I want to extract a specific element from the list and add it
5
{p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6}
I want to extract a specific element from the list and add it.
For example, I want to extract the element which becomes 8 by the element of p [i, j] and add it.
p[0, 8] + p[1, 7] + p[2, 6] + ... = answer
Please advise an efficient way, thank you.
list-manipulation
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
add a comment |
5
{p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6}
I want to extract a specific element from the list and add it.
For example, I want to extract the element which becomes 8 by the element of p [i, j] and add it.
p[0, 8] + p[1, 7] + p[2, 6] + ... = answer
Please advise an efficient way, thank you.
list-manipulation
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
add a comment |
5
5
5
{p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6}
I want to extract a specific element from the list and add it.
For example, I want to extract the element which becomes 8 by the element of p [i, j] and add it.
p[0, 8] + p[1, 7] + p[2, 6] + ... = answer
Please advise an efficient way, thank you.
list-manipulation
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
{p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6}
I want to extract a specific element from the list and add it.
For example, I want to extract the element which becomes 8 by the element of p [i, j] and add it.
p[0, 8] + p[1, 7] + p[2, 6] + ... = answer
Please advise an efficient way, thank you.
list-manipulation
list-manipulation
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
edited yesterday
Αλέξανδρος Ζεγγ
4,1441929
4,1441929
asked 2 days ago
Kenta KawaiKenta Kawai
363
asked 2 days ago
Kenta KawaiKenta Kawai
363
asked 2 days ago
Kenta KawaiKenta Kawai
363
363
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
7
First assign a name to your above list, e.g., run
rules = (*your list*);
Then generate the expression you want, using Table or Array
sum = Plus @@ Table[p[i, 8 - i], {i, 0, 8}]
sum = Array[p[#, 8 - #] &, 9, 0, Plus]
p[0, 8] + p[1, 7] + p[2, 6] + p[3, 5] + p[4, 4] + p[5, 3] + p[6, 2] + p[7, 1] + p[8, 0]
Finally, apply the rules to finish the value substitution via ReplaceAll (/.):
sum /. rules
0.692301
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
add a comment |
4
list= (*your list*)
Total[Select[list, (#[[1, 1]] + #[[1, 2]]) == 8 &] [[All, 2]]]
(*0.692301*)
answered yesterday
Hubble07Hubble07
2,966721
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even useKeySelect:Total @ KeySelect[list, Plus @@ # == 8 &]
– Sjoerd Smit
yesterday
add a comment |
3
Consider GroupBy or Merge. Pick is less specific but still applicable.
rules = {p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6};
GroupBy[rules, Total@*First -> Last, Tr][8]
Merge[Total@# -> #2 & @@@ rules, Tr][8]
Merge[Plus @@@ # & /@ rules, Tr][8]
Merge[rules /. p -> Plus, Tr][8]
Pick[Values@rules, Total /@ Keys@rules, 8] // Tr
All give
0.692301
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
7
First assign a name to your above list, e.g., run
rules = (*your list*);
Then generate the expression you want, using Table or Array
sum = Plus @@ Table[p[i, 8 - i], {i, 0, 8}]
sum = Array[p[#, 8 - #] &, 9, 0, Plus]
p[0, 8] + p[1, 7] + p[2, 6] + p[3, 5] + p[4, 4] + p[5, 3] + p[6, 2] + p[7, 1] + p[8, 0]
Finally, apply the rules to finish the value substitution via ReplaceAll (/.):
sum /. rules
0.692301
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
add a comment |
7
First assign a name to your above list, e.g., run
rules = (*your list*);
Then generate the expression you want, using Table or Array
sum = Plus @@ Table[p[i, 8 - i], {i, 0, 8}]
sum = Array[p[#, 8 - #] &, 9, 0, Plus]
p[0, 8] + p[1, 7] + p[2, 6] + p[3, 5] + p[4, 4] + p[5, 3] + p[6, 2] + p[7, 1] + p[8, 0]
Finally, apply the rules to finish the value substitution via ReplaceAll (/.):
sum /. rules
0.692301
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
add a comment |
7
7
7
First assign a name to your above list, e.g., run
rules = (*your list*);
Then generate the expression you want, using Table or Array
sum = Plus @@ Table[p[i, 8 - i], {i, 0, 8}]
sum = Array[p[#, 8 - #] &, 9, 0, Plus]
p[0, 8] + p[1, 7] + p[2, 6] + p[3, 5] + p[4, 4] + p[5, 3] + p[6, 2] + p[7, 1] + p[8, 0]
Finally, apply the rules to finish the value substitution via ReplaceAll (/.):
sum /. rules
0.692301
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
First assign a name to your above list, e.g., run
rules = (*your list*);
Then generate the expression you want, using Table or Array
