Find function $f:[0,1]to mathbb R$, whose set of discontinuities is such that $left{ frac{k}{2^n}; quad k,n...
Find function $fcolon[0,1]to mathbb R$, whose set of discontinuities is such that
$$left{frac{k}{2^n}; quad k,n in mathbb N, k le 2^nright }$$
I guess that it is Riemann function or something like that but I have no clue how it would look like
real-analysis continuity
add a comment |
Find function $fcolon[0,1]to mathbb R$, whose set of discontinuities is such that
$$left{frac{k}{2^n}; quad k,n in mathbb N, k le 2^nright }$$
I guess that it is Riemann function or something like that but I have no clue how it would look like
real-analysis continuity
The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago
add a comment |
Find function $fcolon[0,1]to mathbb R$, whose set of discontinuities is such that
$$left{frac{k}{2^n}; quad k,n in mathbb N, k le 2^nright }$$
I guess that it is Riemann function or something like that but I have no clue how it would look like
real-analysis continuity
Find function $fcolon[0,1]to mathbb R$, whose set of discontinuities is such that
$$left{frac{k}{2^n}; quad k,n in mathbb N, k le 2^nright }$$
I guess that it is Riemann function or something like that but I have no clue how it would look like
real-analysis continuity
real-analysis continuity
edited 2 days ago
Shaun
8,810113680
8,810113680
asked 2 days ago
math.trouble
566
566
The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago
add a comment |
The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago
The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago
The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago
add a comment |
1 Answer
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Let $f(x) = 0$ whenever $x$ is not a dyadic fraction, and $fleft(frac{k}{2^n}right) = 2^{-n}$.
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Let $f(x) = 0$ whenever $x$ is not a dyadic fraction, and $fleft(frac{k}{2^n}right) = 2^{-n}$.
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
add a comment |
Let $f(x) = 0$ whenever $x$ is not a dyadic fraction, and $fleft(frac{k}{2^n}right) = 2^{-n}$.
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
add a comment |
Let $f(x) = 0$ whenever $x$ is not a dyadic fraction, and $fleft(frac{k}{2^n}right) = 2^{-n}$.
Let $f(x) = 0$ whenever $x$ is not a dyadic fraction, and $fleft(frac{k}{2^n}right) = 2^{-n}$.
answered 2 days ago
MathematicsStudent1122
8,52122366
8,52122366
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
add a comment |
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
2
2
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
Might help to recognize that this is a modified Thomae's function.
– Robert Wolfe
2 days ago
add a comment |
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The set of discontinuities is dense in $[0,1]$. So I think that it might be like Weierstrass function.
– toric_actions
2 days ago