Replacing function, how to use + as delimiter












4














I am using a function for summing numbers like in paper and my input at arguments is like this:
showsum{123+456}



I need to replace the custom function with other from package xlop - opadd.
I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?



documentclass{article}

usepackage{xlop}

usepackage{amsmath}

 usepackage{setspace}

newcommand{showsum}[2][c]{%

    $edeforiginalplusmathcode{themathcode`+}%

    begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%

    edeforiginalminusmathcode{themathcode`-}%

    begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%

    mathcode`+ "8000

    mathcode`- "8000

    begin{array}[#1]{@{}r@{;}r@{}}

    & #2 \

    hline

    & thenumexpr#2relax

    end{array}%

    $%

}



begin{document}

 Original function(don't need anymore)showsum{123+456}

 \

 \

 Replacement needed opadd{123}{456}



end{document}





delimiters







share|improve this question



























    4














    I am using a function for summing numbers like in paper and my input at arguments is like this:
    showsum{123+456}



    I need to replace the custom function with other from package xlop - opadd.
    I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?



    documentclass{article}
    
usepackage{xlop}
    
usepackage{amsmath}
    
 usepackage{setspace}
    
newcommand{showsum}[2][c]{%
    
    $edeforiginalplusmathcode{themathcode`+}%
    
    begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
    
    edeforiginalminusmathcode{themathcode`-}%
    
    begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
    
    mathcode`+ "8000
    
    mathcode`- "8000
    
    begin{array}[#1]{@{}r@{;}r@{}}
    
    & #2 \
    
    hline
    
    & thenumexpr#2relax
    
    end{array}%
    
    $%
    
}
    

    
begin{document}
    
 Original function(don't need anymore)showsum{123+456}
    
 \
    
 \
    
 Replacement needed opadd{123}{456}
    

    
end{document}





    delimiters







    share|improve this question

























      4












      4








      4







      I am using a function for summing numbers like in paper and my input at arguments is like this:
      showsum{123+456}



      I need to replace the custom function with other from package xlop - opadd.
      I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?



      documentclass{article}
      
usepackage{xlop}
      
usepackage{amsmath}
      
 usepackage{setspace}
      
newcommand{showsum}[2][c]{%
      
    $edeforiginalplusmathcode{themathcode`+}%
      
    begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
      
    edeforiginalminusmathcode{themathcode`-}%
      
    begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
      
    mathcode`+ "8000
      
    mathcode`- "8000
      
    begin{array}[#1]{@{}r@{;}r@{}}
      
    & #2 \
      
    hline
      
    & thenumexpr#2relax
      
    end{array}%
      
    $%
      
}
      

      
begin{document}
      
 Original function(don't need anymore)showsum{123+456}
      
 \
      
 \
      
 Replacement needed opadd{123}{456}
      

      
end{document}





      delimiters







      share|improve this question













      I am using a function for summing numbers like in paper and my input at arguments is like this:
      showsum{123+456}



      I need to replace the custom function with other from package xlop - opadd.
      I want the same function name but there are 2 separated arguments in opadd and I want to use {123+456} for opadd arguments. How to make this delimiter?



      documentclass{article}
      
usepackage{xlop}
      
usepackage{amsmath}
      
 usepackage{setspace}
      
newcommand{showsum}[2][c]{%
      
    $edeforiginalplusmathcode{themathcode`+}%
      
    begingrouplccode`~=`+ lowercase{endgroupdef~}{\mathcharoriginalplusmathcode&}%
      
    edeforiginalminusmathcode{themathcode`-}%
      
    begingrouplccode`~=`- lowercase{endgroupdef~}{\mathcharoriginalminusmathcode&}%
      
    mathcode`+ "8000
      
    mathcode`- "8000
      
    begin{array}[#1]{@{}r@{;}r@{}}
      
    & #2 \
      
    hline
      
    & thenumexpr#2relax
      
    end{array}%
      
    $%
      
}
      

      
begin{document}
      
 Original function(don't need anymore)showsum{123+456}
      
 \
      
 \
      
 Replacement needed opadd{123}{456}
      

      
end{document}





      delimiters




      delimiters






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked yesterday









      Simeon SimeonovSimeon Simeonov

      3306




      3306






















          1 Answer
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          oldest

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          7














          You can use a macro with delimited arguments:



          documentclass{article}
          
usepackage{xlop}
          

          
newcommand{showsum}[1]{doshowsum#1doshowsum}
          
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
          

          
begin{document}
          

          
showsum{123+456} qquad opadd{123}{456}
          

          
end{document}


          enter image description here



          You can also support subtraction:



