Finding error in following difference table?












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I've been trying to solve a question on my book on finding error in the following difference table:



enter image description here



My teacher told me to expand the difference table until I find the proper Binomial coefficients, hence I've expanded the difference table to y5.



According to my solution, the error is originating from 6th entry of the table.
In the y5 column, I am using Binomial factors to find the error.



Error = Largest value in a column / Corresponding coefficient of ε in that column



Error = $.095/4 = 0.02375$



Since my teacher told me that the error will always be subtracted from orginal entry



Corrected Value = $ 0.589 - 0.02375 = 0.56525 $



but in my book, the answer is: $0.598$



Where am I missing?










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    0












    $begingroup$


    I've been trying to solve a question on my book on finding error in the following difference table:



    enter image description here



    My teacher told me to expand the difference table until I find the proper Binomial coefficients, hence I've expanded the difference table to y5.



    According to my solution, the error is originating from 6th entry of the table.
    In the y5 column, I am using Binomial factors to find the error.



    Error = Largest value in a column / Corresponding coefficient of ε in that column



    Error = $.095/4 = 0.02375$



    Since my teacher told me that the error will always be subtracted from orginal entry



    Corrected Value = $ 0.589 - 0.02375 = 0.56525 $



    but in my book, the answer is: $0.598$



    Where am I missing?










    share|cite|improve this question











    $endgroup$















      0












      0








      0





      $begingroup$


      I've been trying to solve a question on my book on finding error in the following difference table:



      enter image description here



      My teacher told me to expand the difference table until I find the proper Binomial coefficients, hence I've expanded the difference table to y5.



      According to my solution, the error is originating from 6th entry of the table.
      In the y5 column, I am using Binomial factors to find the error.



      Error = Largest value in a column / Corresponding coefficient of ε in that column



      Error = $.095/4 = 0.02375$



      Since my teacher told me that the error will always be subtracted from orginal entry



      Corrected Value = $ 0.589 - 0.02375 = 0.56525 $



      but in my book, the answer is: $0.598$



      Where am I missing?










      share|cite|improve this question











      $endgroup$




      I've been trying to solve a question on my book on finding error in the following difference table:



      enter image description here



      My teacher told me to expand the difference table until I find the proper Binomial coefficients, hence I've expanded the difference table to y5.



      According to my solution, the error is originating from 6th entry of the table.
      In the y5 column, I am using Binomial factors to find the error.



      Error = Largest value in a column / Corresponding coefficient of ε in that column



      Error = $.095/4 = 0.02375$



      Since my teacher told me that the error will always be subtracted from orginal entry



      Corrected Value = $ 0.589 - 0.02375 = 0.56525 $



      but in my book, the answer is: $0.598$



      Where am I missing?







      numerical-methods finite-differences error-propagation






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      edited Dec 18 '16 at 4:27







      HQuser

















      asked Dec 17 '16 at 14:21









      HQuserHQuser

      142212




      142212






















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          $begingroup$

          The corresponding coefficient of $varepsilon$ in that column for $0.095$ is $-10$.
          So error will be $-0.0095$. And hence Corrected Value $=0.589+0.0095=0.5985$






          share|cite|improve this answer











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            $begingroup$

            The corresponding coefficient of $varepsilon$ in that column for $0.095$ is $-10$.
            So error will be $-0.0095$. And hence Corrected Value $=0.589+0.0095=0.5985$






            share|cite|improve this answer











            $endgroup$


















              0












              $begingroup$

              The corresponding coefficient of $varepsilon$ in that column for $0.095$ is $-10$.
              So error will be $-0.0095$. And hence Corrected Value $=0.589+0.0095=0.5985$






              share|cite|improve this answer











              $endgroup$
















                0












                0








                0





                $begingroup$

                The corresponding coefficient of $varepsilon$ in that column for $0.095$ is $-10$.
                So error will be $-0.0095$. And hence Corrected Value $=0.589+0.0095=0.5985$






                share|cite|improve this answer











                $endgroup$



                The corresponding coefficient of $varepsilon$ in that column for $0.095$ is $-10$.
                So error will be $-0.0095$. And hence Corrected Value $=0.589+0.0095=0.5985$







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Feb 11 '18 at 7:06









                mucciolo

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                1,9721819










                answered Feb 11 '18 at 6:07









                bharat dubeybharat dubey

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