Determine the AV of 13 annual deposits of $1,429 one year after the last deposit, at 2.10% effective












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I got confused when calculating AV in this question.
Apparently the correct formula would be $1,429cdot 1.021 cdot frac{1.021^{13} - 1}{1.021 - 1}$. Or at least, this equals $21.511.03, which is supposed to be the correct answer. But when I was thinking of geometric series, don't we have $AV = 1,429 cdot 1.021 cdot (1 + 1.021 + ... + 1.021^{13}) = 1,429cdot 1.021 frac{1.021^{14} - 1}{1.021 - 1}$.
I just can't figure out why the formula with 14 is wrong. Any help would much be appreciated! Thank you :)










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    I got confused when calculating AV in this question.
    Apparently the correct formula would be $1,429cdot 1.021 cdot frac{1.021^{13} - 1}{1.021 - 1}$. Or at least, this equals $21.511.03, which is supposed to be the correct answer. But when I was thinking of geometric series, don't we have $AV = 1,429 cdot 1.021 cdot (1 + 1.021 + ... + 1.021^{13}) = 1,429cdot 1.021 frac{1.021^{14} - 1}{1.021 - 1}$.
    I just can't figure out why the formula with 14 is wrong. Any help would much be appreciated! Thank you :)










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      I got confused when calculating AV in this question.
      Apparently the correct formula would be $1,429cdot 1.021 cdot frac{1.021^{13} - 1}{1.021 - 1}$. Or at least, this equals $21.511.03, which is supposed to be the correct answer. But when I was thinking of geometric series, don't we have $AV = 1,429 cdot 1.021 cdot (1 + 1.021 + ... + 1.021^{13}) = 1,429cdot 1.021 frac{1.021^{14} - 1}{1.021 - 1}$.
      I just can't figure out why the formula with 14 is wrong. Any help would much be appreciated! Thank you :)










      share|cite|improve this question













      I got confused when calculating AV in this question.
      Apparently the correct formula would be $1,429cdot 1.021 cdot frac{1.021^{13} - 1}{1.021 - 1}$. Or at least, this equals $21.511.03, which is supposed to be the correct answer. But when I was thinking of geometric series, don't we have $AV = 1,429 cdot 1.021 cdot (1 + 1.021 + ... + 1.021^{13}) = 1,429cdot 1.021 frac{1.021^{14} - 1}{1.021 - 1}$.
      I just can't figure out why the formula with 14 is wrong. Any help would much be appreciated! Thank you :)







      finance actuarial-science






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      asked Jan 4 at 2:04









      quietkidquietkid

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          There are only $13$ deposits. Your sum clearly contains $14$ terms, which is why it cannot be correct.



          When we write the cash flow for the accumulated value, the final ($13^{rm th}$) deposit has had $1$ year to accumulate value. This much should be obvious. Then the $12^{rm th}$ deposit has had $2$ years, and so forth, so that the first deposit has had $13$ years to accumulate value. Consequently, the accumulated value of this first payment must be $1429(1.021)^{13}$. So not only do you have an extra deposit, you also have an extra year of interest accrued. The correct cash flow written out is
          $$1429 left( (1.021)^{13} + (1.021)^{12} + cdots + (1.021)^2 + (1.021) right).$$ After factoring out the common factor of $1.021$, and applying the formula for the sum of a geometric series, we get the claimed answer.






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          • Okay! Thank you :) that makes sense
            – quietkid
            Jan 4 at 3:02











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          There are only $13$ deposits. Your sum clearly contains $14$ terms, which is why it cannot be correct.



          When we write the cash flow for the accumulated value, the final ($13^{rm th}$) deposit has had $1$ year to accumulate value. This much should be obvious. Then the $12^{rm th}$ deposit has had $2$ years, and so forth, so that the first deposit has had $13$ years to accumulate value. Consequently, the accumulated value of this first payment must be $1429(1.021)^{13}$. So not only do you have an extra deposit, you also have an extra year of interest accrued. The correct cash flow written out is
          $$1429 left( (1.021)^{13} + (1.021)^{12} + cdots + (1.021)^2 + (1.021) right).$$ After factoring out the common factor of $1.021$, and applying the formula for the sum of a geometric series, we get the claimed answer.






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          • Okay! Thank you :) that makes sense
            – quietkid
            Jan 4 at 3:02
















          1














          There are only $13$ deposits. Your sum clearly contains $14$ terms, which is why it cannot be correct.



          When we write the cash flow for the accumulated value, the final ($13^{rm th}$) deposit has had $1$ year to accumulate value. This much should be obvious. Then the $12^{rm th}$ deposit has had $2$ years, and so forth, so that the first deposit has had $13$ years to accumulate value. Consequently, the accumulated value of this first payment must be $1429(1.021)^{13}$. So not only do you have an extra deposit, you also have an extra year of interest accrued. The correct cash flow written out is
          $$1429 left( (1.021)^{13} + (1.021)^{12} + cdots + (1.021)^2 + (1.021) right).$$ After factoring out the common factor of $1.021$, and applying the formula for the sum of a geometric series, we get the claimed answer.






          share|cite|improve this answer





















          • Okay! Thank you :) that makes sense
            – quietkid
            Jan 4 at 3:02














          1












          1








          1






          There are only $13$ deposits. Your sum clearly contains $14$ terms, which is why it cannot be correct.



          When we write the cash flow for the accumulated value, the final ($13^{rm th}$) deposit has had $1$ year to accumulate value. This much should be obvious. Then the $12^{rm th}$ deposit has had $2$ years, and so forth, so that the first deposit has had $13$ years to accumulate value. Consequently, the accumulated value of this first payment must be $1429(1.021)^{13}$. So not only do you have an extra deposit, you also have an extra year of interest accrued. The correct cash flow written out is
          $$1429 left( (1.021)^{13} + (1.021)^{12} + cdots + (1.021)^2 + (1.021) right).$$ After factoring out the common factor of $1.021$, and applying the formula for the sum of a geometric series, we get the claimed answer.






          share|cite|improve this answer












          There are only $13$ deposits. Your sum clearly contains $14$ terms, which is why it cannot be correct.



          When we write the cash flow for the accumulated value, the final ($13^{rm th}$) deposit has had $1$ year to accumulate value. This much should be obvious. Then the $12^{rm th}$ deposit has had $2$ years, and so forth, so that the first deposit has had $13$ years to accumulate value. Consequently, the accumulated value of this first payment must be $1429(1.021)^{13}$. So not only do you have an extra deposit, you also have an extra year of interest accrued. The correct cash flow written out is
          $$1429 left( (1.021)^{13} + (1.021)^{12} + cdots + (1.021)^2 + (1.021) right).$$ After factoring out the common factor of $1.021$, and applying the formula for the sum of a geometric series, we get the claimed answer.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 4 at 2:09









          heropupheropup

          62.6k66099




          62.6k66099












          • Okay! Thank you :) that makes sense
            – quietkid
            Jan 4 at 3:02


















          • Okay! Thank you :) that makes sense
            – quietkid
            Jan 4 at 3:02
















          Okay! Thank you :) that makes sense
          – quietkid
          Jan 4 at 3:02




          Okay! Thank you :) that makes sense
          – quietkid
          Jan 4 at 3:02


















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