          documentclass{article}
          
usepackage{xparse}
          
usepackage{xlop}
          

          
ExplSyntaxOn
          
NewDocumentCommand{showsum}{m}
          
 {
          
  regex_match:nnTF { + } { #1 }
          
   {
          
    simeon_showsum:nnn { #1 } { + } { opadd }
          
   }
          
   {
          
    simeon_showsum:nnn { #1 } { - } { opsub }
          
   }
          
 }
          
cs_new_protected:Nn simeon_showsum:nnn
          
 {
          
  tl_set:Nn l_tmpa_tl { #1 }
          
  % remove all spaces
          
  regex_replace_all:nnN { s } { } l_tmpa_tl
          
  % replace <number>+<number> with opadd{<number>}{<number>} or
          
  % replace <number>-<number> with opsub{<number>}{<number>}
          
  regex_replace_once:nnN
          
   { A ([^#2]*) #2 (.*) Z }
          
   { c{#3}cB{1cE}cB{2cE} }
          
   l_tmpa_tl
          
  % deliver the result
          
  tl_use:N l_tmpa_tl
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          

          
showsum{123+456} qquad showsum{456-123}
          

          
end{document}


          enter image description here






          share|improve this answer























          • Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
            – Simeon Simeonov
            yesterday






          • 1




            @SimeonSimeonov I added removal of spaces
            – egreg
            yesterday











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          7














          You can use a macro with delimited arguments:



          documentclass{article}
          
usepackage{xlop}
          

          
newcommand{showsum}[1]{doshowsum#1doshowsum}
          
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
          

          
begin{document}
          

          
showsum{123+456} qquad opadd{123}{456}
          

          
end{document}


          enter image description here



          You can also support subtraction:



          documentclass{article}
          
usepackage{xparse}
          
usepackage{xlop}
          

          
ExplSyntaxOn
          
NewDocumentCommand{showsum}{m}
          
 {
          
  regex_match:nnTF { + } { #1 }
          
   {
          
    simeon_showsum:nnn { #1 } { + } { opadd }
          
   }
          
   {
          
    simeon_showsum:nnn { #1 } { - } { opsub }
          
   }
          
 }
          
cs_new_protected:Nn simeon_showsum:nnn
          
 {
          
  tl_set:Nn l_tmpa_tl { #1 }
          
  % remove all spaces
          
  regex_replace_all:nnN { s } { } l_tmpa_tl
          
  % replace <number>+<number> with opadd{<number>}{<number>} or
          
  % replace <number>-<number> with opsub{<number>}{<number>}
          
  regex_replace_once:nnN
          
   { A ([^#2]*) #2 (.*) Z }
          
   { c{#3}cB{1cE}cB{2cE} }
          
   l_tmpa_tl
          
  % deliver the result
          
  tl_use:N l_tmpa_tl
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          

          
showsum{123+456} qquad showsum{456-123}
          

          
end{document}


          enter image description here






          share|improve this answer























          • Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
            – Simeon Simeonov
            yesterday






          • 1




            @SimeonSimeonov I added removal of spaces
            – egreg
            yesterday
















          7














          You can use a macro with delimited arguments:



          documentclass{article}
          
usepackage{xlop}
          

          
newcommand{showsum}[1]{doshowsum#1doshowsum}
          
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
          

          
begin{document}
          

          
showsum{123+456} qquad opadd{123}{456}
          

          
end{document}


          enter image description here



          You can also support subtraction:



          documentclass{article}
          
usepackage{xparse}
          
usepackage{xlop}
          

          
ExplSyntaxOn
          
NewDocumentCommand{showsum}{m}
          
 {
          
  regex_match:nnTF { + } { #1 }
          
   {
          
    simeon_showsum:nnn { #1 } { + } { opadd }
          
   }
          
   {
          
    simeon_showsum:nnn { #1 } { - } { opsub }
          
   }
          
 }
          
cs_new_protected:Nn simeon_showsum:nnn
          
 {
          
  tl_set:Nn l_tmpa_tl { #1 }
          
  % remove all spaces
          
  regex_replace_all:nnN { s } { } l_tmpa_tl
          
  % replace <number>+<number> with opadd{<number>}{<number>} or
          
  % replace <number>-<number> with opsub{<number>}{<number>}
          
  regex_replace_once:nnN
          
   { A ([^#2]*) #2 (.*) Z }
          
   { c{#3}cB{1cE}cB{2cE} }
          
   l_tmpa_tl
          
  % deliver the result
          
  tl_use:N l_tmpa_tl
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          

          
showsum{123+456} qquad showsum{456-123}
          

          
end{document}


          enter image description here






          share|improve this answer























          • Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
            – Simeon Simeonov
            yesterday






