Paint Formula , Finding weight? [closed]












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$begingroup$


I have the following colors and each one have it is own weight , I have all the required information about each color but unfortunately I can't find the paint weight for each one could anyone please help me with that ?



You can see the in the attachment images what the value of weight I need.



In first Image you can see that the weight for color C010 = 1279.86



I need to find this weight from the given information in the second image.



What I need to achieve



What I have










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closed as unclear what you're asking by Yanko, amWhy, JMoravitz, Abcd, Cesareo Jan 6 at 14:43


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    $begingroup$
    I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
    $endgroup$
    – Ross Millikan
    Jan 5 at 14:59










  • $begingroup$
    @RossMillikan updated my question
    $endgroup$
    – Omarj
    Jan 6 at 6:42










  • $begingroup$
    @RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
    $endgroup$
    – Omarj
    Jan 7 at 11:22
















-3












$begingroup$


I have the following colors and each one have it is own weight , I have all the required information about each color but unfortunately I can't find the paint weight for each one could anyone please help me with that ?



You can see the in the attachment images what the value of weight I need.



In first Image you can see that the weight for color C010 = 1279.86



I need to find this weight from the given information in the second image.



What I need to achieve



What I have










share|cite|improve this question











$endgroup$



closed as unclear what you're asking by Yanko, amWhy, JMoravitz, Abcd, Cesareo Jan 6 at 14:43


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.











  • 2




    $begingroup$
    I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
    $endgroup$
    – Ross Millikan
    Jan 5 at 14:59










  • $begingroup$
    @RossMillikan updated my question
    $endgroup$
    – Omarj
    Jan 6 at 6:42










  • $begingroup$
    @RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
    $endgroup$
    – Omarj
    Jan 7 at 11:22














-3












-3








-3





$begingroup$


I have the following colors and each one have it is own weight , I have all the required information about each color but unfortunately I can't find the paint weight for each one could anyone please help me with that ?



You can see the in the attachment images what the value of weight I need.



In first Image you can see that the weight for color C010 = 1279.86



I need to find this weight from the given information in the second image.



What I need to achieve



What I have










share|cite|improve this question











$endgroup$




I have the following colors and each one have it is own weight , I have all the required information about each color but unfortunately I can't find the paint weight for each one could anyone please help me with that ?



You can see the in the attachment images what the value of weight I need.



In first Image you can see that the weight for color C010 = 1279.86



I need to find this weight from the given information in the second image.



What I need to achieve



What I have







algebra-precalculus arithmetic data-analysis






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 7 at 14:53









Ross Millikan

293k23197371




293k23197371










asked Jan 5 at 14:05









OmarjOmarj

952




952




closed as unclear what you're asking by Yanko, amWhy, JMoravitz, Abcd, Cesareo Jan 6 at 14:43


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.






closed as unclear what you're asking by Yanko, amWhy, JMoravitz, Abcd, Cesareo Jan 6 at 14:43


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.










  • 2




    $begingroup$
    I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
    $endgroup$
    – Ross Millikan
    Jan 5 at 14:59










  • $begingroup$
    @RossMillikan updated my question
    $endgroup$
    – Omarj
    Jan 6 at 6:42










  • $begingroup$
    @RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
    $endgroup$
    – Omarj
    Jan 7 at 11:22














  • 2




    $begingroup$
    I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
    $endgroup$
    – Ross Millikan
    Jan 5 at 14:59










  • $begingroup$
    @RossMillikan updated my question
    $endgroup$
    – Omarj
    Jan 6 at 6:42










  • $begingroup$
    @RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
    $endgroup$
    – Omarj
    Jan 7 at 11:22








2




2




$begingroup$
I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
$endgroup$
– Ross Millikan
Jan 5 at 14:59




$begingroup$
I don't understand the question at all. Th weight of each paint is given in the second table. There is a lot of extraneous information here, but no description of what you are trying to do.
$endgroup$
– Ross Millikan
Jan 5 at 14:59












$begingroup$
@RossMillikan updated my question
$endgroup$
– Omarj
Jan 6 at 6:42




$begingroup$
@RossMillikan updated my question
$endgroup$
– Omarj
Jan 6 at 6:42












$begingroup$
@RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
$endgroup$
– Omarj
Jan 7 at 11:22




$begingroup$
@RossMillikan if you have suggestion for Tags , could you please edit the tags for this question.
$endgroup$
– Omarj
Jan 7 at 11:22










1 Answer
1






active

oldest

votes


















0












$begingroup$

I don't see where you get the $1310$ grams/liter. The relative weights just come from each component's ratio out of the total, so for example
$$frac {77.3809}{77.8309+0.03189+0.15949+1.67464}cdot 1310.54=1279.86$$ within rounding. If you are just trying to mix paint for a car, I would guess to use $1.3$ kg/liter and these ratios to get the amount of each.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
    $endgroup$
    – Omarj
    Jan 7 at 11:21


















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0












$begingroup$

I don't see where you get the $1310$ grams/liter. The relative weights just come from each component's ratio out of the total, so for example
$$frac {77.3809}{77.8309+0.03189+0.15949+1.67464}cdot 1310.54=1279.86$$ within rounding. If you are just trying to mix paint for a car, I would guess to use $1.3$ kg/liter and these ratios to get the amount of each.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
    $endgroup$
    – Omarj
    Jan 7 at 11:21
















0












$begingroup$

I don't see where you get the $1310$ grams/liter. The relative weights just come from each component's ratio out of the total, so for example
$$frac {77.3809}{77.8309+0.03189+0.15949+1.67464}cdot 1310.54=1279.86$$ within rounding. If you are just trying to mix paint for a car, I would guess to use $1.3$ kg/liter and these ratios to get the amount of each.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
    $endgroup$
    – Omarj
    Jan 7 at 11:21














0












0








0





$begingroup$

I don't see where you get the $1310$ grams/liter. The relative weights just come from each component's ratio out of the total, so for example
$$frac {77.3809}{77.8309+0.03189+0.15949+1.67464}cdot 1310.54=1279.86$$ within rounding. If you are just trying to mix paint for a car, I would guess to use $1.3$ kg/liter and these ratios to get the amount of each.






share|cite|improve this answer









$endgroup$



I don't see where you get the $1310$ grams/liter. The relative weights just come from each component's ratio out of the total, so for example
$$frac {77.3809}{77.8309+0.03189+0.15949+1.67464}cdot 1310.54=1279.86$$ within rounding. If you are just trying to mix paint for a car, I would guess to use $1.3$ kg/liter and these ratios to get the amount of each.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jan 6 at 14:32









Ross MillikanRoss Millikan

293k23197371




293k23197371












  • $begingroup$
    Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
    $endgroup$
    – Omarj
    Jan 7 at 11:21


















  • $begingroup$
    Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
    $endgroup$
    – Omarj
    Jan 7 at 11:21
















$begingroup$
Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
$endgroup$
– Omarj
Jan 7 at 11:21




$begingroup$
Thank you for helping me here , But It seems I did not make it clear , I don't have the Total weight.
$endgroup$
– Omarj
Jan 7 at 11:21



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