Pushforward of the structure sheaf on $mathbb{P_mathbb{C}^1}$












2












$begingroup$


Today I had the final exam of the lesson Algebraic Geometry. There was a question was asked:




Let $X=Y=mathbb{P_mathbb{C}^1}$ the homogeneous coordinate $(x_0,x_1)$ and $(y_0,y_1)$, respectively. Let $f : X to Y$ be a morphism given by
$$
(x_0,x_1) to (y_0,y_1)=(x_0^2,x_1^2).
$$





  • Show that $f_ast O_X $ is a locally free sheaf of $O_Y $ -modules of rank two. ( $ O_X $ is the structure sheaf of $X$).

  • Show that the induced map $i : O_Y to f_ast O_X $ is injective.

  • Show that the cokernel of $i$ as a sheaf is isomorphic to $O_Y (−1)$.


There is a similar question with respect to the situation of pullback,but I don't even know how to deal with this problem. Hopefully someone can give me a hint.










share|cite|improve this question











$endgroup$

















    2












    $begingroup$


    Today I had the final exam of the lesson Algebraic Geometry. There was a question was asked:




    Let $X=Y=mathbb{P_mathbb{C}^1}$ the homogeneous coordinate $(x_0,x_1)$ and $(y_0,y_1)$, respectively. Let $f : X to Y$ be a morphism given by
    $$
    (x_0,x_1) to (y_0,y_1)=(x_0^2,x_1^2).
    $$





    • Show that $f_ast O_X $ is a locally free sheaf of $O_Y $ -modules of rank two. ( $ O_X $ is the structure sheaf of $X$).

    • Show that the induced map $i : O_Y to f_ast O_X $ is injective.

    • Show that the cokernel of $i$ as a sheaf is isomorphic to $O_Y (−1)$.


    There is a similar question with respect to the situation of pullback,but I don't even know how to deal with this problem. Hopefully someone can give me a hint.










    share|cite|improve this question











    $endgroup$















      2












      2








      2


      2



      $begingroup$


      Today I had the final exam of the lesson Algebraic Geometry. There was a question was asked:




      Let $X=Y=mathbb{P_mathbb{C}^1}$ the homogeneous coordinate $(x_0,x_1)$ and $(y_0,y_1)$, respectively. Let $f : X to Y$ be a morphism given by
      $$
      (x_0,x_1) to (y_0,y_1)=(x_0^2,x_1^2).
      $$





      • Show that $f_ast O_X $ is a locally free sheaf of $O_Y $ -modules of rank two. ( $ O_X $ is the structure sheaf of $X$).

      • Show that the induced map $i : O_Y to f_ast O_X $ is injective.

      • Show that the cokernel of $i$ as a sheaf is isomorphic to $O_Y (−1)$.


      There is a similar question with respect to the situation of pullback,but I don't even know how to deal with this problem. Hopefully someone can give me a hint.










      share|cite|improve this question











      $endgroup$




      Today I had the final exam of the lesson Algebraic Geometry. There was a question was asked:




      Let $X=Y=mathbb{P_mathbb{C}^1}$ the homogeneous coordinate $(x_0,x_1)$ and $(y_0,y_1)$, respectively. Let $f : X to Y$ be a morphism given by
      $$
      (x_0,x_1) to (y_0,y_1)=(x_0^2,x_1^2).
      $$





      • Show that $f_ast O_X $ is a locally free sheaf of $O_Y $ -modules of rank two. ( $ O_X $ is the structure sheaf of $X$).

      • Show that the induced map $i : O_Y to f_ast O_X $ is injective.

      • Show that the cokernel of $i$ as a sheaf is isomorphic to $O_Y (−1)$.


      There is a similar question with respect to the situation of pullback,but I don't even know how to deal with this problem. Hopefully someone can give me a hint.







      algebraic-geometry sheaf-theory






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Jan 8 at 6:07







      Zhu Huanhuan

















      asked Jan 6 at 13:40









      Zhu HuanhuanZhu Huanhuan

      31816




      31816






















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          It's possible to do this by brute force, using open affine covers for $X$ and $Y$:
          $$ U_0 := { [x_0 : 1] in X }cong{rm Spec} mathbb C[x_0], U_1 :={[1 : x_1] in X } cong {rm Spec} mathbb C[x_1] $$
          $$ V_0 := { [y_0 : 1] in Y }cong{rm Spec} mathbb C[y_0], V_1 :={[1 : y_1] in Y } cong {rm Spec} mathbb C[y_1] $$
          On $U_0 cap U_1$, we identify $x_0 in mathbb C[x_0]_{(x_0)}$ with $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$. We make a similar identification between $y_0$ and $y_1^{-1}$ on $V_0 cap V_1$.



