (a standing wave). The string motion causes the tension to oscillate thus applying a varying force on the guitar top through the bridge and saddle. The string engage the air very little (as is evident on an electric guitar without amplification). This is because the acoustic wave impedance of the air does not match that of the string, so the energy transfer is not efficient. The guitar top acts as a transformer matching the impedances. The string tension moves the top and the top moves the air.



          However, the top is a dipole, meaning that it moves the air above and below itself out of phase. The wave generated below the top must have its phase and direction reversed to add to the wave generated above. The guitar body acts as a phase inverter with a sound hole acting much like a port on a ported speaker. The main function of the guitar back and sides is not to vibrate, but to simply reflect the sound. For this reason hard wood species like rosewood work best, but also laminated wood or plastic also works. This is in contrast to the guitar top whose function is to vibrate, so the quality of wood is critical there (typically, but not exclusively, spruce or cedar).



          The back wave inverted inside the guitar body and coming out of the sound hole is not 100% of course due to various losses. Even if it were the same amplitude as the front wave, it would increase the volume only by 6dB. In reality it is less and thus is not critically audible. This is why you don't hear much of a volume change when you cover the sound hole or put a sweater inside a guitar. Note that speakers also exist without a port and most speakers have fiberglass inside much like a sweater in the guitar.



          So out of your options, a combination of 4 and consequently 3 is correct, except the air is moved mostly by the top, but not directly by the strings.






          share|cite|improve this answer























          • excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
            – niels nielsen
            2 days ago










          • @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
            – safesphere
            yesterday












          • yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
            – niels nielsen
            yesterday










          • @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
            – safesphere
            yesterday










          • several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
            – niels nielsen
            yesterday
















          10














          The string oscillations are mainly transverse (a standing wave). The string motion causes the tension to oscillate thus applying a varying force on the guitar top through the bridge and saddle. The string engage the air very little (as is evident on an electric guitar without amplification). This is because the acoustic wave impedance of the air does not match that of the string, so the energy transfer is not efficient. The guitar top acts as a transformer matching the impedances. The string tension moves the top and the top moves the air.



          However, the top is a dipole, meaning that it moves the air above and below itself out of phase. The wave generated below the top must have its phase and direction reversed to add to the wave generated above. The guitar body acts as a phase inverter with a sound hole acting much like a port on a ported speaker. The main function of the guitar back and sides is not to vibrate, but to simply reflect the sound. For this reason hard wood species like rosewood work best, but also laminated wood or plastic also works. This is in contrast to the guitar top whose function is to vibrate, so the quality of wood is critical there (typically, but not exclusively, spruce or cedar).



          The back wave inverted inside the guitar body and coming out of the sound hole is not 100% of course due to various losses. Even if it were the same amplitude as the front wave, it would increase the volume only by 6dB. In reality it is less and thus is not critically audible. This is why you don't hear much of a volume change when you cover the sound hole or put a sweater inside a guitar. Note that speakers also exist without a port and most speakers have fiberglass inside much like a sweater in the guitar.



          So out of your options, a combination of 4 and consequently 3 is correct, except the air is moved mostly by the top, but not directly by the strings.






          share|cite|improve this answer























          • excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
            – niels nielsen
            2 days ago










          • @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
            – safesphere
            yesterday












          • yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
            – niels nielsen
            yesterday










          • @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
            – safesphere
            yesterday










          • several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
            – niels nielsen
            yesterday














          10












          10








          10






          The string oscillations are mainly transverse (a standing wave). The string motion causes the tension to oscillate thus applying a varying force on the guitar top through the bridge and saddle. The string engage the air very little (as is evident on an electric guitar without amplification). This is because the acoustic wave impedance of the air does not match that of the string, so the energy transfer is not efficient. The guitar top acts as a transformer matching the impedances. The string tension moves the top and the top moves the air.



          However, the top is a dipole, meaning that it moves the air above and below itself out of phase. The wave generated below the top must have its phase and direction reversed to add to the wave generated above. The guitar body acts as a phase inverter with a sound hole acting much like a port on a ported speaker. The main function of the guitar back and sides is not to vibrate, but to simply reflect the sound. For this reason hard wood species like rosewood work best, but also laminated wood or plastic also works. This is in contrast to the guitar top whose function is to vibrate, so the quality of wood is critical there (typically, but not exclusively, spruce or cedar).



