How can I replace division sign with slash in ticks of BarLegend
4
$begingroup$
I am plotting a Bar legend for the density plot using BarLegend. I got the desired bar legend but it has ticks in the form $frac{pi}{6},~frac{pi}{3},..$, I want them to be like $pi/6,~pi/3,...$ I want to write the division using slash. How can I do this in mathematica.
The code I am using is:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> {π/6, π/3, π/2, 2 π/3}]
plotting legending
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
4
$begingroup$
I am plotting a Bar legend for the density plot using BarLegend. I got the desired bar legend but it has ticks in the form $frac{pi}{6},~frac{pi}{3},..$, I want them to be like $pi/6,~pi/3,...$ I want to write the division using slash. How can I do this in mathematica.
The code I am using is:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> {π/6, π/3, π/2, 2 π/3}]
plotting legending
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
3
$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something likeFormatType->StandardForm!
$endgroup$
– Carl Lange
Jan 21 at 13:54
add a comment |
4
4
4
$begingroup$
I am plotting a Bar legend for the density plot using BarLegend. I got the desired bar legend but it has ticks in the form $frac{pi}{6},~frac{pi}{3},..$, I want them to be like $pi/6,~pi/3,...$ I want to write the division using slash. How can I do this in mathematica.
The code I am using is:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> {π/6, π/3, π/2, 2 π/3}]
plotting legending
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am plotting a Bar legend for the density plot using BarLegend. I got the desired bar legend but it has ticks in the form $frac{pi}{6},~frac{pi}{3},..$, I want them to be like $pi/6,~pi/3,...$ I want to write the division using slash. How can I do this in mathematica.
The code I am using is:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> {π/6, π/3, π/2, 2 π/3}]
plotting legending
plotting legending
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
edited Jan 21 at 16:03
Henrik Schumacher
51.2k469146
51.2k469146
asked Jan 21 at 13:18
ParveenParveen
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 21 at 13:18
ParveenParveen
355
asked Jan 21 at 13:18
ParveenParveen
355
355
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Parveen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something likeFormatType->StandardForm!
$endgroup$
– Carl Lange
Jan 21 at 13:54
add a comment |
3
$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something likeFormatType->StandardForm!
$endgroup$
– Carl Lange
Jan 21 at 13:54
3
3
$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something like
FormatType->StandardForm!$endgroup$
– Carl Lange
Jan 21 at 13:54
$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something like
FormatType->StandardForm!$endgroup$
– Carl Lange
Jan 21 at 13:54
add a comment |
2 Answers
2
active
oldest
votes
5
$begingroup$
ticks = {π/6, π/3, π/2, 2 π/3};
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
"Ticks" -> Transpose[{#, # /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]} &@
ticks}],
LegendMarkerSize -> {30, 300}]
Alternatively, add the option "TickLabels":
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False, "Ticks" -> ticks,
"TickLabels" -> (ticks /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]),
LegendMarkerSize -> {30, 300}]
answered Jan 21 at 14:42
kglrkglr
181k9200413
$endgroup$
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
|
show 4 more comments
4
$begingroup$
Something like this will work:
BarLegend[{
Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1, 2 [Pi]/3 + .1}
},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> ({#, InputForm@#} & /@ {[Pi]/6, [Pi]/3, [Pi]/2,
2 [Pi]/3})]
The idea is to pass a list like {{x1,label1},{x2,label2}...} to Ticks.
Since it seems like you know exactly what you want to put into your ticks, you could just put strings:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1,
2 [Pi]/3 + .1}},
LabelStyle ->
Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks ->
Transpose[{{[Pi]/6, [Pi]/3, [Pi]/2, 2 [Pi]/3}, {"[Pi]/6",
"[Pi]/3", "[Pi]/2", "2[Pi]/3"}}]]
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
$endgroup$
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
$begingroup$
ticks = {π/6, π/3, π/2, 2 π/3};
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
"Ticks" -> Transpose[{#, # /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]} &@
ticks}],
LegendMarkerSize -> {30, 300}]
Alternatively, add the option "TickLabels":
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False, "Ticks" -> ticks,
"TickLabels" -> (ticks /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]),
LegendMarkerSize -> {30, 300}]
answered Jan 21 at 14:42
kglrkglr
181k9200413
$endgroup$
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
|
show 4 more comments
5
$begingroup$
ticks = {π/6, π/3, π/2, 2 π/3};
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
"Ticks" -> Transpose[{#, # /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]} &@
ticks}],
LegendMarkerSize -> {30, 300}]
Alternatively, add the option "TickLabels":
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False, "Ticks" -> ticks,
"TickLabels" -> (ticks /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]),
LegendMarkerSize -> {30, 300}]
answered Jan 21 at 14:42
kglrkglr
181k9200413
$endgroup$
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
|
show 4 more comments
5
5
5
$begingroup$
ticks = {π/6, π/3, π/2, 2 π/3};
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
"Ticks" -> Transpose[{#, # /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]} &@
ticks}],
LegendMarkerSize -> {30, 300}]
Alternatively, add the option "TickLabels":
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False, "Ticks" -> ticks,
"TickLabels" -> (ticks /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]),
LegendMarkerSize -> {30, 300}]
answered Jan 21 at 14:42
kglrkglr
181k9200413
$endgroup$
ticks = {π/6, π/3, π/2, 2 π/3};
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
"Ticks" -> Transpose[{#, # /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]} &@
ticks}],
LegendMarkerSize -> {30, 300}]
Alternatively, add the option "TickLabels":
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {π/6 - .1, 2 π/3 + .1}},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False, "Ticks" -> ticks,
"TickLabels" -> (ticks /. Times[Rational[a_, b_], Pi] :> Row[{a Pi, "/", b}]),
LegendMarkerSize -> {30, 300}]
answered Jan 21 at 14:42
kglrkglr
181k9200413
edited Jan 21 at 15:07
answered Jan 21 at 14:42
kglrkglr
181k9200413
answered Jan 21 at 14:42
kglrkglr
181k9200413
answered Jan 21 at 14:42
kglrkglr
181k9200413
181k9200413
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
|
show 4 more comments
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
Thanks for the answer. Something strange happened. I did copy and paste your code into my mathematica 11 and the ticks got interchanged. However I got the plot as you got but in my case $pi/6$ appears instead of $pi/2$. I don't know why!