          Conveniently, we have $f^{-1}(V_0) = U_0$ and $f^{-1}(V_1) = U_1$. The morphism $f$ is associated with the ring homomorphisms:
          $$ mathbb C[y_0] to mathbb C[x_0] , y_0 mapsto x_0^2$$
          $$ mathbb C[y_1] to mathbb C[x_1] , y_1 mapsto x_1^2$$



          The original structure sheaf $mathcal O_X$ can be described as follows:




          • On $U_0$: $(mathcal O_X)|_{U_0}$ is the quasicoherent sheaf associated to the $mathbb C[x_0]$-module $mathbb C[x_0]$.

          • On $U_1$: $(mathcal O_X)|_{U_1}$ is the quasicoherent sheaf associated to the $mathbb C[x_1]$-module $mathbb C[x_1]$.

          • On $U_0 cap U_1$: the transition function is defined by identifying the element $x_0 in mathbb C[x_0]_{(x_0)}$ with the element $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$.


          So the pushforward $f_star mathcal O_X$ can be described like this:




          • On $V_0$: $(f_star mathcal O_X)|_{V_0}$ is the quasicoherent sheaf associated with $mathbb C[x_0]$, now viewed as a $mathbb C[y_0]$-module, with $y_0$ viewed as $x_0^2$.

          • On $V_1$: $(f_star mathcal O_X)|_{V_1}$ is the quasicoherent sheaf associated with $mathbb C[x_1]$, now viewed as a $mathbb C[y_1]$-module, with $y_1$ viewed as $x_1^2$.

          • On $V_0 cap V_1$: we identify the element $x_0 in mathbb C[x_0]_{(y_0)}$ with the element $x_1^{-1} in mathbb C[x_1]_{(y_1)}$.


          Now observe that $mathbb C[x_0]$ is a free $mathbb C[y_0]$ module, by virtue of the $mathbb C[y_0]$-module isomorphism $$ mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$$



          So $(f_star mathcal O_X)|_{V_0}$ is a free sheaf of rank two. A similar statement is true on $V_1$. Thus $f_star mathcal O_X$ is a locally free sheaf on $Y$.



          The sheaf morphism $i_star mathcal O_Y to f_star mathcal O_X$ can described using module morphisms on the two affine patches. For example, on $V_0$, $i_star$ is associated with the morphism of $mathbb C[y_0]$-modules,
          $$ mathbb C[y_0] to mathbb C[x_0], y_0 mapsto x_0^2,$$



          which is injective, hence injective on all localisations at prime ideals. As the same is true on $V_1$, we see that $i_star$ is injective on all stalks.



          Finally, we describe the cokernel of $i_star$. On $V_0$ this cokernel is the sheaf associated with the $mathbb C[y_0].x_0$ component of $mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$. On $V_1$, it is the sheaf associated with the $mathbb C[y_1] . x_1 $ component of $mathbb C[x_1] cong mathbb C[y_1]. 1 oplus mathbb C[y_1]. x_1$. Notice that $mathbb C[y_0].x_0$ is a rank-one free module over $mathbb C[y_0]$, and $mathbb C[y_1].x_1$ is a rank-one free module over $mathbb C[y_1]$. So the cokernel of $i_star$ is locally free of rank one. It only remains to find the transition function. On the overlap $V_0 cap V_1$, we identify $1. x_0 in mathbb C[y_0]_{(y_0)}.x_0$ with $y_1^{-1} . x_1 in mathbb C[y_1]_{(y_1)} . x_1$. The identification $1 leftrightarrow y_1^{-1}$ is precisely the transition function for the invertible sheaf $mathcal O_Y(-1)$.






          share|cite|improve this answer











          $endgroup$













            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "69"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3063864%2fpushforward-of-the-structure-sheaf-on-mathbbp-mathbbc1%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            It's possible to do this by brute force, using open affine covers for $X$ and $Y$:
            $$ U_0 := { [x_0 : 1] in X }cong{rm Spec} mathbb C[x_0], U_1 :={[1 : x_1] in X } cong {rm Spec} mathbb C[x_1] $$
            $$ V_0 := { [y_0 : 1] in Y }cong{rm Spec} mathbb C[y_0], V_1 :={[1 : y_1] in Y } cong {rm Spec} mathbb C[y_1] $$
            On $U_0 cap U_1$, we identify $x_0 in mathbb C[x_0]_{(x_0)}$ with $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$. We make a similar identification between $y_0$ and $y_1^{-1}$ on $V_0 cap V_1$.