          The back wave inverted inside the guitar body and coming out of the sound hole is not 100% of course due to various losses. Even if it were the same amplitude as the front wave, it would increase the volume only by 6dB. In reality it is less and thus is not critically audible. This is why you don't hear much of a volume change when you cover the sound hole or put a sweater inside a guitar. Note that speakers also exist without a port and most speakers have fiberglass inside much like a sweater in the guitar.



          So out of your options, a combination of 4 and consequently 3 is correct, except the air is moved mostly by the top, but not directly by the strings.






          share|cite|improve this answer














          The string oscillations are mainly transverse (a standing wave). The string motion causes the tension to oscillate thus applying a varying force on the guitar top through the bridge and saddle. The string engage the air very little (as is evident on an electric guitar without amplification). This is because the acoustic wave impedance of the air does not match that of the string, so the energy transfer is not efficient. The guitar top acts as a transformer matching the impedances. The string tension moves the top and the top moves the air.



          However, the top is a dipole, meaning that it moves the air above and below itself out of phase. The wave generated below the top must have its phase and direction reversed to add to the wave generated above. The guitar body acts as a phase inverter with a sound hole acting much like a port on a ported speaker. The main function of the guitar back and sides is not to vibrate, but to simply reflect the sound. For this reason hard wood species like rosewood work best, but also laminated wood or plastic also works. This is in contrast to the guitar top whose function is to vibrate, so the quality of wood is critical there (typically, but not exclusively, spruce or cedar).



          The back wave inverted inside the guitar body and coming out of the sound hole is not 100% of course due to various losses. Even if it were the same amplitude as the front wave, it would increase the volume only by 6dB. In reality it is less and thus is not critically audible. This is why you don't hear much of a volume change when you cover the sound hole or put a sweater inside a guitar. Note that speakers also exist without a port and most speakers have fiberglass inside much like a sweater in the guitar.



          So out of your options, a combination of 4 and consequently 3 is correct, except the air is moved mostly by the top, but not directly by the strings.







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          edited yesterday

























          answered 2 days ago









          safespheresafesphere

          7,21011540




          7,21011540












          • excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
            – niels nielsen
            2 days ago










          • @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
            – safesphere
            yesterday












          • yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
            – niels nielsen
            yesterday










          • @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
            – safesphere
            yesterday










          • several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
            – niels nielsen
            yesterday


















          • excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
            – niels nielsen
            2 days ago










          • @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
            – safesphere
            yesterday












          • yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
            – niels nielsen
            yesterday










          • @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
            – safesphere
            yesterday










          • several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
            – niels nielsen
            yesterday
















          excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
          – niels nielsen
          2 days ago




          excellent reply @safesphere, this topic is of great interest to me, having played guitar and bass for the last 48 years.
          – niels nielsen
          2 days ago












          @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
          – safesphere
          yesterday






          @nielsnielsen Thank you Sir! Please also note that, despite a common misconception, the guitar body is not a resonator. In fact, the objective is for all notes to play uniformly without any resonances standing out. The main design objective there is to tune the body as the most efficient phase inverter for low frequencies (exactly as in a ported speaker). There exist guitars with more than one sound hole on the top and even on the side near the neck (like this for example: hillguitar.com).
          – safesphere
          yesterday














          yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
          – niels nielsen
          yesterday




          yep, it's all about impedance matching... and I'm trying to work out a bass design that uses a 15" speaker cone as the resonating surface- with a reflex port in the body- and a body the same size as the reflex enclosure the speaker was designed for. see my webpage www.nielsenkillowatt for photos of some of my designs. best regards, Niels
          – niels nielsen
          yesterday












          @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
          – safesphere
          yesterday




          @nielsnielsen Cool! I wonder if I should merge my Jose Ramirez with my Daniel Defense ;) I see the woofer base. It looks like you are connecting the cone to the strings. This may cause issues and inefficiency. If I were you, I'd try a setup similar to the acoustic guitar. Put a saddle on a bridge there and pull or push the bridge either up or down with powerful springs attached to the body. This way the vibrating tension of the strings would move the bridge up and down without changing the scale length or pitch. Then just attach the cone solid to the bridge for the energy transfer. Good luck!
          – safesphere
          yesterday












          several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
          – niels nielsen
          yesterday




          several attempts have been made over the years to build "acoustic basses" in which the string coupling to the radiator is as you describe. These radiate very poorly, but my second speaker/resonator bass (which I built into a suitcase) radiates better than any acoustic bass on the market. it has the strings tied to the cone so the cone is forced to move with the string but not required to take any tension loads or static preload (as in the dobro resonators, which have to use aluminum cones for this reason).
          – niels nielsen
          yesterday


















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