          • 1




            @SimeonSimeonov I added removal of spaces
            – egreg
            yesterday














          7












          7








          7






          You can use a macro with delimited arguments:



          documentclass{article}
          
usepackage{xlop}
          

          
newcommand{showsum}[1]{doshowsum#1doshowsum}
          
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
          

          
begin{document}
          

          
showsum{123+456} qquad opadd{123}{456}
          

          
end{document}


          enter image description here



          You can also support subtraction:



          documentclass{article}
          
usepackage{xparse}
          
usepackage{xlop}
          

          
ExplSyntaxOn
          
NewDocumentCommand{showsum}{m}
          
 {
          
  regex_match:nnTF { + } { #1 }
          
   {
          
    simeon_showsum:nnn { #1 } { + } { opadd }
          
   }
          
   {
          
    simeon_showsum:nnn { #1 } { - } { opsub }
          
   }
          
 }
          
cs_new_protected:Nn simeon_showsum:nnn
          
 {
          
  tl_set:Nn l_tmpa_tl { #1 }
          
  % remove all spaces
          
  regex_replace_all:nnN { s } { } l_tmpa_tl
          
  % replace <number>+<number> with opadd{<number>}{<number>} or
          
  % replace <number>-<number> with opsub{<number>}{<number>}
          
  regex_replace_once:nnN
          
   { A ([^#2]*) #2 (.*) Z }
          
   { c{#3}cB{1cE}cB{2cE} }
          
   l_tmpa_tl
          
  % deliver the result
          
  tl_use:N l_tmpa_tl
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          

          
showsum{123+456} qquad showsum{456-123}
          

          
end{document}


          enter image description here






          share|improve this answer














          You can use a macro with delimited arguments:



          documentclass{article}
          
usepackage{xlop}
          

          
newcommand{showsum}[1]{doshowsum#1doshowsum}
          
defdoshowsum#1+#2doshowsum{opadd{#1}{#2}}
          

          
begin{document}
          

          
showsum{123+456} qquad opadd{123}{456}
          

          
end{document}


          enter image description here



          You can also support subtraction:



          documentclass{article}
          
usepackage{xparse}
          
usepackage{xlop}
          

          
ExplSyntaxOn
          
NewDocumentCommand{showsum}{m}
          
 {
          
  regex_match:nnTF { + } { #1 }
          
   {
          
    simeon_showsum:nnn { #1 } { + } { opadd }
          
   }
          
   {
          
    simeon_showsum:nnn { #1 } { - } { opsub }
          
   }
          
 }
          
cs_new_protected:Nn simeon_showsum:nnn
          
 {
          
  tl_set:Nn l_tmpa_tl { #1 }
          
  % remove all spaces
          
  regex_replace_all:nnN { s } { } l_tmpa_tl
          
  % replace <number>+<number> with opadd{<number>}{<number>} or
          
  % replace <number>-<number> with opsub{<number>}{<number>}
          
  regex_replace_once:nnN
          
   { A ([^#2]*) #2 (.*) Z }
          
   { c{#3}cB{1cE}cB{2cE} }
          
   l_tmpa_tl
          
  % deliver the result
          
  tl_use:N l_tmpa_tl
          
 }
          
ExplSyntaxOff
          

          
begin{document}
          

          
showsum{123+456} qquad showsum{456-123}
          

          
end{document}


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited yesterday

























          answered yesterday









          egregegreg

          710k8618883172




          710k8618883172












          • Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
            – Simeon Simeonov
            yesterday






          • 1




            @SimeonSimeonov I added removal of spaces
            – egreg
            yesterday


















          • Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
            – Simeon Simeonov
            yesterday






          • 1




            @SimeonSimeonov I added removal of spaces
            – egreg
            yesterday
















          Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
          – Simeon Simeonov
          yesterday




          Great! I needed subtraction aswell. I have new problem. My functions are showsum{123 + 456} with spaces between +/- and numbers. Is there any fast solution?
          – Simeon Simeonov
          yesterday




          1




          1




          @SimeonSimeonov I added removal of spaces
          – egreg
          yesterday




          @SimeonSimeonov I added removal of spaces
          – egreg
          yesterday


















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