            Conveniently, we have $f^{-1}(V_0) = U_0$ and $f^{-1}(V_1) = U_1$. The morphism $f$ is associated with the ring homomorphisms:
            $$ mathbb C[y_0] to mathbb C[x_0] , y_0 mapsto x_0^2$$
            $$ mathbb C[y_1] to mathbb C[x_1] , y_1 mapsto x_1^2$$



            The original structure sheaf $mathcal O_X$ can be described as follows:




            • On $U_0$: $(mathcal O_X)|_{U_0}$ is the quasicoherent sheaf associated to the $mathbb C[x_0]$-module $mathbb C[x_0]$.

            • On $U_1$: $(mathcal O_X)|_{U_1}$ is the quasicoherent sheaf associated to the $mathbb C[x_1]$-module $mathbb C[x_1]$.

            • On $U_0 cap U_1$: the transition function is defined by identifying the element $x_0 in mathbb C[x_0]_{(x_0)}$ with the element $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$.


            So the pushforward $f_star mathcal O_X$ can be described like this:




            • On $V_0$: $(f_star mathcal O_X)|_{V_0}$ is the quasicoherent sheaf associated with $mathbb C[x_0]$, now viewed as a $mathbb C[y_0]$-module, with $y_0$ viewed as $x_0^2$.

            • On $V_1$: $(f_star mathcal O_X)|_{V_1}$ is the quasicoherent sheaf associated with $mathbb C[x_1]$, now viewed as a $mathbb C[y_1]$-module, with $y_1$ viewed as $x_1^2$.

            • On $V_0 cap V_1$: we identify the element $x_0 in mathbb C[x_0]_{(y_0)}$ with the element $x_1^{-1} in mathbb C[x_1]_{(y_1)}$.


            Now observe that $mathbb C[x_0]$ is a free $mathbb C[y_0]$ module, by virtue of the $mathbb C[y_0]$-module isomorphism $$ mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$$



            So $(f_star mathcal O_X)|_{V_0}$ is a free sheaf of rank two. A similar statement is true on $V_1$. Thus $f_star mathcal O_X$ is a locally free sheaf on $Y$.



            The sheaf morphism $i_star mathcal O_Y to f_star mathcal O_X$ can described using module morphisms on the two affine patches. For example, on $V_0$, $i_star$ is associated with the morphism of $mathbb C[y_0]$-modules,
            $$ mathbb C[y_0] to mathbb C[x_0], y_0 mapsto x_0^2,$$



            which is injective, hence injective on all localisations at prime ideals. As the same is true on $V_1$, we see that $i_star$ is injective on all stalks.



            Finally, we describe the cokernel of $i_star$. On $V_0$ this cokernel is the sheaf associated with the $mathbb C[y_0].x_0$ component of $mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$. On $V_1$, it is the sheaf associated with the $mathbb C[y_1] . x_1 $ component of $mathbb C[x_1] cong mathbb C[y_1]. 1 oplus mathbb C[y_1]. x_1$. Notice that $mathbb C[y_0].x_0$ is a rank-one free module over $mathbb C[y_0]$, and $mathbb C[y_1].x_1$ is a rank-one free module over $mathbb C[y_1]$. So the cokernel of $i_star$ is locally free of rank one. It only remains to find the transition function. On the overlap $V_0 cap V_1$, we identify $1. x_0 in mathbb C[y_0]_{(y_0)}.x_0$ with $y_1^{-1} . x_1 in mathbb C[y_1]_{(y_1)} . x_1$. The identification $1 leftrightarrow y_1^{-1}$ is precisely the transition function for the invertible sheaf $mathcal O_Y(-1)$.






            share|cite|improve this answer











            $endgroup$


















              2












              $begingroup$

              It's possible to do this by brute force, using open affine covers for $X$ and $Y$:
              $$ U_0 := { [x_0 : 1] in X }cong{rm Spec} mathbb C[x_0], U_1 :={[1 : x_1] in X } cong {rm Spec} mathbb C[x_1] $$
              $$ V_0 := { [y_0 : 1] in Y }cong{rm Spec} mathbb C[y_0], V_1 :={[1 : y_1] in Y } cong {rm Spec} mathbb C[y_1] $$
              On $U_0 cap U_1$, we identify $x_0 in mathbb C[x_0]_{(x_0)}$ with $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$. We make a similar identification between $y_0$ and $y_1^{-1}$ on $V_0 cap V_1$.



