Differentiation of inverse trigonometric functions
I am unable to get this sum.
Find dy/dx.
Question
y = arcsin(x.(1-x)^(1/2) - (x)^(1/2).(1-(x^2))^(1/2) )
In the answer key that I have, it has been directly simplified to: [ arcsinx - arcsin(rt x) ] (I am unable to understand how this was obtained). and then it has been differentiated.
derivatives
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I am unable to get this sum.
Find dy/dx.
Question
y = arcsin(x.(1-x)^(1/2) - (x)^(1/2).(1-(x^2))^(1/2) )
In the answer key that I have, it has been directly simplified to: [ arcsinx - arcsin(rt x) ] (I am unable to understand how this was obtained). and then it has been differentiated.
derivatives
asked yesterday
user329952
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday
add a comment |
I am unable to get this sum.
Find dy/dx.
Question
y = arcsin(x.(1-x)^(1/2) - (x)^(1/2).(1-(x^2))^(1/2) )
In the answer key that I have, it has been directly simplified to: [ arcsinx - arcsin(rt x) ] (I am unable to understand how this was obtained). and then it has been differentiated.
derivatives
asked yesterday
user329952
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am unable to get this sum.
Find dy/dx.
Question
y = arcsin(x.(1-x)^(1/2) - (x)^(1/2).(1-(x^2))^(1/2) )
In the answer key that I have, it has been directly simplified to: [ arcsinx - arcsin(rt x) ] (I am unable to understand how this was obtained). and then it has been differentiated.
derivatives
derivatives
asked yesterday
user329952
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
user329952
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
user329952
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
user329952
1
asked yesterday
user329952
1
1
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
user329952 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday
add a comment |
Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday
Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday
Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday
add a comment |
1 Answer
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HINT: Use the chain rule $$frac{d}{dx} f(g(x))=g'(x)f'(g(x))$$ with $f(x)=arcsin(x)$ and $g(x)=xsqrt{1-x}-sqrt{x(1-x^2)}$. You can use the product rule to differentiate $g(x)$.
answered yesterday
aleden
1,725411
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1 Answer
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1 Answer
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HINT: Use the chain rule $$frac{d}{dx} f(g(x))=g'(x)f'(g(x))$$ with $f(x)=arcsin(x)$ and $g(x)=xsqrt{1-x}-sqrt{x(1-x^2)}$. You can use the product rule to differentiate $g(x)$.
answered yesterday
aleden
1,725411
add a comment |
HINT: Use the chain rule $$frac{d}{dx} f(g(x))=g'(x)f'(g(x))$$ with $f(x)=arcsin(x)$ and $g(x)=xsqrt{1-x}-sqrt{x(1-x^2)}$. You can use the product rule to differentiate $g(x)$.
answered yesterday
aleden
1,725411
add a comment |
HINT: Use the chain rule $$frac{d}{dx} f(g(x))=g'(x)f'(g(x))$$ with $f(x)=arcsin(x)$ and $g(x)=xsqrt{1-x}-sqrt{x(1-x^2)}$. You can use the product rule to differentiate $g(x)$.
answered yesterday
aleden
1,725411
HINT: Use the chain rule $$frac{d}{dx} f(g(x))=g'(x)f'(g(x))$$ with $f(x)=arcsin(x)$ and $g(x)=xsqrt{1-x}-sqrt{x(1-x^2)}$. You can use the product rule to differentiate $g(x)$.
answered yesterday
aleden
1,725411
answered yesterday
aleden
1,725411
answered yesterday
aleden
1,725411
answered yesterday
aleden
1,725411
1,725411
add a comment |
add a comment |
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Use math.stackexchange.com/questions/672575/… and math.stackexchange.com/questions/2099342/…
– lab bhattacharjee
yesterday