3D geometry, what are the coordinates of the 4th vertex and the point of intersection of this trapezoid?
3 Vertex of the trapezoid are given : A(4,-1,2) B(7,1,-3) D(0,-4,6) and we know that AB and CD are parallel, and CD=2AB (opposite vertices are B-D and A-C)
The question is : what are the coordinates of vertex C, and what are the coordinates of the point of intersection of the diagonals?
Thank you!
geometry 3d
New contributor
add a comment |
3 Vertex of the trapezoid are given : A(4,-1,2) B(7,1,-3) D(0,-4,6) and we know that AB and CD are parallel, and CD=2AB (opposite vertices are B-D and A-C)
The question is : what are the coordinates of vertex C, and what are the coordinates of the point of intersection of the diagonals?
Thank you!
geometry 3d
New contributor
What have you tried?
– YiFan
Jan 4 at 12:04
add a comment |
3 Vertex of the trapezoid are given : A(4,-1,2) B(7,1,-3) D(0,-4,6) and we know that AB and CD are parallel, and CD=2AB (opposite vertices are B-D and A-C)
The question is : what are the coordinates of vertex C, and what are the coordinates of the point of intersection of the diagonals?
Thank you!
geometry 3d
New contributor
3 Vertex of the trapezoid are given : A(4,-1,2) B(7,1,-3) D(0,-4,6) and we know that AB and CD are parallel, and CD=2AB (opposite vertices are B-D and A-C)
The question is : what are the coordinates of vertex C, and what are the coordinates of the point of intersection of the diagonals?
Thank you!
geometry 3d
geometry 3d
New contributor
New contributor
edited Jan 4 at 11:54
20190104
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asked Jan 4 at 11:43
2019010420190104
11
11
New contributor
New contributor
What have you tried?
– YiFan
Jan 4 at 12:04
add a comment |
What have you tried?
– YiFan
Jan 4 at 12:04
What have you tried?
– YiFan
Jan 4 at 12:04
What have you tried?
– YiFan
Jan 4 at 12:04
add a comment |
2 Answers
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Hint: From parallelism, $vec{AB} = kvec{CD}$ for some negative $k$. Find $k$; so $1/k(B-A) + D = C$. To get the intersection of the diagonals, look at the lines $t(C - A)$ and $r(D-B)$ and their intersection.
add a comment |
Let $$C[x_C,y_C,z_c]$$ then $$2[0-x_C,-4-y_C,6-z_C]=[7-4,1+1,-3-2]$$ Can you solve this?
You will get $$-2x_C=3,-8-2y_C=2,12-2z_C=-5$$
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
add a comment |
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2 Answers
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Hint: From parallelism, $vec{AB} = kvec{CD}$ for some negative $k$. Find $k$; so $1/k(B-A) + D = C$. To get the intersection of the diagonals, look at the lines $t(C - A)$ and $r(D-B)$ and their intersection.
add a comment |
Hint: From parallelism, $vec{AB} = kvec{CD}$ for some negative $k$. Find $k$; so $1/k(B-A) + D = C$. To get the intersection of the diagonals, look at the lines $t(C - A)$ and $r(D-B)$ and their intersection.
add a comment |
Hint: From parallelism, $vec{AB} = kvec{CD}$ for some negative $k$. Find $k$; so $1/k(B-A) + D = C$. To get the intersection of the diagonals, look at the lines $t(C - A)$ and $r(D-B)$ and their intersection.
Hint: From parallelism, $vec{AB} = kvec{CD}$ for some negative $k$. Find $k$; so $1/k(B-A) + D = C$. To get the intersection of the diagonals, look at the lines $t(C - A)$ and $r(D-B)$ and their intersection.
edited Jan 4 at 12:15
answered Jan 4 at 12:00
Lucas HenriqueLucas Henrique
968414
968414
add a comment |
add a comment |
Let $$C[x_C,y_C,z_c]$$ then $$2[0-x_C,-4-y_C,6-z_C]=[7-4,1+1,-3-2]$$ Can you solve this?
You will get $$-2x_C=3,-8-2y_C=2,12-2z_C=-5$$
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
add a comment |
Let $$C[x_C,y_C,z_c]$$ then $$2[0-x_C,-4-y_C,6-z_C]=[7-4,1+1,-3-2]$$ Can you solve this?
You will get $$-2x_C=3,-8-2y_C=2,12-2z_C=-5$$
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
add a comment |
Let $$C[x_C,y_C,z_c]$$ then $$2[0-x_C,-4-y_C,6-z_C]=[7-4,1+1,-3-2]$$ Can you solve this?
You will get $$-2x_C=3,-8-2y_C=2,12-2z_C=-5$$
Let $$C[x_C,y_C,z_c]$$ then $$2[0-x_C,-4-y_C,6-z_C]=[7-4,1+1,-3-2]$$ Can you solve this?
You will get $$-2x_C=3,-8-2y_C=2,12-2z_C=-5$$
edited Jan 4 at 12:54
answered Jan 4 at 12:02
Dr. Sonnhard GraubnerDr. Sonnhard Graubner
73.5k42865
73.5k42865
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
add a comment |
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Thank you, and from the 4 vertices how can i get the point of intersection of the diagonals?
– 20190104
Jan 4 at 12:20
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
Should i post you the solution?
– Dr. Sonnhard Graubner
Jan 4 at 12:21
i would appreciate that!
– 20190104
Jan 4 at 12:23
i would appreciate that!
– 20190104
Jan 4 at 12:23
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
I got (14/3, -2/3, 0) for the intersection point. Is it right?
– 20190104
Jan 4 at 15:13
add a comment |
20190104 is a new contributor. Be nice, and check out our Code of Conduct.
20190104 is a new contributor. Be nice, and check out our Code of Conduct.
20190104 is a new contributor. Be nice, and check out our Code of Conduct.
20190104 is a new contributor. Be nice, and check out our Code of Conduct.
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What have you tried?
– YiFan
Jan 4 at 12:04