              Conveniently, we have $f^{-1}(V_0) = U_0$ and $f^{-1}(V_1) = U_1$. The morphism $f$ is associated with the ring homomorphisms:
              $$ mathbb C[y_0] to mathbb C[x_0] , y_0 mapsto x_0^2$$
              $$ mathbb C[y_1] to mathbb C[x_1] , y_1 mapsto x_1^2$$



              The original structure sheaf $mathcal O_X$ can be described as follows:




              • On $U_0$: $(mathcal O_X)|_{U_0}$ is the quasicoherent sheaf associated to the $mathbb C[x_0]$-module $mathbb C[x_0]$.

              • On $U_1$: $(mathcal O_X)|_{U_1}$ is the quasicoherent sheaf associated to the $mathbb C[x_1]$-module $mathbb C[x_1]$.

              • On $U_0 cap U_1$: the transition function is defined by identifying the element $x_0 in mathbb C[x_0]_{(x_0)}$ with the element $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$.


              So the pushforward $f_star mathcal O_X$ can be described like this:




              • On $V_0$: $(f_star mathcal O_X)|_{V_0}$ is the quasicoherent sheaf associated with $mathbb C[x_0]$, now viewed as a $mathbb C[y_0]$-module, with $y_0$ viewed as $x_0^2$.

              • On $V_1$: $(f_star mathcal O_X)|_{V_1}$ is the quasicoherent sheaf associated with $mathbb C[x_1]$, now viewed as a $mathbb C[y_1]$-module, with $y_1$ viewed as $x_1^2$.

              • On $V_0 cap V_1$: we identify the element $x_0 in mathbb C[x_0]_{(y_0)}$ with the element $x_1^{-1} in mathbb C[x_1]_{(y_1)}$.


              Now observe that $mathbb C[x_0]$ is a free $mathbb C[y_0]$ module, by virtue of the $mathbb C[y_0]$-module isomorphism $$ mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$$



              So $(f_star mathcal O_X)|_{V_0}$ is a free sheaf of rank two. A similar statement is true on $V_1$. Thus $f_star mathcal O_X$ is a locally free sheaf on $Y$.



              The sheaf morphism $i_star mathcal O_Y to f_star mathcal O_X$ can described using module morphisms on the two affine patches. For example, on $V_0$, $i_star$ is associated with the morphism of $mathbb C[y_0]$-modules,
              $$ mathbb C[y_0] to mathbb C[x_0], y_0 mapsto x_0^2,$$



              which is injective, hence injective on all localisations at prime ideals. As the same is true on $V_1$, we see that $i_star$ is injective on all stalks.



              Finally, we describe the cokernel of $i_star$. On $V_0$ this cokernel is the sheaf associated with the $mathbb C[y_0].x_0$ component of $mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$. On $V_1$, it is the sheaf associated with the $mathbb C[y_1] . x_1 $ component of $mathbb C[x_1] cong mathbb C[y_1]. 1 oplus mathbb C[y_1]. x_1$. Notice that $mathbb C[y_0].x_0$ is a rank-one free module over $mathbb C[y_0]$, and $mathbb C[y_1].x_1$ is a rank-one free module over $mathbb C[y_1]$. So the cokernel of $i_star$ is locally free of rank one. It only remains to find the transition function. On the overlap $V_0 cap V_1$, we identify $1. x_0 in mathbb C[y_0]_{(y_0)}.x_0$ with $y_1^{-1} . x_1 in mathbb C[y_1]_{(y_1)} . x_1$. The identification $1 leftrightarrow y_1^{-1}$ is precisely the transition function for the invertible sheaf $mathcal O_Y(-1)$.






              share|cite|improve this answer











              $endgroup$
















                2












                2








                2





                $begingroup$

                It's possible to do this by brute force, using open affine covers for $X$ and $Y$:
                $$ U_0 := { [x_0 : 1] in X }cong{rm Spec} mathbb C[x_0], U_1 :={[1 : x_1] in X } cong {rm Spec} mathbb C[x_1] $$
                $$ V_0 := { [y_0 : 1] in Y }cong{rm Spec} mathbb C[y_0], V_1 :={[1 : y_1] in Y } cong {rm Spec} mathbb C[y_1] $$
                On $U_0 cap U_1$, we identify $x_0 in mathbb C[x_0]_{(x_0)}$ with $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$. We make a similar identification between $y_0$ and $y_1^{-1}$ on $V_0 cap V_1$.