sum = Plus @@ Table[p[i, 8 - i], {i, 0, 8}]
sum = Array[p[#, 8 - #] &, 9, 0, Plus]
p[0, 8] + p[1, 7] + p[2, 6] + p[3, 5] + p[4, 4] + p[5, 3] + p[6, 2] + p[7, 1] + p[8, 0]
Finally, apply the rules to finish the value substitution via ReplaceAll (/.):
sum /. rules
0.692301
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
answered yesterday
Αλέξανδρος ΖεγγΑλέξανδρος Ζεγγ
4,1441929
4,1441929
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
add a comment |
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
add a comment |
4
list= (*your list*)
Total[Select[list, (#[[1, 1]] + #[[1, 2]]) == 8 &] [[All, 2]]]
(*0.692301*)
answered yesterday
Hubble07Hubble07
2,966721
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even useKeySelect:Total @ KeySelect[list, Plus @@ # == 8 &]
– Sjoerd Smit
yesterday
add a comment |
4
list= (*your list*)
Total[Select[list, (#[[1, 1]] + #[[1, 2]]) == 8 &] [[All, 2]]]
(*0.692301*)
answered yesterday
Hubble07Hubble07
2,966721
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even useKeySelect:Total @ KeySelect[list, Plus @@ # == 8 &]
– Sjoerd Smit
yesterday
add a comment |
4
4
4
list= (*your list*)
Total[Select[list, (#[[1, 1]] + #[[1, 2]]) == 8 &] [[All, 2]]]
(*0.692301*)
answered yesterday
Hubble07Hubble07
2,966721
list= (*your list*)
Total[Select[list, (#[[1, 1]] + #[[1, 2]]) == 8 &] [[All, 2]]]
(*0.692301*)
answered yesterday
Hubble07Hubble07
2,966721
answered yesterday
Hubble07Hubble07
2,966721
answered yesterday
Hubble07Hubble07
2,966721
answered yesterday
Hubble07Hubble07
2,966721
2,966721
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even useKeySelect:Total @ KeySelect[list, Plus @@ # == 8 &]
– Sjoerd Smit
yesterday
add a comment |
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even useKeySelect:Total @ KeySelect[list, Plus @@ # == 8 &]
– Sjoerd Smit
yesterday
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
Thank you for advice.It solved properly.
– Kenta Kawai
yesterday
You can even use
KeySelect: Total @ KeySelect[list, Plus @@ # == 8 &]– Sjoerd Smit
yesterday
You can even use
KeySelect: Total @ KeySelect[list, Plus @@ # == 8 &]– Sjoerd Smit
yesterday
add a comment |
3
Consider GroupBy or Merge. Pick is less specific but still applicable.
rules = {p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6};
GroupBy[rules, Total@*First -> Last, Tr][8]
Merge[Total@# -> #2 & @@@ rules, Tr][8]
Merge[Plus @@@ # & /@ rules, Tr][8]
Merge[rules /. p -> Plus, Tr][8]
Pick[Values@rules, Total /@ Keys@rules, 8] // Tr
All give
0.692301
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
add a comment |
3
Consider GroupBy or Merge. Pick is less specific but still applicable.
rules = {p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6};
GroupBy[rules, Total@*First -> Last, Tr][8]
Merge[Total@# -> #2 & @@@ rules, Tr][8]
Merge[Plus @@@ # & /@ rules, Tr][8]
Merge[rules /. p -> Plus, Tr][8]
Pick[Values@rules, Total /@ Keys@rules, 8] // Tr
All give
0.692301
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
add a comment |
3
3
3
Consider GroupBy or Merge. Pick is less specific but still applicable.
rules = {p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6};
GroupBy[rules, Total@*First -> Last, Tr][8]
Merge[Total@# -> #2 & @@@ rules, Tr][8]
Merge[Plus @@@ # & /@ rules, Tr][8]
Merge[rules /. p -> Plus, Tr][8]
Pick[Values@rules, Total /@ Keys@rules, 8] // Tr
All give
0.692301
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
Consider GroupBy or Merge. Pick is less specific but still applicable.
rules = {p[0, 8] -> 0.538464, p[1, 7] -> 0.107693, p[1, 8] -> 0.161539,
p[2, 6] -> 0.0323078, p[2, 7] -> 0.0484617, p[2, 8] -> 0.0538464,
p[3, 5] -> 0.00969234, p[3, 6] -> 0.0145385, p[3, 7] -> 0.0161539,
p[4, 4] -> 0.0029077, p[4, 5] -> 0.00436155, p[4, 6] -> 0.00484617,
p[5, 3] -> 0.000872311, p[5, 4] -> 0.00130847, p[5, 5] -> 0.00145385,
p[6, 2] -> 0.000261693, p[6, 3] -> 0.00039254, p[6, 4] -> 0.000436155,
p[7, 1] -> 0.000078508, p[7, 2] -> 0.000117762, p[7, 3] -> 0.000130847,
p[8, 0] -> 0.0000235524, p[8, 1] -> 0.0000353286, p[8, 2] -> 0.000039254,
p[9, 0] -> 0.0000176643, p[9, 1] -> 0.0000117762, p[10, 0] -> 8.83215*10^-6};
GroupBy[rules, Total@*First -> Last, Tr][8]
Merge[Total@# -> #2 & @@@ rules, Tr][8]
Merge[Plus @@@ # & /@ rules, Tr][8]
Merge[rules /. p -> Plus, Tr][8]
Pick[Values@rules, Total /@ Keys@rules, 8] // Tr
All give
0.692301
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
edited yesterday
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
answered yesterday
Mr.Wizard♦Mr.Wizard
230k294741038
230k294741038
add a comment |
add a comment |
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