Taylor series expression of the function.
$begingroup$
Suppose we are given the following function.
$$f(x)=frac{1}{2}[xsqrt{1-x^2} +sin^{-1}x]$$. Write down the Taylor series expansion about the origin, up to term involving $x^7$, for the function.
This problem was asked in a mathematics exam where students have to solve 40 questions in 150 minutes.
I know the routine method but it is too lengthy.
Is there a more easy("Think out of the box") like approach to solve it.
real-analysis
$endgroup$
add a comment |
$begingroup$
Suppose we are given the following function.
$$f(x)=frac{1}{2}[xsqrt{1-x^2} +sin^{-1}x]$$. Write down the Taylor series expansion about the origin, up to term involving $x^7$, for the function.
This problem was asked in a mathematics exam where students have to solve 40 questions in 150 minutes.
I know the routine method but it is too lengthy.
Is there a more easy("Think out of the box") like approach to solve it.
real-analysis
$endgroup$
3
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59
add a comment |
$begingroup$
Suppose we are given the following function.
$$f(x)=frac{1}{2}[xsqrt{1-x^2} +sin^{-1}x]$$. Write down the Taylor series expansion about the origin, up to term involving $x^7$, for the function.
This problem was asked in a mathematics exam where students have to solve 40 questions in 150 minutes.
I know the routine method but it is too lengthy.
Is there a more easy("Think out of the box") like approach to solve it.
real-analysis
$endgroup$
Suppose we are given the following function.
$$f(x)=frac{1}{2}[xsqrt{1-x^2} +sin^{-1}x]$$. Write down the Taylor series expansion about the origin, up to term involving $x^7$, for the function.
This problem was asked in a mathematics exam where students have to solve 40 questions in 150 minutes.
I know the routine method but it is too lengthy.
Is there a more easy("Think out of the box") like approach to solve it.
real-analysis
real-analysis
asked Jan 6 at 13:55
StammeringMathematicianStammeringMathematician
2,3121322
2,3121322
3
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59
add a comment |
3
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59
3
3
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Your function is just$$int_0^xsqrt{1-t^2},mathrm dt.$$
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3063887%2ftaylor-series-expression-of-the-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your function is just$$int_0^xsqrt{1-t^2},mathrm dt.$$
$endgroup$
add a comment |
$begingroup$
Your function is just$$int_0^xsqrt{1-t^2},mathrm dt.$$
$endgroup$
add a comment |
$begingroup$
Your function is just$$int_0^xsqrt{1-t^2},mathrm dt.$$
$endgroup$
Your function is just$$int_0^xsqrt{1-t^2},mathrm dt.$$
answered Jan 6 at 14:00
José Carlos SantosJosé Carlos Santos
154k22124227
154k22124227
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3063887%2ftaylor-series-expression-of-the-function%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
3
$begingroup$
Differentiate it?
$endgroup$
– Lord Shark the Unknown
Jan 6 at 13:58
$begingroup$
Got it. Thanks!!
$endgroup$
– StammeringMathematician
Jan 6 at 13:59