Arithmetic question with distance speed and time
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If I have a time of departure with is 10:35 and I have an arrival time of 12:55 and the distance 36km how do I calculate average speed?
I get the formula of distance speed and time but it says the answer is 15 3/7 km/hr and I’m really confused on how it is.
arithmetic
edited Jan 7 at 17:21
David G. Stork
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
$endgroup$
|
show 9 more comments
$begingroup$
If I have a time of departure with is 10:35 and I have an arrival time of 12:55 and the distance 36km how do I calculate average speed?
I get the formula of distance speed and time but it says the answer is 15 3/7 km/hr and I’m really confused on how it is.
arithmetic
edited Jan 7 at 17:21
David G. Stork
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
$endgroup$
$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
1
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
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– KM101
Jan 7 at 17:09
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Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
1
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13
|
show 9 more comments
$begingroup$
If I have a time of departure with is 10:35 and I have an arrival time of 12:55 and the distance 36km how do I calculate average speed?
I get the formula of distance speed and time but it says the answer is 15 3/7 km/hr and I’m really confused on how it is.
arithmetic
edited Jan 7 at 17:21
David G. Stork
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
$endgroup$
If I have a time of departure with is 10:35 and I have an arrival time of 12:55 and the distance 36km how do I calculate average speed?
I get the formula of distance speed and time but it says the answer is 15 3/7 km/hr and I’m really confused on how it is.
arithmetic
arithmetic
edited Jan 7 at 17:21
David G. Stork
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
edited Jan 7 at 17:21
David G. Stork
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
edited Jan 7 at 17:21
David G. Stork
10.7k31332
edited Jan 7 at 17:21
David G. Stork
10.7k31332
edited Jan 7 at 17:21
David G. Stork
10.7k31332
10.7k31332
asked Jan 7 at 17:07
baek wonbaek won
11
asked Jan 7 at 17:07
baek wonbaek won
11
asked Jan 7 at 17:07
baek wonbaek won
11
11
$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
1
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
$endgroup$
– KM101
Jan 7 at 17:09
$begingroup$
Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
1
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13
|
show 9 more comments
$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
1
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
$endgroup$
– KM101
Jan 7 at 17:09
$begingroup$
Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
1
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13
$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
1
1
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
$endgroup$
– KM101
Jan 7 at 17:09
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
$endgroup$
– KM101
Jan 7 at 17:09
$begingroup$
Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
$begingroup$
Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
1
1
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13
|
show 9 more comments
1 Answer
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$begingroup$
Once you calculated 2 1/3 hours, you can figure out what to do next with units. The answer is speed, which has units (distance)/(time). So you divide the distance (36 km) by the time (2 1/3 hours) to get 15 3/7 km/hr.
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
$endgroup$
add a comment |
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$begingroup$
Once you calculated 2 1/3 hours, you can figure out what to do next with units. The answer is speed, which has units (distance)/(time). So you divide the distance (36 km) by the time (2 1/3 hours) to get 15 3/7 km/hr.
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
$endgroup$
add a comment |
$begingroup$
Once you calculated 2 1/3 hours, you can figure out what to do next with units. The answer is speed, which has units (distance)/(time). So you divide the distance (36 km) by the time (2 1/3 hours) to get 15 3/7 km/hr.
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
$endgroup$
add a comment |
$begingroup$
Once you calculated 2 1/3 hours, you can figure out what to do next with units. The answer is speed, which has units (distance)/(time). So you divide the distance (36 km) by the time (2 1/3 hours) to get 15 3/7 km/hr.
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
$endgroup$
Once you calculated 2 1/3 hours, you can figure out what to do next with units. The answer is speed, which has units (distance)/(time). So you divide the distance (36 km) by the time (2 1/3 hours) to get 15 3/7 km/hr.
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
answered Jan 7 at 17:13
Calvin GodfreyCalvin Godfrey
633311
633311
add a comment |
add a comment |
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$begingroup$
What have you tried so far?
$endgroup$
– Calvin Godfrey
Jan 7 at 17:08
1
$begingroup$
Avg speed = total distance / total time. Have you computed these?
$endgroup$
– Ben W
Jan 7 at 17:08
$begingroup$
What is the elapsed time in hours from $10$:$35$ to $12$:$55$?
$endgroup$
– KM101
Jan 7 at 17:09
$begingroup$
Tried finding the differences of the times which got me 02:20 and I had to covert it to 2 1/3 hours and then I know I have to divide 36 by something but that’s as far as I got really
$endgroup$
– baek won
Jan 7 at 17:10
1
$begingroup$
$2 frac{1}{3} = frac{7}{3}$ and $frac{36}{frac{7}{3}} = frac{36cdot 3}{7} = frac{108}{7} = 15frac{3}{7}$.
$endgroup$
– KM101
Jan 7 at 17:13