                Conveniently, we have $f^{-1}(V_0) = U_0$ and $f^{-1}(V_1) = U_1$. The morphism $f$ is associated with the ring homomorphisms:
                $$ mathbb C[y_0] to mathbb C[x_0] , y_0 mapsto x_0^2$$
                $$ mathbb C[y_1] to mathbb C[x_1] , y_1 mapsto x_1^2$$



                The original structure sheaf $mathcal O_X$ can be described as follows:




                • On $U_0$: $(mathcal O_X)|_{U_0}$ is the quasicoherent sheaf associated to the $mathbb C[x_0]$-module $mathbb C[x_0]$.

                • On $U_1$: $(mathcal O_X)|_{U_1}$ is the quasicoherent sheaf associated to the $mathbb C[x_1]$-module $mathbb C[x_1]$.

                • On $U_0 cap U_1$: the transition function is defined by identifying the element $x_0 in mathbb C[x_0]_{(x_0)}$ with the element $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$.


                So the pushforward $f_star mathcal O_X$ can be described like this:




                • On $V_0$: $(f_star mathcal O_X)|_{V_0}$ is the quasicoherent sheaf associated with $mathbb C[x_0]$, now viewed as a $mathbb C[y_0]$-module, with $y_0$ viewed as $x_0^2$.

                • On $V_1$: $(f_star mathcal O_X)|_{V_1}$ is the quasicoherent sheaf associated with $mathbb C[x_1]$, now viewed as a $mathbb C[y_1]$-module, with $y_1$ viewed as $x_1^2$.

                • On $V_0 cap V_1$: we identify the element $x_0 in mathbb C[x_0]_{(y_0)}$ with the element $x_1^{-1} in mathbb C[x_1]_{(y_1)}$.


                Now observe that $mathbb C[x_0]$ is a free $mathbb C[y_0]$ module, by virtue of the $mathbb C[y_0]$-module isomorphism $$ mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$$



                So $(f_star mathcal O_X)|_{V_0}$ is a free sheaf of rank two. A similar statement is true on $V_1$. Thus $f_star mathcal O_X$ is a locally free sheaf on $Y$.



                The sheaf morphism $i_star mathcal O_Y to f_star mathcal O_X$ can described using module morphisms on the two affine patches. For example, on $V_0$, $i_star$ is associated with the morphism of $mathbb C[y_0]$-modules,
                $$ mathbb C[y_0] to mathbb C[x_0], y_0 mapsto x_0^2,$$



                which is injective, hence injective on all localisations at prime ideals. As the same is true on $V_1$, we see that $i_star$ is injective on all stalks.



                Finally, we describe the cokernel of $i_star$. On $V_0$ this cokernel is the sheaf associated with the $mathbb C[y_0].x_0$ component of $mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$. On $V_1$, it is the sheaf associated with the $mathbb C[y_1] . x_1 $ component of $mathbb C[x_1] cong mathbb C[y_1]. 1 oplus mathbb C[y_1]. x_1$. Notice that $mathbb C[y_0].x_0$ is a rank-one free module over $mathbb C[y_0]$, and $mathbb C[y_1].x_1$ is a rank-one free module over $mathbb C[y_1]$. So the cokernel of $i_star$ is locally free of rank one. It only remains to find the transition function. On the overlap $V_0 cap V_1$, we identify $1. x_0 in mathbb C[y_0]_{(y_0)}.x_0$ with $y_1^{-1} . x_1 in mathbb C[y_1]_{(y_1)} . x_1$. The identification $1 leftrightarrow y_1^{-1}$ is precisely the transition function for the invertible sheaf $mathcal O_Y(-1)$.






                share|cite|improve this answer











                $endgroup$



                It's possible to do this by brute force, using open affine covers for $X$ and $Y$:
                $$ U_0 := { [x_0 : 1] in X }cong{rm Spec} mathbb C[x_0], U_1 :={[1 : x_1] in X } cong {rm Spec} mathbb C[x_1] $$
                $$ V_0 := { [y_0 : 1] in Y }cong{rm Spec} mathbb C[y_0], V_1 :={[1 : y_1] in Y } cong {rm Spec} mathbb C[y_1] $$
                On $U_0 cap U_1$, we identify $x_0 in mathbb C[x_0]_{(x_0)}$ with $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$. We make a similar identification between $y_0$ and $y_1^{-1}$ on $V_0 cap V_1$.



