How do I figure which LED I need?
$begingroup$
I need to replace two LED diodes on a TP4056 board (bottom right corner on the picture).
The board is going to be in a box and I want to move diodes to the small holes in the box.
There are two resistors with marks 102, and that is 1 kilohm. I measured voltage on diodes and my multi-meter said 2.7 V.
I want to use something like this:
Those diodes are 3 V 20 mAh. Can they replace exiting diodes?
update:
Thank you guys. You helped me a lot.
Btw, current LEDs are blue and red
led resistors diodes
edited 2 days ago
Nick Alexeev♦
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I need to replace two LED diodes on a TP4056 board (bottom right corner on the picture).
The board is going to be in a box and I want to move diodes to the small holes in the box.
There are two resistors with marks 102, and that is 1 kilohm. I measured voltage on diodes and my multi-meter said 2.7 V.
I want to use something like this:
Those diodes are 3 V 20 mAh. Can they replace exiting diodes?
update:
Thank you guys. You helped me a lot.
Btw, current LEDs are blue and red
led resistors diodes
edited 2 days ago
Nick Alexeev♦
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
$endgroup$
– Transistor
Jan 11 at 19:04
2
$begingroup$
An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
$endgroup$
– Dithermaster
2 days ago
$begingroup$
FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
$endgroup$
– CYB3R
2 days ago
add a comment |
$begingroup$
I need to replace two LED diodes on a TP4056 board (bottom right corner on the picture).
The board is going to be in a box and I want to move diodes to the small holes in the box.
There are two resistors with marks 102, and that is 1 kilohm. I measured voltage on diodes and my multi-meter said 2.7 V.
I want to use something like this:
Those diodes are 3 V 20 mAh. Can they replace exiting diodes?
update:
Thank you guys. You helped me a lot.
Btw, current LEDs are blue and red
led resistors diodes
edited 2 days ago
Nick Alexeev♦
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I need to replace two LED diodes on a TP4056 board (bottom right corner on the picture).
The board is going to be in a box and I want to move diodes to the small holes in the box.
There are two resistors with marks 102, and that is 1 kilohm. I measured voltage on diodes and my multi-meter said 2.7 V.
I want to use something like this:
Those diodes are 3 V 20 mAh. Can they replace exiting diodes?
update:
Thank you guys. You helped me a lot.
Btw, current LEDs are blue and red
led resistors diodes
led resistors diodes
edited 2 days ago
Nick Alexeev♦
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Nick Alexeev♦
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Nick Alexeev♦
32.2k1063164
edited 2 days ago
Nick Alexeev♦
32.2k1063164
edited 2 days ago
Nick Alexeev♦
32.2k1063164
32.2k1063164
asked Jan 11 at 19:00
mt82mt82
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 11 at 19:00
mt82mt82
243
asked Jan 11 at 19:00
mt82mt82
243
243
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
mt82 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
$endgroup$
– Transistor
Jan 11 at 19:04
2
$begingroup$
An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
$endgroup$
– Dithermaster
2 days ago
$begingroup$
FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
$endgroup$
– CYB3R
2 days ago
add a comment |
$begingroup$
Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
$endgroup$
– Transistor
Jan 11 at 19:04
2
$begingroup$
An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
$endgroup$
– Dithermaster
2 days ago
$begingroup$
FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
$endgroup$
– CYB3R
2 days ago
$begingroup$
Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
$endgroup$
– Transistor
Jan 11 at 19:04
$begingroup$
Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
$endgroup$
– Transistor
Jan 11 at 19:04
2
2
$begingroup$
An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
$endgroup$
– Dithermaster
2 days ago
$begingroup$
An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
$endgroup$
– Dithermaster
2 days ago
$begingroup$
FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
$endgroup$
– CYB3R
2 days ago
$begingroup$
FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
$endgroup$
– CYB3R
2 days ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Figure 1. Typical IV curves for various colours of LEDs. Image source: LEDnique.
Replacement of any of those small indicator LEDs with 3 or 5 mm LEDs should be fine.
A little bit of background theory may help. LEDs have a non-linear relationship between applied voltage and current. The forward voltage also depends on the colour as shown in Figure 1.
Your measured 3 V LED voltage suggests that you've got either white or blue LEDs on the board. With the 1 kΩ resistor in series the current will be limited to a safe value even if you change to one with a lower forward voltage.
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
$endgroup$
add a comment |
$begingroup$
Based on the schematic in the datasheet, they're not critical, any LED will do.
answered Jan 11 at 19:28
Phil GPhil G
2,244412
$endgroup$
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
add a comment |
$begingroup$
Yes, you can most likely replace the SMD LEDs by any "jellybean" LED. You can easily try it. Do observe the correct LED polarity.
edited Jan 11 at 22:03
SamGibson
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
$endgroup$
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Figure 1. Typical IV curves for various colours of LEDs. Image source: LEDnique.
Replacement of any of those small indicator LEDs with 3 or 5 mm LEDs should be fine.
A little bit of background theory may help. LEDs have a non-linear relationship between applied voltage and current. The forward voltage also depends on the colour as shown in Figure 1.
Your measured 3 V LED voltage suggests that you've got either white or blue LEDs on the board. With the 1 kΩ resistor in series the current will be limited to a safe value even if you change to one with a lower forward voltage.
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
$endgroup$
add a comment |
$begingroup$
Figure 1. Typical IV curves for various colours of LEDs. Image source: LEDnique.
Replacement of any of those small indicator LEDs with 3 or 5 mm LEDs should be fine.
A little bit of background theory may help. LEDs have a non-linear relationship between applied voltage and current. The forward voltage also depends on the colour as shown in Figure 1.
