Lambert W-Function with numerical












0












$begingroup$


$ln x+x=1$
I am looking for solution of this equation. However, I am not able to find any simple way to solve this problem. Please help me to solve this problem by steps by steps as a result I will be able to understand.










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$endgroup$












  • $begingroup$
    What is with $x=1$?
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 16:58






  • 1




    $begingroup$
    $x=1$, satisfies $ln x+x=1$
    $endgroup$
    – Key Flex
    Jan 7 at 16:58










  • $begingroup$
    This is the only real solution!
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 17:00










  • $begingroup$
    @ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
    $endgroup$
    – Moo
    Jan 7 at 17:06


















0












$begingroup$


$ln x+x=1$
I am looking for solution of this equation. However, I am not able to find any simple way to solve this problem. Please help me to solve this problem by steps by steps as a result I will be able to understand.










share|cite|improve this question









$endgroup$












  • $begingroup$
    What is with $x=1$?
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 16:58






  • 1




    $begingroup$
    $x=1$, satisfies $ln x+x=1$
    $endgroup$
    – Key Flex
    Jan 7 at 16:58










  • $begingroup$
    This is the only real solution!
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 17:00










  • $begingroup$
    @ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
    $endgroup$
    – Moo
    Jan 7 at 17:06
















0












0








0





$begingroup$


$ln x+x=1$
I am looking for solution of this equation. However, I am not able to find any simple way to solve this problem. Please help me to solve this problem by steps by steps as a result I will be able to understand.










share|cite|improve this question









$endgroup$




$ln x+x=1$
I am looking for solution of this equation. However, I am not able to find any simple way to solve this problem. Please help me to solve this problem by steps by steps as a result I will be able to understand.







complex-analysis






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jan 7 at 16:55









Arun ChandArun Chand

1




1












  • $begingroup$
    What is with $x=1$?
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 16:58






  • 1




    $begingroup$
    $x=1$, satisfies $ln x+x=1$
    $endgroup$
    – Key Flex
    Jan 7 at 16:58










  • $begingroup$
    This is the only real solution!
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 17:00










  • $begingroup$
    @ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
    $endgroup$
    – Moo
    Jan 7 at 17:06




















  • $begingroup$
    What is with $x=1$?
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 16:58






  • 1




    $begingroup$
    $x=1$, satisfies $ln x+x=1$
    $endgroup$
    – Key Flex
    Jan 7 at 16:58










  • $begingroup$
    This is the only real solution!
    $endgroup$
    – Dr. Sonnhard Graubner
    Jan 7 at 17:00










  • $begingroup$
    @ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
    $endgroup$
    – Moo
    Jan 7 at 17:06


















$begingroup$
What is with $x=1$?
$endgroup$
– Dr. Sonnhard Graubner
Jan 7 at 16:58




$begingroup$
What is with $x=1$?
$endgroup$
– Dr. Sonnhard Graubner
Jan 7 at 16:58




1




1




$begingroup$
$x=1$, satisfies $ln x+x=1$
$endgroup$
– Key Flex
Jan 7 at 16:58




$begingroup$
$x=1$, satisfies $ln x+x=1$
$endgroup$
– Key Flex
Jan 7 at 16:58












$begingroup$
This is the only real solution!
$endgroup$
– Dr. Sonnhard Graubner
Jan 7 at 17:00




$begingroup$
This is the only real solution!
$endgroup$
– Dr. Sonnhard Graubner
Jan 7 at 17:00












$begingroup$
@ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
$endgroup$
– Moo
Jan 7 at 17:06






$begingroup$
@ArunChand: When all else fails, start with a plot: wolframalpha.com/input/?i=ln(x)+%2B+x+%3D+1
$endgroup$
– Moo
Jan 7 at 17:06












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