Given $u$ and $v$ are functions of $x$ and $y$ and $ux=vy$, $u^2y=vx^2$, find $frac {partial u}{partial x}$
Given $u$ and $v$ are functions of $x$ and $y$ and $ux=vy$, $u^2y=vx^2$, find $frac {partial u}{partial x}$ and show that $$frac {partial v}{partial x}=frac{2v^2y^y+xv^2}{y(2uy^2-2vx^2)}$$
I have literally no idea on where to start with this question. Should I be substituting the two equations into each other. I thinking it has something to do with the chain rule?
derivatives partial-derivative
asked yesterday
H.Linkhorn
31212
add a comment |
Given $u$ and $v$ are functions of $x$ and $y$ and $ux=vy$, $u^2y=vx^2$, find $frac {partial u}{partial x}$ and show that $$frac {partial v}{partial x}=frac{2v^2y^y+xv^2}{y(2uy^2-2vx^2)}$$
I have literally no idea on where to start with this question. Should I be substituting the two equations into each other. I thinking it has something to do with the chain rule?
derivatives partial-derivative
asked yesterday
H.Linkhorn
31212
Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday
add a comment |
Given $u$ and $v$ are functions of $x$ and $y$ and $ux=vy$, $u^2y=vx^2$, find $frac {partial u}{partial x}$ and show that $$frac {partial v}{partial x}=frac{2v^2y^y+xv^2}{y(2uy^2-2vx^2)}$$
I have literally no idea on where to start with this question. Should I be substituting the two equations into each other. I thinking it has something to do with the chain rule?
derivatives partial-derivative
asked yesterday
H.Linkhorn
31212
Given $u$ and $v$ are functions of $x$ and $y$ and $ux=vy$, $u^2y=vx^2$, find $frac {partial u}{partial x}$ and show that $$frac {partial v}{partial x}=frac{2v^2y^y+xv^2}{y(2uy^2-2vx^2)}$$
I have literally no idea on where to start with this question. Should I be substituting the two equations into each other. I thinking it has something to do with the chain rule?
derivatives partial-derivative
derivatives partial-derivative
asked yesterday
H.Linkhorn
31212
asked yesterday
H.Linkhorn
31212
asked yesterday
H.Linkhorn
31212
asked yesterday
H.Linkhorn
31212
asked yesterday
H.Linkhorn
31212
31212
Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday
add a comment |
Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday
Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday
Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday
add a comment |
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Differentiate the two relations $ux=vy$, $u^2y=vx^2$ about $x$, and you will get two equations of $u_x$ and $v_x$. Then solve them.
– W. mu
yesterday