Your measured 3 V LED voltage suggests that you've got either white or blue LEDs on the board. With the 1 kΩ resistor in series the current will be limited to a safe value even if you change to one with a lower forward voltage.
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
$endgroup$
add a comment |
$begingroup$
Figure 1. Typical IV curves for various colours of LEDs. Image source: LEDnique.
Replacement of any of those small indicator LEDs with 3 or 5 mm LEDs should be fine.
A little bit of background theory may help. LEDs have a non-linear relationship between applied voltage and current. The forward voltage also depends on the colour as shown in Figure 1.
Your measured 3 V LED voltage suggests that you've got either white or blue LEDs on the board. With the 1 kΩ resistor in series the current will be limited to a safe value even if you change to one with a lower forward voltage.
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
$endgroup$
Figure 1. Typical IV curves for various colours of LEDs. Image source: LEDnique.
Replacement of any of those small indicator LEDs with 3 or 5 mm LEDs should be fine.
A little bit of background theory may help. LEDs have a non-linear relationship between applied voltage and current. The forward voltage also depends on the colour as shown in Figure 1.
Your measured 3 V LED voltage suggests that you've got either white or blue LEDs on the board. With the 1 kΩ resistor in series the current will be limited to a safe value even if you change to one with a lower forward voltage.
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
answered Jan 11 at 19:30
TransistorTransistor
81.5k778176
81.5k778176
add a comment |
add a comment |
$begingroup$
Based on the schematic in the datasheet, they're not critical, any LED will do.
answered Jan 11 at 19:28
Phil GPhil G
2,244412
$endgroup$
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
add a comment |
$begingroup$
Based on the schematic in the datasheet, they're not critical, any LED will do.
answered Jan 11 at 19:28
Phil GPhil G
2,244412
$endgroup$
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
add a comment |
$begingroup$
Based on the schematic in the datasheet, they're not critical, any LED will do.
answered Jan 11 at 19:28
Phil GPhil G
2,244412
$endgroup$
Based on the schematic in the datasheet, they're not critical, any LED will do.
answered Jan 11 at 19:28
Phil GPhil G
2,244412
answered Jan 11 at 19:28
Phil GPhil G
2,244412
answered Jan 11 at 19:28
Phil GPhil G
2,244412
answered Jan 11 at 19:28
Phil GPhil G
2,244412
2,244412
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
add a comment |
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
Also, when designing something like this it is very common that the manufacturer just implemented the reference design, so chances are high that you will find a red and green (greed?) LED just like shown here.
$endgroup$
– pipe
2 days ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
$begingroup$
These boards often follow the reference design exactly - all the versions I've found or sale have the same color LEDs for indication. There's also an over- and undercharge battery protection circuit on this board - the two packages in the left side, that looks like it's the one here - electronics.stackexchange.com/questions/203463/….
$endgroup$
– Phil G
11 hours ago
add a comment |
$begingroup$
Yes, you can most likely replace the SMD LEDs by any "jellybean" LED. You can easily try it. Do observe the correct LED polarity.
edited Jan 11 at 22:03
SamGibson
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
$endgroup$
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
add a comment |
$begingroup$
Yes, you can most likely replace the SMD LEDs by any "jellybean" LED. You can easily try it. Do observe the correct LED polarity.
edited Jan 11 at 22:03
SamGibson
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
$endgroup$
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
add a comment |
$begingroup$
Yes, you can most likely replace the SMD LEDs by any "jellybean" LED. You can easily try it. Do observe the correct LED polarity.
edited Jan 11 at 22:03
SamGibson
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
$endgroup$
Yes, you can most likely replace the SMD LEDs by any "jellybean" LED. You can easily try it. Do observe the correct LED polarity.
edited Jan 11 at 22:03
SamGibson
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
edited Jan 11 at 22:03
SamGibson
10.9k41537
edited Jan 11 at 22:03
SamGibson
10.9k41537
edited Jan 11 at 22:03
SamGibson
10.9k41537
10.9k41537
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
answered Jan 11 at 19:24
Wouter van OoijenWouter van Ooijen
44.3k150118
44.3k150118
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
add a comment |
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
$begingroup$
Even getting the polarity wrong is unlikely to hurt anything, it'll just result in the LED not lighting, while the rest of the circuit works normally. And the LED won't be harmed either, so once installed with the correct polarity, it'll be just fine.
$endgroup$
– Ben Voigt
Jan 11 at 23:02
1
1
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
$begingroup$
Correct. But the LED won't work, that's all I was saying.
$endgroup$
– Wouter van Ooijen
2 days ago
add a comment |
mt82 is a new contributor. Be nice, and check out our Code of Conduct.
mt82 is a new contributor. Be nice, and check out our Code of Conduct.
mt82 is a new contributor. Be nice, and check out our Code of Conduct.
mt82 is a new contributor. Be nice, and check out our Code of Conduct.
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Welcome to EE.SE. For this question to be any use to future readers it is important that you include the images inline in your question so that it still makes sense when the eBay links die. Not many of us will follow links just to understand what you are asking about. There should be enough information in the question to answer it. The current rating of diodes will be in mA, not mAh which is used as a measure of energy capacity in a battery. There is an edit link below your question ...
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– Transistor
Jan 11 at 19:04
2
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An alternate solution is that you could use a light pipe to guide the light from the existing LEDs to the place you want to see it. On some devices the plastic thing you see lighting up is not the LED itself but one end of a light pipe.
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– Dithermaster
2 days ago
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FYI: "LED diodes" stand for "light-emitting diode diodes". Just use "LEDs" instead. Sorry for being a nudnik.
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– CYB3R
2 days ago