Prove the size of a hyperbolic angle is twice the area of its hyperbolic sector.












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I'm trying to figure out how the hyperbolic functions are derived using a unit hyperbola.



According to this walkthrough, argument u in (cosh(u), sinh(u)) should be equal to 2A, where A is the area of an intercepted hyperbolic sector from (0,0) to (cosh(u), sinh(u)).



Confused as to why this is defined as such, I found on Wikipedia:




The size of a hyperbolic angle is twice the area of its hyperbolic sector. The hyperbolic functions may be defined in terms of the legs of a right triangle covering this sector.




However, I couldn't find a explanation for this anywhere. Can anyone help show me why this is?










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    1












    $begingroup$


    I'm trying to figure out how the hyperbolic functions are derived using a unit hyperbola.



    According to this walkthrough, argument u in (cosh(u), sinh(u)) should be equal to 2A, where A is the area of an intercepted hyperbolic sector from (0,0) to (cosh(u), sinh(u)).



    Confused as to why this is defined as such, I found on Wikipedia:




    The size of a hyperbolic angle is twice the area of its hyperbolic sector. The hyperbolic functions may be defined in terms of the legs of a right triangle covering this sector.




    However, I couldn't find a explanation for this anywhere. Can anyone help show me why this is?










    share|cite|improve this question









    New contributor




    sqrtpapi2001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1


      1



      $begingroup$


      I'm trying to figure out how the hyperbolic functions are derived using a unit hyperbola.



      According to this walkthrough, argument u in (cosh(u), sinh(u)) should be equal to 2A, where A is the area of an intercepted hyperbolic sector from (0,0) to (cosh(u), sinh(u)).



      Confused as to why this is defined as such, I found on Wikipedia:




      The size of a hyperbolic angle is twice the area of its hyperbolic sector. The hyperbolic functions may be defined in terms of the legs of a right triangle covering this sector.




      However, I couldn't find a explanation for this anywhere. Can anyone help show me why this is?










      share|cite|improve this question









      New contributor




      sqrtpapi2001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      I'm trying to figure out how the hyperbolic functions are derived using a unit hyperbola.



      According to this walkthrough, argument u in (cosh(u), sinh(u)) should be equal to 2A, where A is the area of an intercepted hyperbolic sector from (0,0) to (cosh(u), sinh(u)).



      Confused as to why this is defined as such, I found on Wikipedia:




      The size of a hyperbolic angle is twice the area of its hyperbolic sector. The hyperbolic functions may be defined in terms of the legs of a right triangle covering this sector.




      However, I couldn't find a explanation for this anywhere. Can anyone help show me why this is?







      calculus geometry hyperbolic-functions






      share|cite|improve this question









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      sqrtpapi2001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|cite|improve this question









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      sqrtpapi2001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      edited Jan 5 at 6:10







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      asked Jan 5 at 6:04









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