How to prove a class of elementary algebra? [on hold]
-4
It is known that m+n=x, mn=y, m,n∈Q,Prove that m, n∈Z if and only if x, y∈Z
algebra-precalculus group-theory elementary-number-theory
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by KReiser, Lord Shark the Unknown, max_zorn, Shaun, Hans Lundmark Jan 4 at 6:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KReiser, max_zorn, Shaun, Hans Lundmark
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
-4
It is known that m+n=x, mn=y, m,n∈Q,Prove that m, n∈Z if and only if x, y∈Z
algebra-precalculus group-theory elementary-number-theory
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by KReiser, Lord Shark the Unknown, max_zorn, Shaun, Hans Lundmark Jan 4 at 6:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KReiser, max_zorn, Shaun, Hans Lundmark
If this question can be reworded to fit the rules in the help center, please edit the question.
6
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
1
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23
add a comment |
-4
-4
-4
It is known that m+n=x, mn=y, m,n∈Q,Prove that m, n∈Z if and only if x, y∈Z
algebra-precalculus group-theory elementary-number-theory
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
It is known that m+n=x, mn=y, m,n∈Q,Prove that m, n∈Z if and only if x, y∈Z
algebra-precalculus group-theory elementary-number-theory
algebra-precalculus group-theory elementary-number-theory
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Jan 4 at 6:29
maks L
asked Jan 4 at 5:22
maks Lmaks L
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 4 at 5:22
maks Lmaks L
11
asked Jan 4 at 5:22
maks Lmaks L
11
11
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
maks L is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by KReiser, Lord Shark the Unknown, max_zorn, Shaun, Hans Lundmark Jan 4 at 6:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KReiser, max_zorn, Shaun, Hans Lundmark
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by KReiser, Lord Shark the Unknown, max_zorn, Shaun, Hans Lundmark Jan 4 at 6:38
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – KReiser, max_zorn, Shaun, Hans Lundmark
If this question can be reworded to fit the rules in the help center, please edit the question.
6
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
1
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23
add a comment |
6
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
1
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23
6
6
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
1
1
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23
add a comment |
0
active
oldest
votes
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
What about $m=sqrt2$, $n=-sqrt2$?
– Lord Shark the Unknown
Jan 4 at 5:29
1
What are the solutions to the quadratic $z^2-xz+y=(z-m)(z-n)=0$?
– Mark Bennet
Jan 4 at 5:52
z=m,n and m+n=x,mn=y
– maks L
Jan 4 at 6:13
Let $m,n=(1pmsqrt{5})/2$, then $x=m+n=1ne0$ and $y=mn=-1$.
– Alexander Burstein
Jan 4 at 6:13
Try $m,n=1pm sqrt{2}$. Then $x=2$ and $y=-1$
– Sauhard Sharma
Jan 4 at 6:23