$endgroup$
– Parveen
Jan 21 at 14:51
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
@Parveen, it could be related to version/os. I am using version 11.3 (windows 10).
$endgroup$
– kglr
Jan 21 at 14:57
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
Seems so. I am using ubuntu and mathematica 11
$endgroup$
– Parveen
Jan 21 at 15:00
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
@Parveen, mathematica 11.3 or an earlier version?
$endgroup$
– kglr
Jan 21 at 15:01
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
$begingroup$
11.1.0.0 version
$endgroup$
– Parveen
Jan 21 at 15:02
|
show 4 more comments
4
$begingroup$
Something like this will work:
BarLegend[{
Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1, 2 [Pi]/3 + .1}
},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> ({#, InputForm@#} & /@ {[Pi]/6, [Pi]/3, [Pi]/2,
2 [Pi]/3})]
The idea is to pass a list like {{x1,label1},{x2,label2}...} to Ticks.
Since it seems like you know exactly what you want to put into your ticks, you could just put strings:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1,
2 [Pi]/3 + .1}},
LabelStyle ->
Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks ->
Transpose[{{[Pi]/6, [Pi]/3, [Pi]/2, 2 [Pi]/3}, {"[Pi]/6",
"[Pi]/3", "[Pi]/2", "2[Pi]/3"}}]]
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
$endgroup$
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
add a comment |
4
$begingroup$
Something like this will work:
BarLegend[{
Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1, 2 [Pi]/3 + .1}
},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> ({#, InputForm@#} & /@ {[Pi]/6, [Pi]/3, [Pi]/2,
2 [Pi]/3})]
The idea is to pass a list like {{x1,label1},{x2,label2}...} to Ticks.
Since it seems like you know exactly what you want to put into your ticks, you could just put strings:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1,
2 [Pi]/3 + .1}},
LabelStyle ->
Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks ->
Transpose[{{[Pi]/6, [Pi]/3, [Pi]/2, 2 [Pi]/3}, {"[Pi]/6",
"[Pi]/3", "[Pi]/2", "2[Pi]/3"}}]]
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
$endgroup$
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
add a comment |
4
4
4
$begingroup$
Something like this will work:
BarLegend[{
Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1, 2 [Pi]/3 + .1}
},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> ({#, InputForm@#} & /@ {[Pi]/6, [Pi]/3, [Pi]/2,
2 [Pi]/3})]
The idea is to pass a list like {{x1,label1},{x2,label2}...} to Ticks.
Since it seems like you know exactly what you want to put into your ticks, you could just put strings:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1,
2 [Pi]/3 + .1}},
LabelStyle ->
Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks ->
Transpose[{{[Pi]/6, [Pi]/3, [Pi]/2, 2 [Pi]/3}, {"[Pi]/6",
"[Pi]/3", "[Pi]/2", "2[Pi]/3"}}]]
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
$endgroup$
Something like this will work:
BarLegend[{
Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1, 2 [Pi]/3 + .1}
},
LabelStyle -> Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks -> ({#, InputForm@#} & /@ {[Pi]/6, [Pi]/3, [Pi]/2,
2 [Pi]/3})]
The idea is to pass a list like {{x1,label1},{x2,label2}...} to Ticks.
Since it seems like you know exactly what you want to put into your ticks, you could just put strings:
BarLegend[{Hue[Rescale[#, {0, Pi}, {0, 1}]] &, {[Pi]/6 - .1,
2 [Pi]/3 + .1}},
LabelStyle ->
Directive[Black, Bold, Medium, FontFamily -> "Courier"],
ColorFunctionScaling -> False,
Ticks ->
Transpose[{{[Pi]/6, [Pi]/3, [Pi]/2, 2 [Pi]/3}, {"[Pi]/6",
"[Pi]/3", "[Pi]/2", "2[Pi]/3"}}]]
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
edited Jan 21 at 15:10
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
answered Jan 21 at 14:45
Carl LangeCarl Lange
3,3401731
3,3401731
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
add a comment |
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
Seems correct but I want $pi$ instead of $Pi$ and the upper most tick should be $2pi/3$ instead of $2*Pi/3$. If you can modify it, then it would be a great help
$endgroup$
– Parveen
Jan 21 at 14:53
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
@Parveen Check my latest edit.
$endgroup$
– Carl Lange
Jan 21 at 15:10
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Thanks. It works now
$endgroup$
– Parveen
Jan 21 at 15:12
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
$begingroup$
Consider marking the answer (or @kglr's answer, which is at least as good as mine) as accepted if it solved your problem!
$endgroup$
– Carl Lange
Jan 21 at 15:22
add a comment |
Parveen is a new contributor. Be nice, and check out our Code of Conduct.
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Parveen is a new contributor. Be nice, and check out our Code of Conduct.
Parveen is a new contributor. Be nice, and check out our Code of Conduct.
Parveen is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Hi Parveen, welcome to MMA.SE! Please consider adding some code to your question - it really helps us help you if we can quickly reproduce your results. I'm pretty sure you want something like
FormatType->StandardForm!$endgroup$
– Carl Lange
Jan 21 at 13:54