                Conveniently, we have $f^{-1}(V_0) = U_0$ and $f^{-1}(V_1) = U_1$. The morphism $f$ is associated with the ring homomorphisms:
                $$ mathbb C[y_0] to mathbb C[x_0] , y_0 mapsto x_0^2$$
                $$ mathbb C[y_1] to mathbb C[x_1] , y_1 mapsto x_1^2$$



                The original structure sheaf $mathcal O_X$ can be described as follows:




                • On $U_0$: $(mathcal O_X)|_{U_0}$ is the quasicoherent sheaf associated to the $mathbb C[x_0]$-module $mathbb C[x_0]$.

                • On $U_1$: $(mathcal O_X)|_{U_1}$ is the quasicoherent sheaf associated to the $mathbb C[x_1]$-module $mathbb C[x_1]$.

                • On $U_0 cap U_1$: the transition function is defined by identifying the element $x_0 in mathbb C[x_0]_{(x_0)}$ with the element $x^{-1}_1 in mathbb C[x_1]_{(x_1)}$.


                So the pushforward $f_star mathcal O_X$ can be described like this:




                • On $V_0$: $(f_star mathcal O_X)|_{V_0}$ is the quasicoherent sheaf associated with $mathbb C[x_0]$, now viewed as a $mathbb C[y_0]$-module, with $y_0$ viewed as $x_0^2$.

                • On $V_1$: $(f_star mathcal O_X)|_{V_1}$ is the quasicoherent sheaf associated with $mathbb C[x_1]$, now viewed as a $mathbb C[y_1]$-module, with $y_1$ viewed as $x_1^2$.

                • On $V_0 cap V_1$: we identify the element $x_0 in mathbb C[x_0]_{(y_0)}$ with the element $x_1^{-1} in mathbb C[x_1]_{(y_1)}$.


                Now observe that $mathbb C[x_0]$ is a free $mathbb C[y_0]$ module, by virtue of the $mathbb C[y_0]$-module isomorphism $$ mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$$



                So $(f_star mathcal O_X)|_{V_0}$ is a free sheaf of rank two. A similar statement is true on $V_1$. Thus $f_star mathcal O_X$ is a locally free sheaf on $Y$.



                The sheaf morphism $i_star mathcal O_Y to f_star mathcal O_X$ can described using module morphisms on the two affine patches. For example, on $V_0$, $i_star$ is associated with the morphism of $mathbb C[y_0]$-modules,
                $$ mathbb C[y_0] to mathbb C[x_0], y_0 mapsto x_0^2,$$



                which is injective, hence injective on all localisations at prime ideals. As the same is true on $V_1$, we see that $i_star$ is injective on all stalks.



                Finally, we describe the cokernel of $i_star$. On $V_0$ this cokernel is the sheaf associated with the $mathbb C[y_0].x_0$ component of $mathbb C[x_0] cong mathbb C[y_0]. 1 oplus mathbb C[y_0]. x_0$. On $V_1$, it is the sheaf associated with the $mathbb C[y_1] . x_1 $ component of $mathbb C[x_1] cong mathbb C[y_1]. 1 oplus mathbb C[y_1]. x_1$. Notice that $mathbb C[y_0].x_0$ is a rank-one free module over $mathbb C[y_0]$, and $mathbb C[y_1].x_1$ is a rank-one free module over $mathbb C[y_1]$. So the cokernel of $i_star$ is locally free of rank one. It only remains to find the transition function. On the overlap $V_0 cap V_1$, we identify $1. x_0 in mathbb C[y_0]_{(y_0)}.x_0$ with $y_1^{-1} . x_1 in mathbb C[y_1]_{(y_1)} . x_1$. The identification $1 leftrightarrow y_1^{-1}$ is precisely the transition function for the invertible sheaf $mathcal O_Y(-1)$.







                share|cite|improve this answer














                share|cite|improve this answer



                share|cite|improve this answer








                edited Jan 6 at 14:55

























                answered Jan 6 at 14:49









                Kenny WongKenny Wong

                18.3k21438




                18.3k21438






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Mathematics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3063864%2fpushforward-of-the-structure-sheaf-on-mathbbp-mathbbc1%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    1300-talet

                    1300-talet

                    Display a custom attribute below product name in the front-end Magento 1.9.3.8